Worksheet for practicing balancing chemical equations with 15 problems.
A worksheet titled "Balancing Chemical Equations" with 15 incomplete chemical reactions to be balanced, including spaces for coefficients and a header for name and date.
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Step-by-step solution for: Free Printable Balancing Equations Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Free Printable Balancing Equations Worksheets
Here are the balanced chemical equations for the problems listed. To balance them, we make sure the number of atoms for each element is the same on both the left (reactants) and right (products) sides.
1. CuO + H₂ → Cu + H₂O
* This one is already balanced. There is 1 Copper, 1 Oxygen, and 2 Hydrogens on both sides.
2. 2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
* *Note: The product was missing in the image, but Aluminum reacts with Sulfuric Acid to form Aluminum Sulfate.*
* We need 2 Aluminums, so we put a 2 in front of Al.
* We need 3 Sulfates (SO₄), so we put a 3 in front of H₂SO₄.
* This gives us 6 Hydrogens on the left, so we put a 3 in front of H₂ on the right.
3. MgBr₂ + Cl₂ → MgCl₂ + Br₂
* This is already balanced. 1 Magnesium, 2 Bromines, and 2 Chlorines on both sides.
4. SnO₂ + 2 C → Sn + 2 CO
* There are 2 Oxygens on the left. To get 2 Oxygens on the right, we put a 2 in front of CO.
* Now there are 2 Carbons on the right, so we put a 2 in front of C on the left.
5. Pb(NO₃)₂ + H₂S → PbS + 2 HNO₃
* There are 2 Nitrate groups (NO₃) on the left. We put a 2 in front of HNO₃ on the right to match.
* This gives us 2 Hydrogens on the right, which matches the H₂ on the left.
6. 2 HgO → 2 Hg + O₂
* There are 2 Oxygens on the right. We put a 2 in front of HgO on the left.
* Now there are 2 Mercuries (Hg) on the left, so we put a 2 in front of Hg on the right.
7. 2 KClO₃ → 2 KCl + 3 O₂
* We have 3 Oxygens on the left and 2 on the right. The common multiple is 6.
* Put a 2 in front of KClO₃ (making 6 Oxygens).
* Put a 3 in front of O₂ (making 6 Oxygens).
* Now balance Potassium (K) and Chlorine (Cl) by putting a 2 in front of KCl.
8. N₂ + 3 H₂ → 2 NH₃
* There are 2 Nitrogens on the left. Put a 2 in front of NH₃.
* Now there are 6 Hydrogens on the right ($2 \times 3$). Put a 3 in front of H₂ on the left.
9. 2 NaBr + Cl₂ → 2 NaCl + Br₂
* There are 2 Bromines on the right. Put a 2 in front of NaBr.
* Now there are 2 Sodiums (Na) on the left. Put a 2 in front of NaCl.
10. Zn + 2 AgNO₃ → Zn(NO₃)₂ + 2 Ag
* There are 2 Nitrate groups on the right. Put a 2 in front of AgNO₃.
* Now there are 2 Silvers (Ag) on the left. Put a 2 in front of Ag on the right.
11. Sn + 2 Cl₂ → SnCl₄
* There are 4 Chlorines on the right. Put a 2 in front of Cl₂ on the left.
12. Ba(OH)₂ → BaO + H₂O
* This is already balanced. 1 Barium, 2 Oxygens, and 2 Hydrogens on both sides.
13. Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
* There are 2 Chlorines on the right. Put a 2 in front of HCl.
* Now there are 4 Hydrogens total on the left (2 from OH, 2 from HCl). Put a 2 in front of H₂O.
14. Na₂CO₃ + 2 HCl → 2 NaCl + H₂CO₃
* There are 2 Sodiums on the left. Put a 2 in front of NaCl.
* Now there are 2 Chlorines on the right. Put a 2 in front of HCl.
15. NH₄NO₂ → N₂ + 2 H₂O
* There are 4 Hydrogens on the left. Put a 2 in front of H₂O on the right.
* Check Oxygens: 2 on the left, 2 on the right. It balances!
Final Answer:
1. CuO + H₂ → Cu + H₂O
2. 2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
3. MgBr₂ + Cl₂ → MgCl₂ + Br₂
4. SnO₂ + 2 C → Sn + 2 CO
5. Pb(NO₃)₂ + H₂S → PbS + 2 HNO₃
6. 2 HgO → 2 Hg + O₂
7. 2 KClO₃ → 2 KCl + 3 O₂
8. N₂ + 3 H₂ → 2 NH₃
9. 2 NaBr + Cl₂ → 2 NaCl + Br₂
10. Zn + 2 AgNO₃ → Zn(NO₃)₂ + 2 Ag
11. Sn + 2 Cl₂ → SnCl
12. Ba(OH)₂ → BaO + H₂O
13. Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
14. Na₂CO₃ + 2 HCl → 2 NaCl + H₂CO₃
15. NH₄NO₂ → N₂ + 2 H₂O
1. CuO + H₂ → Cu + H₂O
* This one is already balanced. There is 1 Copper, 1 Oxygen, and 2 Hydrogens on both sides.
2. 2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
* *Note: The product was missing in the image, but Aluminum reacts with Sulfuric Acid to form Aluminum Sulfate.*
* We need 2 Aluminums, so we put a 2 in front of Al.
* We need 3 Sulfates (SO₄), so we put a 3 in front of H₂SO₄.
* This gives us 6 Hydrogens on the left, so we put a 3 in front of H₂ on the right.
3. MgBr₂ + Cl₂ → MgCl₂ + Br₂
* This is already balanced. 1 Magnesium, 2 Bromines, and 2 Chlorines on both sides.
4. SnO₂ + 2 C → Sn + 2 CO
* There are 2 Oxygens on the left. To get 2 Oxygens on the right, we put a 2 in front of CO.
* Now there are 2 Carbons on the right, so we put a 2 in front of C on the left.
5. Pb(NO₃)₂ + H₂S → PbS + 2 HNO₃
* There are 2 Nitrate groups (NO₃) on the left. We put a 2 in front of HNO₃ on the right to match.
* This gives us 2 Hydrogens on the right, which matches the H₂ on the left.
6. 2 HgO → 2 Hg + O₂
* There are 2 Oxygens on the right. We put a 2 in front of HgO on the left.
* Now there are 2 Mercuries (Hg) on the left, so we put a 2 in front of Hg on the right.
7. 2 KClO₃ → 2 KCl + 3 O₂
* We have 3 Oxygens on the left and 2 on the right. The common multiple is 6.
* Put a 2 in front of KClO₃ (making 6 Oxygens).
* Put a 3 in front of O₂ (making 6 Oxygens).
* Now balance Potassium (K) and Chlorine (Cl) by putting a 2 in front of KCl.
8. N₂ + 3 H₂ → 2 NH₃
* There are 2 Nitrogens on the left. Put a 2 in front of NH₃.
* Now there are 6 Hydrogens on the right ($2 \times 3$). Put a 3 in front of H₂ on the left.
9. 2 NaBr + Cl₂ → 2 NaCl + Br₂
* There are 2 Bromines on the right. Put a 2 in front of NaBr.
* Now there are 2 Sodiums (Na) on the left. Put a 2 in front of NaCl.
10. Zn + 2 AgNO₃ → Zn(NO₃)₂ + 2 Ag
* There are 2 Nitrate groups on the right. Put a 2 in front of AgNO₃.
* Now there are 2 Silvers (Ag) on the left. Put a 2 in front of Ag on the right.
11. Sn + 2 Cl₂ → SnCl₄
* There are 4 Chlorines on the right. Put a 2 in front of Cl₂ on the left.
12. Ba(OH)₂ → BaO + H₂O
* This is already balanced. 1 Barium, 2 Oxygens, and 2 Hydrogens on both sides.
13. Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
* There are 2 Chlorines on the right. Put a 2 in front of HCl.
* Now there are 4 Hydrogens total on the left (2 from OH, 2 from HCl). Put a 2 in front of H₂O.
14. Na₂CO₃ + 2 HCl → 2 NaCl + H₂CO₃
* There are 2 Sodiums on the left. Put a 2 in front of NaCl.
* Now there are 2 Chlorines on the right. Put a 2 in front of HCl.
15. NH₄NO₂ → N₂ + 2 H₂O
* There are 4 Hydrogens on the left. Put a 2 in front of H₂O on the right.
* Check Oxygens: 2 on the left, 2 on the right. It balances!
Final Answer:
1. CuO + H₂ → Cu + H₂O
2. 2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
3. MgBr₂ + Cl₂ → MgCl₂ + Br₂
4. SnO₂ + 2 C → Sn + 2 CO
5. Pb(NO₃)₂ + H₂S → PbS + 2 HNO₃
6. 2 HgO → 2 Hg + O₂
7. 2 KClO₃ → 2 KCl + 3 O₂
8. N₂ + 3 H₂ → 2 NH₃
9. 2 NaBr + Cl₂ → 2 NaCl + Br₂
10. Zn + 2 AgNO₃ → Zn(NO₃)₂ + 2 Ag
11. Sn + 2 Cl₂ → SnCl
12. Ba(OH)₂ → BaO + H₂O
13. Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O
14. Na₂CO₃ + 2 HCl → 2 NaCl + H₂CO₃
15. NH₄NO₂ → N₂ + 2 H₂O
Parent Tip: Review the logic above to help your child master the concept of balancing simple chemical equations worksheet.
![Grade 9 Physical Science: Chemical Reactions] Balancing equations ...](/images2/balancing-simple-chemical-equations-worksheet/balancing-simple-chemical-equations-worksheet-31.jpg)
