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Area of Compound Shapes (Composite Shapes) Worksheets - Free Printable

Area of Compound Shapes (Composite Shapes) Worksheets

Educational worksheet: Area of Compound Shapes (Composite Shapes) Worksheets. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Area of Compound Shapes (Composite Shapes) Worksheets
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Let’s solve each compound shape one by one. We’ll break them into simpler shapes (like rectangles, triangles, semicircles), find their areas, and add or subtract as needed.

We’re told to use π = 3.14 and round answers to 2 decimal places if required.

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Shape 1:

This is a rectangle with a triangle on top and a triangle cut out from the bottom.

- Rectangle: width = 6 cm, height = 8 cm → Area = 6 × 8 = 48 cm²
- Top triangle: base = 6 cm, height = 5 cm → Area = (1/2) × 6 × 5 = 15 cm²
- Bottom triangle (cut out): base = 6 cm, height = 4 cm → Area = (1/2) × 6 × 4 = 12 cm²

Total area = rectangle + top triangle – bottom triangle
= 48 + 15 – 12 = 51.00 cm²

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Shape 2:

This looks like a trapezoid plus a rectangle on top? Wait — actually, it’s a large trapezoid with a small rectangle missing from the top right? Let me re-express:

Actually, better way: It’s a big trapezoid minus a small rectangle? Or maybe split into parts.

Looking again: The full shape can be seen as:

- A rectangle at the bottom: 10 m wide × 4 m high → Area = 10 × 4 = 40 m²
- A triangle on the left side: base = 6 m (since total height is 10 m, and rectangle is 4 m, so triangle height = 6 m), and base of triangle is 10 - 4 = 6 m? Wait, let's label properly.

Wait — dimensions given:

Left vertical side: 10 m
Bottom horizontal: 10 m
Top right has a step: 4 m up, then 4 m right? Actually, looking at the diagram description:

It says: left side 10 m, bottom 10 m, then there’s a part that goes up 4 m and right 4 m? Hmm.

Alternative approach: Think of it as a trapezoid with parallel sides 10 m and 4 m, height 10 m? No.

Wait — perhaps it’s composed of:

- A rectangle 4 m × 4 m on top right? But that doesn’t fit.

Better: Split vertically.

From left to right:

At x=0 to x=6: height is 10 m → rectangle 6×10 = 60? But no, because after x=6, it drops.

Actually, standard way for this shape:

It’s a trapezoid with bases 10 m and 4 m, and height 10 m? But the non-parallel sides are slanted.

Wait — look at coordinates mentally:

Start at bottom-left (0,0), go right 10 m to (10,0), up 4 m to (10,4), left 4 m to (6,4), up 6 m to (6,10), left 6 m to (0,10), down 10 m to (0,0). That makes sense.

So we can split into:

- Rectangle from x=0 to x=6, y=0 to y=10 → 6×10 = 60 m²
- Rectangle from x=6 to x=10, y=0 to y=4 → 4×4 = 16 m²

But wait — that would be overlapping? No, actually, from x=6 to x=10, only up to y=4, and from x=0 to x=6, up to y=10. So yes, two rectangles.

Total area = 6×10 + 4×4 = 60 + 16 = 76.00 m²

Alternatively, you could see it as a big rectangle 10×10 = 100, minus a rectangle 4×6 = 24 (the missing part on top right), so 100 - 24 = 76. Same answer.

Good.

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Shape 3:

This is a rectangle with a triangle attached on the right.

Rectangle: 9 cm × 6 cm → Area = 54 cm²

Triangle: base = 6 cm (same as rectangle height), height = 4 cm → Area = (1/2) × 6 × 4 = 12 cm²

Total area = 54 + 12 = 66.00 cm²

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Shape 4:

This is a parallelogram with a semicircle attached on the right.

Parallelogram: base = 12 m, height = 6 m → Area = base × height = 12 × 6 = 72 m²

Semicircle: diameter = 6 m → radius = 3 m
Area of circle = πr² = 3.14 × 3² = 3.14 × 9 = 28.26
Semicircle = half of that = 14.13 m²

Total area = 72 + 14.13 = 86.13 m²

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Shape 5:

This is a rectangle with a semicircle on top.

Rectangle: 12 ft × 6 ft → Area = 72 ft²

Semicircle: diameter = 12 ft → radius = 6 ft
Area of circle = 3.14 × 6² = 3.14 × 36 = 113.04
Semicircle = 56.52 ft²

Total area = 72 + 56.52 = 128.52 ft²

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Shape 6:

This is a square with four triangles cut out from the corners? Or rather, it’s a star-like shape made by cutting triangles from a square.

Actually, looking at dimensions: outer square is 10 in × 10 in? But the inner shape is formed by connecting midpoints? Wait.

Dimensions given: from center to corner is 5 in? And the “arms” extend 5 in.

Actually, this shape is a square rotated 45 degrees inside another square? Or it’s an octagon? No.

Standard interpretation: This is a square with side length 10 in, but with four right triangles cut off from the corners. Each triangle has legs of 5 in.

Wait — the diagram shows: from each corner, a line goes inward 5 in along both axes, forming a smaller square in the middle? Actually, no.

Another way: The shape is composed of a central square and four triangles? Or it’s a single polygon.

Actually, common problem: This is a square of side 10 in, and from each corner, a right triangle with legs 5 in is removed.

So original square area = 10 × 10 = 100 in²

Each triangle: (1/2) × 5 × 5 = 12.5 in²

Four triangles: 4 × 12.5 = 50 in²

Remaining area = 100 - 50 = 50.00 in²

Yes, that matches typical problems.

Alternatively, the remaining shape is a square rotated 45 degrees with diagonal 10 in? Then side = 10/√2, area = (10/√2)^2 = 100/2 = 50. Same.

Perfect.

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Now, compiling all answers:

1. 51.00 cm²
2. 76.00 m²
3. 66.00 cm²
4. 86.13 m²
5. 128.52 ft²
6. 50.00 in²

All rounded to 2 decimal places where needed.

Final Answer:
1. 51.00
2. 76.00
3. 66.00
4. 86.13
5. 128.52
6. 50.00
Parent Tip: Review the logic above to help your child master the concept of area of compound shapes worksheet.
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