To solve the problem of finding the area for each shape, we will break down each figure into simpler geometric shapes (rectangles) and calculate their areas individually. Then, we will sum up the areas to get the total area for each figure.
---
Problem 1:
The given shape can be divided into two rectangles:
1. A rectangle with dimensions \(8 \, \text{m} \times 8 \, \text{m}\).
2. A rectangle with dimensions \(3 \, \text{m} \times 12 \, \text{m}\).
#### Step 1: Calculate the area of the first rectangle.
\[
\text{Area}_1 = 8 \, \text{m} \times 8 \, \text{m} = 64 \, \text{m}^2
\]
#### Step 2: Calculate the area of the second rectangle.
\[
\text{Area}_2 = 3 \, \text{m} \times 12 \, \text{m} = 36 \, \text{m}^2
\]
#### Step 3: Sum the areas of the two rectangles.
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 64 \, \text{m}^2 + 36 \, \text{m}^2 = 100 \, \text{m}^2
\]
Answer for Problem 1:
\[
\boxed{100}
\]
---
Problem 2:
The given shape can be divided into two rectangles:
1. A rectangle with dimensions \(20 \, \text{cm} \times 18 \, \text{cm}\).
2. A smaller rectangle with dimensions \(5 \, \text{cm} \times 10 \, \text{cm}\).
#### Step 1: Calculate the area of the first rectangle.
\[
\text{Area}_1 = 20 \, \text{cm} \times 18 \, \text{cm} = 360 \, \text{cm}^2
\]
#### Step 2: Calculate the area of the second rectangle.
\[
\text{Area}_2 = 5 \, \text{cm} \times 10 \, \text{cm} = 50 \, \text{cm}^2
\]
#### Step 3: Subtract the area of the smaller rectangle from the area of the larger rectangle.
\[
\text{Total Area} = \text{Area}_1 - \text{Area}_2 = 360 \, \text{cm}^2 - 50 \, \text{cm}^2 = 310 \, \text{cm}^2
\]
Answer for Problem 2:
\[
\boxed{310}
\]
---
Problem 3:
The given shape can be divided into three rectangles:
1. A large rectangle with dimensions \(10 \, \text{m} \times 14 \, \text{m}\).
2. A smaller rectangle with dimensions \(5 \, \text{m} \times 5 \, \text{m}\).
3. Another smaller rectangle with dimensions \(4 \, \text{m} \times 5 \, \text{m}\).
#### Step 1: Calculate the area of the large rectangle.
\[
\text{Area}_1 = 10 \, \text{m} \times 14 \, \text{m} = 140 \, \text{m}^2
\]
#### Step 2: Calculate the area of the first smaller rectangle.
\[
\text{Area}_2 = 5 \, \text{m} \times 5 \, \text{m} = 25 \, \text{m}^2
\]
#### Step 3: Calculate the area of the second smaller rectangle.
\[
\text{Area}_3 = 4 \, \text{m} \times 5 \, \text{m} = 20 \, \text{m}^2
\]
#### Step 4: Subtract the areas of the two smaller rectangles from the area of the large rectangle.
\[
\text{Total Area} = \text{Area}_1 - (\text{Area}_2 + \text{Area}_3) = 140 \, \text{m}^2 - (25 \, \text{m}^2 + 20 \, \text{m}^2) = 140 \, \text{m}^2 - 45 \, \text{m}^2 = 95 \, \text{m}^2
\]
Answer for Problem 3:
\[
\boxed{95}
\]
---
Final Answers:
1. \(\boxed{100}\)
2. \(\boxed{310}\)
3. \(\boxed{95}\)
Parent Tip: Review the logic above to help your child master the concept of area of composite figures worksheet 6th grade.
