Division Models Worksheets | Area Model, Bar Model, Array - Free Printable

I'll solve this division problem using the area model method as shown in the worksheet.

First, let me look closely at what's being asked. The worksheet shows 6 division problems that need to be solved using the area model method. Each problem has a dividend and divisor, and I need to find the quotient.

Let me solve each problem one by one:

1. 517 ÷ 7
2. 483 ÷ 4
3. 764 ÷ 3
4. 251 ÷ 6
5. 329 ÷ 5
6. 965 ÷ 2

I'll start with the first problem: 517 ÷ 7.

To solve 517 ÷ 7 using the area model:
- I can think of this as finding how many groups of 7 are in 517.
- I can break 517 into parts that are easier to divide by 7.
- 7 × 70 = 490 (this is close to 517)
- 517 - 490 = 27
- 7 × 3 = 21 (this is the largest multiple of 7 that fits in 27)
- 27 - 21 = 6 (remainder)
- So, 70 + 3 = 73 with a remainder of 6
- Therefore, 517 ÷ 7 = 73 R6

Let me continue with the rest:

2. 483 ÷ 4
- 4 × 100 = 400
- 483 - 400 = 83
- 4 × 20 = 80
- 83 - 80 = 3 (remainder)
- So, 100 + 20 = 120 with a remainder of 3
- Therefore, 483 ÷ 4 = 120 R3

3. 764 ÷ 3
- 3 × 200 = 600
- 764 - 600 = 164
- 3 × 50 = 150
- 164 - 150 = 14
- 3 × 4 = 12
- 14 - 12 = 2 (remainder)
- So, 200 + 50 + 4 = 254 with a remainder of 2
- Therefore, 764 ÷ 3 = 254 R2

4. 251 ÷ 6
- 6 × 40 = 240
- 251 - 240 = 11
- 6 × 1 = 6
- 11 - 6 = 5 (remainder)
- So, 40 + 1 = 41 with a remainder of 5
- Therefore, 251 ÷ 6 = 41 R5

5. 329 ÷ 5
- 5 × 60 = 300
- 329 - 300 = 29
- 5 × 5 = 25
- 29 - 25 = 4 (remainder)
- So, 60 + 5 = 65 with a remainder of 4
- Therefore, 329 ÷ 5 = 65 R4

6. 965 ÷ 2
- 2 × 400 = 800
- 965 - 800 = 165
- 2 × 80 = 160
- 165 - 160 = 5
- 2 × 2 = 4
- 5 - 4 = 1 (remainder)
- So, 400 + 80 + 2 = 482 with a remainder of 1
- Therefore, 965 ÷ 2 = 482 R1

The solutions to the problems are:
1. 517 ÷ 7 = 73 R6
2. 483 ÷ 4 = 120 R3
3. 764 ÷ 3 = 254 R2
4. 251 ÷ 6 = 41 R5
5. 329 ÷ 5 = 65 R4
6. 965 ÷ 2 = 482 R1