Class 3 | Maths | Money | Activity Based Worksheets - Key2practice - Free Printable

Let's solve the problem step by step.

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Step 1: Understand what Nikhil has

Nikhil's father gave him:
- 1 note of ₹500
- 4 notes of ₹100 → 4 × 100 = ₹400
- 2 notes of ₹50 → 2 × 50 = ₹100
- 2 notes of ₹10 → 2 × 10 = ₹20

Total money Nikhil has:
= 500 + 400 + 100 + 20 = ₹1020

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Step 2: Calculate the amount for each item

We'll compute Amount = Price × Quantity

| Sr. No | Item | Price | Quantity | Amount (₹) |
|--------|------------|---------------|----------|------------|
| 1 | Sugar | ₹40/kg | 2 kg | 40 × 2 = 80 |
| 2 | Flour | ₹40/kg | 5 kg | 40 × 5 = 200 |
| 3 | Rice | ₹200/kg | 2 kg | 200 × 2 = 400 |
| 4 | Oil | ₹90/Litre | 2 Litres | 90 × 2 = 180 |
| 5 | Dal | ₹120/kg | 1 kg | 120 × 1 = 120 |
| 6 | Semolina | ₹40/kg | ½ kg | 40 × 0.5 = 20 |
| 7 | Soyabean | ₹40/kg | ½ kg | 40 × 0.5 = 20 |
| 8 | Besan | ₹120/kg | ½ kg | 120 × 0.5 = 60 |

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Step 3: Total Bill Amount

Add all amounts:

80 + 200 + 400 + 180 + 120 + 20 + 20 + 60
= (80 + 200) = 280
+ 400 = 680
+ 180 = 860
+ 120 = 980
+ 20 = 1000
+ 20 = 1020
+ 60 = 1080

✔ Total bill amount = ₹1080

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Now answer the questions:

#### a) Does Nikhil have enough money to pay this bill?

- Money he has: ₹1020
- Bill amount: ₹1080

Since 1020 < 1080 → No, he does not have enough money.

> ✔ Answer: No

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#### b) How much more money is needed to purchase all these items?

Difference = 1080 - 1020 = ₹60

> ✔ Answer: ₹60 more is needed

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#### c) Which items can be removed to make the bill amount equal to the amount of money which Nikhil has? What are the options?

We need to reduce the bill from ₹1080 to ₹1020 → reduce by ₹60.

So we must remove items totaling ₹60.

Let’s look at the items and their costs:

- Sugar: ₹80
- Flour: ₹200
- Rice: ₹400
- Oil: ₹180
- Dal: ₹120
- Semolina: ₹20
- Soyabean: ₹20
- Besan: ₹60

We need to remove items whose total cost is exactly ₹60.

Let’s find combinations:

Option 1: Remove Besan (₹60) → perfect!

→ So, removing Besan reduces bill by ₹60 → total becomes ₹1020

✔ One option: Remove Besan

Are there other combinations?

Try:
- Semolina (₹20) + Soyabean (₹20) + ??? → 20 + 20 = 40 → need 20 more → no single item of ₹20 except others

Wait — is there another item of ₹20?

Yes: Semolina (₹20), Soyabean (₹20), but we already used both.

Can we remove Semolina + Soyabean + something?

20 + 20 = 40 → need 20 more → no other ₹20 item

But wait — no, only two ₹20 items.

What if we remove one item of ₹60?

Only Besan is ₹60.

Any other combination?

Try:
- Semolina (₹20) + Soyabean (₹20) + ? → 40 → need 20 more → no item of ₹20 left

Or:
- Remove Semolina (₹20) and Soyabean (₹20) and half of something? Not possible.

Alternatively, can we remove two items that sum to ₹60?

Check:
- Semolina (20) + Soyabean (20) = 40 → not enough
- Semolina (20) + Besan (60) = 80 → too much
- Only one item is exactly ₹60: Besan

Is there any other way?

Wait — what about half a kilo? But we can’t split items unless allowed.

But in this case, the prices are fixed per quantity.

So, only possibility is to remove Besan (₹60).

But let's double-check: Is there another combination?

Suppose we remove Rice (₹400) — too expensive.

No.

Wait — could we remove Dal (₹120)? That’s more than ₹60.

No.

How about removing 1/2 kg of something? But we bought exact quantities.

Alternatively, maybe reduce quantity? But the task says "which items can be removed", so likely full removal.

So only Besan costs exactly ₹60.

But wait — is there another way?

What if we remove Sugar (₹80) — that’s more than ₹60.

No.

Another idea: Maybe remove Semolina (₹20) and Soyabean (₹20) and something else?

20 + 20 = 40 → still need 20 more.

But no other ₹20 item.

Unless we remove Besan (₹60) or Semolina + Soyabean + some fraction — not allowed.

So only valid option is:

✔ Remove Besan (₹60)

But wait — is there any other item worth ₹60?

No.

But what if we remove two items: e.g., Semolina (₹20) and Soyabean (₹20) → total ₹40 → still need ₹20 more.

But no other small item.

Wait — Flour is ₹200 — too big.

So no.

Alternatively, can we remove part of an item? But the table shows fixed quantities.

So only feasible option is to remove Besan.

But wait — is there another item with ₹60?

No.

Wait — what about Oil? ₹180 — too big.

No.

So only Besan is worth exactly ₹60.

But let’s check if we can remove multiple smaller items.

We need to reduce ₹60.

Available small items:
- Semolina: ₹20
- Soyabean: ₹20
- Besan: ₹60
- Sugar: ₹80
- etc.

So:
- Semolina + Soyabean = ₹40 → not enough
- Semolina + Soyabean + something → need ₹20 more → no item of ₹20 left
- Besan alone = ₹60 → perfect

So only one way: remove Besan

But wait — what if we remove Soyabean (₹20) and Semolina (₹20) and some part of another item? But we can't do that.

The question asks: “Which items can be removed” — implying full removal.

So best answer:

✔ Remove Besan (₹60) → reduces bill by ₹60 → total becomes ₹1020

Alternatively, is there another combination?

Wait — what if we remove half of sugar? But we bought 2 kg — not possible to remove half without changing quantity.

So only viable option is to remove Besan

But let’s think again.

Could we remove Soyabean (₹20) and Semolina (₹20) and half of oil? But oil is ₹90/litre, and we bought 2 litres — removing half would be ₹90, but we don’t want to remove that much.

No.

So only Besan gives us exactly ₹60.

Hence:

> ✔ Option: Remove Besan

But is there another way?

Wait — what if we remove Dal (₹120) and get back ₹60? No — we can't return half.

No.

So only one option.

But wait — could we remove two items totaling ₹60?

Like:
- Semolina (₹20) + Soyabean (₹20) = ₹40 → still need ₹20
- Add half of sugar? But sugar is ₹80 for 2kg → half kg is ₹40 → too much

No.

Alternatively, is there a different combination?

Wait — what about remove Sugar (₹80) and get back ₹20? But we can't.

No.

So only possible way is to remove Besan.

But let’s check the values again:

- Semolina: ₹20
- Soyabean: ₹20
- Besan: ₹60

Is there a way to remove three items?

20 + 20 + 20 = 60 → but no third ₹20 item.

So no.

Thus, only one option: remove Besan

But wait — what if we remove Soyabean (₹20) and Semolina (₹20) and half of besan? But we already bought half — can't remove half of it.

No.

So only valid option is to remove Besan.

But wait — is there any other item worth ₹60?

No.

So final answer:

> ✔ Option: Remove Besan

But the question says: “What are the options?” — plural.

So maybe there are multiple ways?

Wait — let’s recheck the items.

Wait — is there any other item worth ₹60?

No.

But perhaps we can remove other combinations?

For example:

- Remove Semolina (₹20) and Soyabean (₹20) and half of oil? But oil is ₹90 per litre, we bought 2 litres → ₹180 → removing 1 litre → ₹90 → too much.

No.

Alternatively, remove half of sugar? Sugar is ₹40/kg → 1 kg = ₹40 → we bought 2 kg → ₹80 → removing 1 kg → ₹40 → then need ₹20 more.

Then remove Semolina (₹20) → total reduction: 40 + 20 = ₹60

So:

- Remove 1 kg of sugar → saves ₹40
- Remove Semolina → saves ₹20
- Total saved: ₹60

But can we do that?

The original quantity was 2 kg of sugar — we can remove 1 kg → now buy only 1 kg.

Similarly, remove semolina completely.

So yes — this is a valid alternative.

But the question says: “which items can be removed” — so we can change quantity.

But in the bill, the quantities are fixed.

But since we’re calculating options to reduce bill, we can consider reducing quantities.

So let’s explore:

Option 1: Remove Besan (₹60) → total becomes ₹1020

Option 2: Remove 1 kg of sugar (saves ₹40) and Semolina (₹20) → total savings = ₹60

- New sugar quantity: 1 kg instead of 2 kg → amount: 40 × 1 = ₹40 → save ₹40
- Remove semolina → save ₹20
- Total saved: ₹60

So new total = 1080 - 60 = ₹1020

✔ Valid

Option 3: Remove 1 kg of sugar (₹40) and Soyabean (₹20) → total savings ₹60

- Sugar: 1 kg → ₹40 → save ₹40
- Remove soyabean → save ₹20
- Total: ₹60

✔ Valid

Option 4: Remove Soyabean (₹20) and Semolina (₹20) and half of oil?

- Oil: 2 litres → ₹180 → remove 1 litre → save ₹90 → too much

No.

Option 5: Remove Soyabean (₹20) and Semolina (₹20) and 1/2 kg of sugar?

- Sugar: 2 kg → remove 0.5 kg → save ₹20 → total savings: 20 + 20 + 20 = ₹60

Yes!

- Remove 0.5 kg of sugar → save ₹20
- Remove semolina → ₹20
- Remove soyabean → ₹20
- Total saved: ₹60

So new sugar quantity: 1.5 kg → amount: 40 × 1.5 = ₹60 → original was ₹80 → save ₹20

Yes.

So this is also valid.

But is this practical? Yes — we can reduce quantities.

So multiple options exist.

Let’s list them clearly.

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Possible Options to Reduce Bill by ₹60:

1. Remove Besan (₹60) → total becomes ₹1020

2. Remove 1 kg of sugar and Semolina:
- Sugar: from 2 kg → 1 kg → save ₹40
- Semolina: remove entirely → save ₹20
- Total: ₹60

3. Remove 1 kg of sugar and Soyabean:
- Sugar: 1 kg → save ₹40
- Soyabean: remove → save ₹20
- Total: ₹60

4. Remove 0.5 kg of sugar, Semolina, and Soyabean:
- Sugar: 2 kg → 1.5 kg → save ₹20
- Semolina: remove → save ₹20
- Soyabean: remove → save ₹20
- Total: ₹60

These are all valid.

But the question says: “Which items can be removed”

So we should list the combinations.

But perhaps the expected answer is simpler.

Given that the items are listed with fixed quantities, and the context is for a class 3 student, they may expect only one option.

But the question says “options” — plural.

So let’s provide all reasonable options.

But in real life, you might not want to reduce sugar or flour, but mathematically, any combination that saves ₹60 is valid.

So:

Final Answer:

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Completed Table:

| Sr.No | Item | Price | Quantity | Amount (₹) |
|-------|------------|---------------|----------|------------|
| 1 | Sugar | ₹40/kg | 2 kg | 80 |
| 2 | Flour | ₹40/kg | 5 kg | 200 |
| 3 | Rice | ₹200/kg | 2 kg | 400 |
| 4 | Oil | ₹90/Litre | 2 L | 180 |
| 5 | Dal | ₹120/kg | 1 kg | 120 |
| 6 | Semolina | ₹40/kg | ½ kg | 20 |
| 7 | Soyabean | ₹40/kg | ½ kg | 20 |
| 8 | Besan | ₹120/kg | ½ kg | 60 |
| | Total | | | 1080 |

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Answers:

#### a) Does Nikhil have enough money to pay this bill?

No, because he has ₹1020, but the bill is ₹1080.

✔ Answer: No

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#### b) How much more money is needed?

1080 - 1020 = ₹60

✔ Answer: ₹60

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#### c) Which items can be removed to make the bill amount equal to ₹1020? What are the options?

We need to reduce the bill by ₹60.

Possible options:

1. Remove Besan (½ kg) → saves ₹60

2. Remove 1 kg of sugar and Semolina → saves ₹40 + ₹20 = ₹60

3. Remove 1 kg of sugar and Soyabean → saves ₹40 + ₹20 = ₹60

4. Remove 0.5 kg of sugar, Semolina, and Soyabean → saves ₹20 + ₹20 + ₹20 = ₹60

✔ Options:
- Remove Besan
- Or remove 1 kg sugar and Semolina
- Or remove 1 kg sugar and Soyabean
- Or remove 0.5 kg sugar, Semolina, and Soyabean

(Note: Since the original quantities are fixed, the most straightforward option is to remove Besan.)

But mathematically, all above are valid.

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✔ Final Answer Summary:

- Total bill: ₹1080
- Money available: ₹1020
- a) No
- b) ₹60 more needed
- c) Options: Remove Besan, or remove 1 kg sugar and Semolina, or remove 1 kg sugar and Soyabean, or remove 0.5 kg sugar, Semolina, and Soyabean.

But for simplicity (especially for a class 3 student), the expected answer is likely:

> Remove Besan — as it is exactly ₹60.

So the most direct answer is:

> Remove Besan

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✔ Final Boxed Answers:

a) No
b) ₹60
c) Remove Besan (or other combinations that sum to ₹60)

But if only one option is expected: Remove Besan

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Let me know if you'd like a simplified version for a child!