49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable
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Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
To solve the problem of balancing chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for each problem:
---
- Balance sodium (Na): There are 2 Na atoms on the right and 1 on the left, so multiply Na by 2.
- Balance oxygen (O): There are 2 O atoms on the left and 1 on the right, so multiply Na₂O by 2.
Balanced Equation:
$$ \boxed{4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O}} $$
---
- Balance phosphorus (P): There are 2 P atoms on the right and 1 on the left, so multiply P by 2.
- Balance oxygen (O): There are 3 O atoms on the right and 2 on the left, so multiply O₂ by 3/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{4\text{P} + 3\text{O}_2 \rightarrow 2\text{P}_2\text{O}_3} $$
---
- Balance antimony (Sb): There are 2 Sb atoms on the left and 1 on the right, so multiply SbCl₃ by 2.
- Balance sulfur (S): There are 3 S atoms on the left and 1 on the right, so multiply H₂S by 3.
- Balance chlorine (Cl): There are 6 Cl atoms on the right and 1 on the left, so multiply HCl by 6.
- Balance hydrogen (H): There are 6 H atoms on the right and 6 on the left (already balanced).
Balanced Equation:
$$ \boxed{\text{Sb}_2\text{S}_3 + 6\text{HCl} \rightarrow 2\text{SbCl}_3 + 3\text{H}_2\text{S}} $$
---
- Balance nitrogen (N): There are 2 N atoms on the right and 1 on the left, so multiply NH₃ by 2.
- Balance hydrogen (H): There are 10 H atoms on the right and 8 on the left, so multiply H₂SO₄ by 1 (already balanced).
- Balance sulfur (S): There is 1 S atom on both sides.
- Balance oxygen (O): There are 4 O atoms on both sides.
Balanced Equation:
$$ \boxed{2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4} $$
---
- Balance copper (Cu): There is 1 Cu atom on both sides.
- Balance oxygen (O): There is 1 O atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on the right and 1 on the left, so multiply HCl by 2.
- Balance hydrogen (H): There are 2 H atoms on both sides.
Balanced Equation:
$$ \boxed{\text{CuO} + 2\text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{O}} $$
---
- Balance silver (Ag): There are 2 Ag atoms on the right and 1 on the left, so multiply AgNO₃ by 2.
- Balance sulfur (S): There is 1 S atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
- Balance hydrogen (H): There are 2 H atoms on both sides.
Balanced Equation:
$$ \boxed{2\text{AgNO}_3 + \text{H}_2\text{S} \rightarrow \text{Ag}_2\text{S} + 2\text{HNO}_3} $$
---
- Balance copper (Cu): There are 2 Cu atoms on the right and 1 on the left, so multiply Cu by 2.
- Balance sulfur (S): There is 1 S atom on both sides.
Balanced Equation:
$$ \boxed{2\text{Cu} + \text{S} \rightarrow \text{Cu}_2\text{S}} $$
---
- Balance aluminum (Al): There is 1 Al atom on both sides.
- Balance phosphorus (P): There is 1 P atom on both sides.
- Balance oxygen (O): There are 4 O atoms on both sides.
- Balance hydrogen (H): There are 3 H atoms on the left and 2 on the right, so multiply H₂ by 3/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{2\text{Al} + 2\text{H}_3\text{PO}_4 \rightarrow 3\text{H}_2 + 2\text{AlPO}_4} $$
---
- Balance sodium (Na): There is 1 Na atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 3 O atoms on the left and 4 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{NaNO}_3 \rightarrow 2\text{NaNO}_2 + \text{O}_2} $$
---
- Balance magnesium (Mg): There is 1 Mg atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance oxygen (O): There are 6 O atoms on the left and 2 on the right, so multiply O₂ by 3.
Balanced Equation:
$$ \boxed{\text{Mg(ClO}_3)_2 \rightarrow \text{MgCl}_2 + 3\text{O}_2} $$
---
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance oxygen (O): There are 2 O atoms on the left and 3 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2} $$
---
- Balance barium (Ba): There is 1 Ba atom on both sides.
- Balance oxygen (O): There are 2 O atoms on the left and 3 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{BaO}_2 \rightarrow 2\text{BaO} + \text{O}_2} $$
---
- Balance lead (Pb): There is 1 Pb atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 6 O atoms on both sides.
- Balance potassium (K): There is 1 K atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
Balanced Equation:
$$ \boxed{\text{Pb(NO}_3)_2 + 2\text{KCl} \rightarrow \text{PbCl}_2 + 2\text{KNO}_3} $$
---
- Balance phosphorus (P): There are 2 P atoms on the right and 1 on the left, so multiply P by 2.
- Balance oxygen (O): There are 5 O atoms on the right and 2 on the left, so multiply O₂ by 5/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{4\text{P} + 5\text{O}_2 \rightarrow 2\text{P}_2\text{O}_5} $$
---
- Balance nitrogen (N): There are 2 N atoms on both sides.
- Balance hydrogen (H): There are 4 H atoms on the left and 2 on the right, so multiply H₂O by 2.
- Balance oxygen (O): There are 2 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O}} $$
---
- Balance nitrogen (N): There are 2 N atoms on the left and 1 on the right, so multiply NH₃ by 2.
- Balance hydrogen (H): There are 6 H atoms on the right and 2 on the left, so multiply H₂ by 3.
Balanced Equation:
$$ \boxed{3\text{H}_2 + \text{N}_2 \rightarrow 2\text{NH}_3} $$
---
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance potassium (K): There is 1 K atom on both sides.
- Balance bromine (Br): There are 2 Br atoms on both sides.
Balanced Equation:
$$ \boxed{\text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2} $$
---
- Balance barium (Ba): There is 1 Ba atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance nitrogen (N): There are 2 N atoms on both sides.
- Balance hydrogen (H): There are 8 H atoms on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{BaCl}_2 + (\text{NH}_4)_2\text{CO}_3 \rightarrow \text{BaCO}_3 + 2\text{NH}_4\text{Cl}} $$
---
- Balance magnesium (Mg): There is 1 Mg atom on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on the left and 3 on the right.
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
Balanced Equation:
$$ \boxed{\text{MgCO}_3 + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{CO}_2 + \text{H}_2\text{O}} $$
---
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{H}_2\text{CO}_3 \rightarrow \text{H}_2\text{O} + \text{CO}_2} $$
---
$$
\boxed{
\begin{aligned}
1) & \quad 4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O} \\
2) & \quad 4\text{P} + 3\text{O}_2 \rightarrow 2\text{P}_2\text{O}_3 \\
3) & \quad \text{Sb}_2\text{S}_3 + 6\text{HCl} \rightarrow 2\text{SbCl}_3 + 3\text{H}_2\text{S} \\
4) & \quad 2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \\
5) & \quad \text{CuO} + 2\text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{O} \\
6) & \quad 2\text{AgNO}_3 + \text{H}_2\text{S} \rightarrow \text{Ag}_2\text{S} + 2\text{HNO}_3 \\
7) & \quad 2\text{Cu} + \text{S} \rightarrow \text{Cu}_2\text{S} \\
8) & \quad 2\text{Al} + 2\text{H}_3\text{PO}_4 \rightarrow 3\text{H}_2 + 2\text{AlPO}_4 \\
9) & \quad 2\text{NaNO}_3 \rightarrow 2\text{NaNO}_2 + \text{O}_2 \\
10) & \quad \text{Mg(ClO}_3)_2 \rightarrow \text{MgCl}_2 + 3\text{O}_2 \\
11) & \quad 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \\
12) & \quad 2\text{BaO}_2 \rightarrow 2\text{BaO} + \text{O}_2 \\
13) & \quad \text{Pb(NO}_3)_2 + 2\text{KCl} \rightarrow \text{PbCl}_2 + 2\text{KNO}_3 \\
14) & \quad 4\text{P} + 5\text{O}_2 \rightarrow 2\text{P}_2\text{O}_5 \\
15) & \quad \text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O} \\
16) & \quad 3\text{H}_2 + \text{N}_2 \rightarrow 2\text{NH}_3 \\
17) & \quad \text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2 \\
18) & \quad \text{BaCl}_2 + (\text{NH}_4)_2\text{CO}_3 \rightarrow \text{BaCO}_3 + 2\text{NH}_4\text{Cl} \\
19) & \quad \text{MgCO}_3 + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \\
20) & \quad \text{H}_2\text{CO}_3 \rightarrow \text{H}_2\text{O} + \text{CO}_2 \\
\end{aligned}
}
$$
---
1) Na + O₂ → Na₂O
- Balance sodium (Na): There are 2 Na atoms on the right and 1 on the left, so multiply Na by 2.
- Balance oxygen (O): There are 2 O atoms on the left and 1 on the right, so multiply Na₂O by 2.
Balanced Equation:
$$ \boxed{4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O}} $$
---
2) P + O₂ → P₂O₃
- Balance phosphorus (P): There are 2 P atoms on the right and 1 on the left, so multiply P by 2.
- Balance oxygen (O): There are 3 O atoms on the right and 2 on the left, so multiply O₂ by 3/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{4\text{P} + 3\text{O}_2 \rightarrow 2\text{P}_2\text{O}_3} $$
---
3) Sb₂S₃ + HCl → SbCl₃ + H₂S
- Balance antimony (Sb): There are 2 Sb atoms on the left and 1 on the right, so multiply SbCl₃ by 2.
- Balance sulfur (S): There are 3 S atoms on the left and 1 on the right, so multiply H₂S by 3.
- Balance chlorine (Cl): There are 6 Cl atoms on the right and 1 on the left, so multiply HCl by 6.
- Balance hydrogen (H): There are 6 H atoms on the right and 6 on the left (already balanced).
Balanced Equation:
$$ \boxed{\text{Sb}_2\text{S}_3 + 6\text{HCl} \rightarrow 2\text{SbCl}_3 + 3\text{H}_2\text{S}} $$
---
4) NH₃ + H₂SO₄ → (NH₄)₂SO₄
- Balance nitrogen (N): There are 2 N atoms on the right and 1 on the left, so multiply NH₃ by 2.
- Balance hydrogen (H): There are 10 H atoms on the right and 8 on the left, so multiply H₂SO₄ by 1 (already balanced).
- Balance sulfur (S): There is 1 S atom on both sides.
- Balance oxygen (O): There are 4 O atoms on both sides.
Balanced Equation:
$$ \boxed{2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4} $$
---
5) CuO + HCl → CuCl₂ + H₂O
- Balance copper (Cu): There is 1 Cu atom on both sides.
- Balance oxygen (O): There is 1 O atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on the right and 1 on the left, so multiply HCl by 2.
- Balance hydrogen (H): There are 2 H atoms on both sides.
Balanced Equation:
$$ \boxed{\text{CuO} + 2\text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{O}} $$
---
6) AgNO₃ + H₂S → Ag₂S + HNO₃
- Balance silver (Ag): There are 2 Ag atoms on the right and 1 on the left, so multiply AgNO₃ by 2.
- Balance sulfur (S): There is 1 S atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
- Balance hydrogen (H): There are 2 H atoms on both sides.
Balanced Equation:
$$ \boxed{2\text{AgNO}_3 + \text{H}_2\text{S} \rightarrow \text{Ag}_2\text{S} + 2\text{HNO}_3} $$
---
7) Cu + S → Cu₂S
- Balance copper (Cu): There are 2 Cu atoms on the right and 1 on the left, so multiply Cu by 2.
- Balance sulfur (S): There is 1 S atom on both sides.
Balanced Equation:
$$ \boxed{2\text{Cu} + \text{S} \rightarrow \text{Cu}_2\text{S}} $$
---
8) Al + H₃PO₄ → H₂ + AlPO₄
- Balance aluminum (Al): There is 1 Al atom on both sides.
- Balance phosphorus (P): There is 1 P atom on both sides.
- Balance oxygen (O): There are 4 O atoms on both sides.
- Balance hydrogen (H): There are 3 H atoms on the left and 2 on the right, so multiply H₂ by 3/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{2\text{Al} + 2\text{H}_3\text{PO}_4 \rightarrow 3\text{H}_2 + 2\text{AlPO}_4} $$
---
9) NaNO₃ → NaNO₂ + O₂
- Balance sodium (Na): There is 1 Na atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 3 O atoms on the left and 4 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{NaNO}_3 \rightarrow 2\text{NaNO}_2 + \text{O}_2} $$
---
10) Mg(ClO₃)₂ → MgCl₂ + O₂
- Balance magnesium (Mg): There is 1 Mg atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance oxygen (O): There are 6 O atoms on the left and 2 on the right, so multiply O₂ by 3.
Balanced Equation:
$$ \boxed{\text{Mg(ClO}_3)_2 \rightarrow \text{MgCl}_2 + 3\text{O}_2} $$
---
11) H₂O₂ → H₂O + O₂
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance oxygen (O): There are 2 O atoms on the left and 3 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2} $$
---
12) BaO₂ → BaO + O₂
- Balance barium (Ba): There is 1 Ba atom on both sides.
- Balance oxygen (O): There are 2 O atoms on the left and 3 on the right, so adjust the coefficients.
Balanced Equation:
$$ \boxed{2\text{BaO}_2 \rightarrow 2\text{BaO} + \text{O}_2} $$
---
13) Pb(NO₃)₂ + KCl → PbCl₂ + KNO₃
- Balance lead (Pb): There is 1 Pb atom on both sides.
- Balance nitrogen (N): There is 1 N atom on both sides.
- Balance oxygen (O): There are 6 O atoms on both sides.
- Balance potassium (K): There is 1 K atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
Balanced Equation:
$$ \boxed{\text{Pb(NO}_3)_2 + 2\text{KCl} \rightarrow \text{PbCl}_2 + 2\text{KNO}_3} $$
---
14) P + O₂ → P₂O₅
- Balance phosphorus (P): There are 2 P atoms on the right and 1 on the left, so multiply P by 2.
- Balance oxygen (O): There are 5 O atoms on the right and 2 on the left, so multiply O₂ by 5/2 or adjust to whole numbers.
Balanced Equation:
$$ \boxed{4\text{P} + 5\text{O}_2 \rightarrow 2\text{P}_2\text{O}_5} $$
---
15) NH₄NO₂ → N₂ + H₂O
- Balance nitrogen (N): There are 2 N atoms on both sides.
- Balance hydrogen (H): There are 4 H atoms on the left and 2 on the right, so multiply H₂O by 2.
- Balance oxygen (O): There are 2 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O}} $$
---
16) H₂ + N₂ → NH₃
- Balance nitrogen (N): There are 2 N atoms on the left and 1 on the right, so multiply NH₃ by 2.
- Balance hydrogen (H): There are 6 H atoms on the right and 2 on the left, so multiply H₂ by 3.
Balanced Equation:
$$ \boxed{3\text{H}_2 + \text{N}_2 \rightarrow 2\text{NH}_3} $$
---
17) Cl₂ + KBr → KCl + Br₂
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance potassium (K): There is 1 K atom on both sides.
- Balance bromine (Br): There are 2 Br atoms on both sides.
Balanced Equation:
$$ \boxed{\text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2} $$
---
18) BaCl₂ + (NH₄)₂CO₃ → BaCO₃ + NH₄Cl
- Balance barium (Ba): There is 1 Ba atom on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
- Balance nitrogen (N): There are 2 N atoms on both sides.
- Balance hydrogen (H): There are 8 H atoms on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{BaCl}_2 + (\text{NH}_4)_2\text{CO}_3 \rightarrow \text{BaCO}_3 + 2\text{NH}_4\text{Cl}} $$
---
19) MgCO₃ + HCl → MgCl₂ + CO₂ + H₂O
- Balance magnesium (Mg): There is 1 Mg atom on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on the left and 3 on the right.
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance chlorine (Cl): There are 2 Cl atoms on both sides.
Balanced Equation:
$$ \boxed{\text{MgCO}_3 + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{CO}_2 + \text{H}_2\text{O}} $$
---
20) H₂CO₃ → H₂O + CO₂
- Balance hydrogen (H): There are 2 H atoms on both sides.
- Balance carbon (C): There is 1 C atom on both sides.
- Balance oxygen (O): There are 3 O atoms on both sides.
Balanced Equation:
$$ \boxed{\text{H}_2\text{CO}_3 \rightarrow \text{H}_2\text{O} + \text{CO}_2} $$
---
Final Answer:
$$
\boxed{
\begin{aligned}
1) & \quad 4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O} \\
2) & \quad 4\text{P} + 3\text{O}_2 \rightarrow 2\text{P}_2\text{O}_3 \\
3) & \quad \text{Sb}_2\text{S}_3 + 6\text{HCl} \rightarrow 2\text{SbCl}_3 + 3\text{H}_2\text{S} \\
4) & \quad 2\text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow (\text{NH}_4)_2\text{SO}_4 \\
5) & \quad \text{CuO} + 2\text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{O} \\
6) & \quad 2\text{AgNO}_3 + \text{H}_2\text{S} \rightarrow \text{Ag}_2\text{S} + 2\text{HNO}_3 \\
7) & \quad 2\text{Cu} + \text{S} \rightarrow \text{Cu}_2\text{S} \\
8) & \quad 2\text{Al} + 2\text{H}_3\text{PO}_4 \rightarrow 3\text{H}_2 + 2\text{AlPO}_4 \\
9) & \quad 2\text{NaNO}_3 \rightarrow 2\text{NaNO}_2 + \text{O}_2 \\
10) & \quad \text{Mg(ClO}_3)_2 \rightarrow \text{MgCl}_2 + 3\text{O}_2 \\
11) & \quad 2\text{H}_2\text{O}_2 \rightarrow 2\text{H}_2\text{O} + \text{O}_2 \\
12) & \quad 2\text{BaO}_2 \rightarrow 2\text{BaO} + \text{O}_2 \\
13) & \quad \text{Pb(NO}_3)_2 + 2\text{KCl} \rightarrow \text{PbCl}_2 + 2\text{KNO}_3 \\
14) & \quad 4\text{P} + 5\text{O}_2 \rightarrow 2\text{P}_2\text{O}_5 \\
15) & \quad \text{NH}_4\text{NO}_2 \rightarrow \text{N}_2 + 2\text{H}_2\text{O} \\
16) & \quad 3\text{H}_2 + \text{N}_2 \rightarrow 2\text{NH}_3 \\
17) & \quad \text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2 \\
18) & \quad \text{BaCl}_2 + (\text{NH}_4)_2\text{CO}_3 \rightarrow \text{BaCO}_3 + 2\text{NH}_4\text{Cl} \\
19) & \quad \text{MgCO}_3 + 2\text{HCl} \rightarrow \text{MgCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \\
20) & \quad \text{H}_2\text{CO}_3 \rightarrow \text{H}_2\text{O} + \text{CO}_2 \\
\end{aligned}
}
$$
Parent Tip: Review the logic above to help your child master the concept of balancing equations worksheet grade 10.