To solve the problem, we need to count the place value blocks in each row and determine the total number of blocks. Place value blocks typically represent:
-
Cubes (thousands): Each cube represents 1,000.
-
Flats (hundreds): Each flat represents 100.
-
Rods (tens): Each rod represents 10.
-
Units (ones): Each unit represents 1.
Let's analyze each row step by step:
---
Row 1:
-
Cubes (thousands): 3 cubes → \(3 \times 1,000 = 3,000\)
-
Flats (hundreds): 4 flats → \(4 \times 100 = 400\)
-
Rods (tens): 5 rods → \(5 \times 10 = 50\)
-
Units (ones): 1 unit → \(1 \times 1 = 1\)
Total for Row 1:
\[
3,000 + 400 + 50 + 1 = 3,451
\]
---
Row 2:
-
Cubes (thousands): 2 cubes → \(2 \times 1,000 = 2,000\)
-
Flats (hundreds): 6 flats → \(6 \times 100 = 600\)
-
Rods (tens): 7 rods → \(7 \times 10 = 70\)
-
Units (ones): 8 units → \(8 \times 1 = 8\)
Total for Row 2:
\[
2,000 + 600 + 70 + 8 = 2,678
\]
---
Row 3:
-
Cubes (thousands): 1 cube → \(1 \times 1,000 = 1,000\)
-
Flats (hundreds): 9 flats → \(9 \times 100 = 900\)
-
Rods (tens): 6 rods → \(6 \times 10 = 60\)
-
Units (ones): 5 units → \(5 \times 1 = 5\)
Total for Row 3:
\[
1,000 + 900 + 60 + 5 = 1,965
\]
---
Row 4:
-
Cubes (thousands): 5 cubes → \(5 \times 1,000 = 5,000\)
-
Flats (hundreds): 0 flats → \(0 \times 100 = 0\)
-
Rods (tens): 8 rods → \(8 \times 10 = 80\)
-
Units (ones): 0 units → \(0 \times 1 = 0\)
Total for Row 4:
\[
5,000 + 0 + 80 + 0 = 5,080
\]
---
Row 5:
-
Cubes (thousands): 4 cubes → \(4 \times 1,000 = 4,000\)
-
Flats (hundreds): 7 flats → \(7 \times 100 = 700\)
-
Rods (tens): 9 rods → \(9 \times 10 = 90\)
-
Units (ones): 3 units → \(3 \times 1 = 3\)
Total for Row 5:
\[
4,000 + 700 + 90 + 3 = 4,793
\]
---
Final Answers:
\[
\boxed{3451, 2678, 1965, 5080, 4793}
\]
Parent Tip: Review the logic above to help your child master the concept of base ten system worksheet.
