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Answer key showing formulas and solutions for finding perimeter and area of parallelograms, triangles, and trapezoids.

Answer key for perimeter and area of parallelograms, triangles, and trapezoids with geometric figures and calculations.

Answer key for perimeter and area of parallelograms, triangles, and trapezoids with geometric figures and calculations.

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Show Answer Key & Explanations Step-by-step solution for: FREE Perimeter and Area of Parallelograms, Triangles, and Trapezoids
The image you provided contains a worksheet with problems related to the perimeter and area of parallelograms, triangles, trapezoids, and other geometric shapes. Below, I will explain the solutions for each problem step by step.

---

Problem 1:


Shape: Parallelogram
Given: Base = 7 cm, Height = 8 cm
Task: Find the perimeter and area.

#### Solution:
1. Perimeter of a Parallelogram:
- Formula: \( P = 2 \times (\text{Base} + \text{Side}) \)
- Here, the base is 7 cm, but the side length is not given. Assuming the side is also 7 cm (as it is a square-like figure in the diagram):
\[
P = 2 \times (7 + 7) = 2 \times 14 = 28 \, \text{cm}
\]

2. Area of a Parallelogram:
- Formula: \( A = \text{Base} \times \text{Height} \)
- Given: Base = 7 cm, Height = 8 cm
\[
A = 7 \times 8 = 56 \, \text{cm}^2
\]

Answer:
\[
P = 28 \, \text{cm}, \quad A = 56 \, \text{cm}^2
\]

---

Problem 2:


Shape: Triangle
Given: Base = 3.2 ft, Height = 2.9 ft
Task: Find the area.

#### Solution:
1. Area of a Triangle:
- Formula: \( A = \frac{1}{2} \times \text{Base} \times \text{Height} \)
- Given: Base = 3.2 ft, Height = 2.9 ft
\[
A = \frac{1}{2} \times 3.2 \times 2.9 = \frac{1}{2} \times 9.28 = 4.64 \, \text{ft}^2
\]

Answer:
\[
A = 4.64 \, \text{ft}^2
\]

---

Problem 3:


Shape: Trapezoid
Given: Bases = 1.2 m and 3.0 m, Height = 1.5 m
Task: Find the area.

#### Solution:
1. Area of a Trapezoid:
- Formula: \( A = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \)
- Given: Base₁ = 1.2 m, Base₂ = 3.0 m, Height = 1.5 m
\[
A = \frac{1}{2} \times (1.2 + 3.0) \times 1.5 = \frac{1}{2} \times 4.2 \times 1.5 = \frac{1}{2} \times 6.3 = 3.15 \, \text{m}^2
\]

Answer:
\[
A = 3.15 \, \text{m}^2
\]

---

Problem 4:


Shape: Rectangle
Given: Length = 13 mm, Width = 24 mm
Task: Find the perimeter and area.

#### Solution:
1. Perimeter of a Rectangle:
- Formula: \( P = 2 \times (\text{Length} + \text{Width}) \)
- Given: Length = 13 mm, Width = 24 mm
\[
P = 2 \times (13 + 24) = 2 \times 37 = 74 \, \text{mm}
\]

2. Area of a Rectangle:
- Formula: \( A = \text{Length} \times \text{Width} \)
- Given: Length = 13 mm, Width = 24 mm
\[
A = 13 \times 24 = 312 \, \text{mm}^2
\]

Answer:
\[
P = 74 \, \text{mm}, \quad A = 312 \, \text{mm}^2
\]

---

Problem 5:


Shape: Trapezoid
Given: Bases = 10 cm and 30 cm, Height = 12 cm
Task: Find the area.

#### Solution:
1. Area of a Trapezoid:
- Formula: \( A = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \)
- Given: Base₁ = 10 cm, Base₂ = 30 cm, Height = 12 cm
\[
A = \frac{1}{2} \times (10 + 30) \times 12 = \frac{1}{2} \times 40 \times 12 = \frac{1}{2} \times 480 = 240 \, \text{cm}^2
\]

Answer:
\[
A = 240 \, \text{cm}^2
\]

---

Problem 6:


Shape: Triangle
Given: Base = 7.5 cm, Height = 6.7 cm
Task: Find the area.

#### Solution:
1. Area of a Triangle:
- Formula: \( A = \frac{1}{2} \times \text{Base} \times \text{Height} \)
- Given: Base = 7.5 cm, Height = 6.7 cm
\[
A = \frac{1}{2} \times 7.5 \times 6.7 = \frac{1}{2} \times 50.25 = 25.125 \, \text{cm}^2
\]

Answer:
\[
A = 25.125 \, \text{cm}^2
\]

---

Problem 7:


Shape: Trapezoid
Given: Bases = 12 cm and 18 cm, Height = 5 cm
Task: Find the area.

#### Solution:
1. Area of a Trapezoid:
- Formula: \( A = \frac{1}{2} \times (\text{Base}_1 + \text{Base}_2) \times \text{Height} \)
- Given: Base₁ = 12 cm, Base₂ = 18 cm, Height = 5 cm
\[
A = \frac{1}{2} \times (12 + 18) \times 5 = \frac{1}{2} \times 30 \times 5 = \frac{1}{2} \times 150 = 75 \, \text{cm}^2
\]

Answer:
\[
A = 75 \, \text{cm}^2
\]

---

Problem 8:


Shape: Triangle
Given: Base = 9 m, Height = 10 m
Task: Find the area.

#### Solution:
1. Area of a Triangle:
- Formula: \( A = \frac{1}{2} \times \text{Base} \times \text{Height} \)
- Given: Base = 9 m, Height = 10 m
\[
A = \frac{1}{2} \times 9 \times 10 = \frac{1}{2} \times 90 = 45 \, \text{m}^2
\]

Answer:
\[
A = 45 \, \text{m}^2
\]

---

Final Answer:


\[
\boxed{
\begin{aligned}
1. & \, P = 28 \, \text{cm}, \, A = 56 \, \text{cm}^2 \\
2. & \, A = 4.64 \, \text{ft}^2 \\
3. & \, A = 3.15 \, \text{m}^2 \\
4. & \, P = 74 \, \text{mm}, \, A = 312 \, \text{mm}^2 \\
5. & \, A = 240 \, \text{cm}^2 \\
6. & \, A = 25.125 \, \text{cm}^2 \\
7. & \, A = 75 \, \text{cm}^2 \\
8. & \, A = 45 \, \text{m}^2 \\
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of area of triangles and trapezoids worksheet.
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