Worksheet for calculating area and perimeter of rectangles with mixed units and fractions.

To solve the problem, we need to calculate the area and perimeter of each rectangle. The formulas for these are:

- Area of a rectangle: \( \text{Area} = \text{length} \times \text{width} \)
- Perimeter of a rectangle: \( \text{Perimeter} = 2 \times (\text{length} + \text{width}) \)

Let's solve each rectangle step by step.

---

Rectangle 1

- Dimensions: Length = 6 cm, Width = 1½ cm = 1.5 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 6 \times 1.5 = 9 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (6 + 1.5) = 2 \times 7.5 = 15 \, \text{cm}
\]

Answers for Rectangle 1:
- Area = 9 cm²
- Perimeter = 15 cm

---

Rectangle 2

- Dimensions: Length = 5½ m = 5.5 m, Width = 3 m
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 5.5 \times 3 = 16.5 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (5.5 + 3) = 2 \times 8.5 = 17 \, \text{m}
\]

Answers for Rectangle 2:
- Area = 16.5 m²
- Perimeter = 17 m

---

Rectangle 3

- Dimensions: Length = 5 ft, Width = 2½ ft = 2.5 ft
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 5 \times 2.5 = 12.5 \, \text{ft}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (5 + 2.5) = 2 \times 7.5 = 15 \, \text{ft}
\]

Answers for Rectangle 3:
- Area = 12.5 ft²
- Perimeter = 15 ft

---

Rectangle 4

- Dimensions: Length = 20 cm, Width = 7 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 20 \times 7 = 140 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (20 + 7) = 2 \times 27 = 54 \, \text{cm}
\]

Answers for Rectangle 4:
- Area = 140 cm²
- Perimeter = 54 cm

---

Rectangle 5

- Dimensions: Length = 8 cm, Width = 3½ cm = 3.5 cm
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 8 \times 3.5 = 28 \, \text{cm}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (8 + 3.5) = 2 \times 11.5 = 23 \, \text{cm}
\]

Answers for Rectangle 5:
- Area = 28 cm²
- Perimeter = 23 cm

---

Rectangle 6

- Dimensions: Length = 30 m, Width = 20 m
- Area:
\[
\text{Area} = \text{length} \times \text{width} = 30 \times 20 = 600 \, \text{m}^2
\]
- Perimeter:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width}) = 2 \times (30 + 20) = 2 \times 50 = 100 \, \text{m}
\]

Answers for Rectangle 6:
- Area = 600 m²
- Perimeter = 100 m

---

Final Answers

1. Area = 9 cm², Perimeter = 15 cm
2. Area = 16.5 m², Perimeter = 17 m
3. Area = 12.5 ft², Perimeter = 15 ft
4. Area = 140 cm², Perimeter = 54 cm
5. Area = 28 cm², Perimeter = 23 cm
6. Area = 600 m², Perimeter = 100 m

\boxed{
\begin{array}{ll}
1. & \text{Area} = 9 \, \text{cm}^2, \, \text{Perimeter} = 15 \, \text{cm} \\
2. & \text{Area} = 16.5 \, \text{m}^2, \, \text{Perimeter} = 17 \, \text{m} \\
3. & \text{Area} = 12.5 \, \text{ft}^2, \, \text{Perimeter} = 15 \, \text{ft} \\
4. & \text{Area} = 140 \, \text{cm}^2, \, \text{Perimeter} = 54 \, \text{cm} \\
5. & \text{Area} = 28 \, \text{cm}^2, \, \text{Perimeter} = 23 \, \text{cm} \\
6. & \text{Area} = 600 \, \text{m}^2, \, \text{Perimeter} = 100 \, \text{m} \\
\end{array}
}