BODMAS-LEVEL-1 math worksheet with 25 arithmetic problems requiring order of operations.

To solve the given problems, we will use the BODMAS rule, which stands for:

- B: Brackets
- O: Orders (exponents and roots)
- D: Division
- M: Multiplication
- A: Addition
- S: Subtraction

Let's solve each problem step by step.

---

1. \( 8 + (-9 - 3) - (-12 - 5) = \)

#### Step-by-Step Solution:
1. Solve the expressions inside the brackets first:
- \( -9 - 3 = -12 \)
- \( -12 - 5 = -17 \)

2. Substitute these values back into the expression:
\[
8 + (-12) - (-17)
\]

3. Simplify the additions and subtractions:
- \( 8 + (-12) = 8 - 12 = -4 \)
- \( -4 - (-17) = -4 + 17 = 13 \)

#### Final Answer:
\[
\boxed{13}
\]

---

2. \( 12 \times 36 \div 12 \div 3 + 5 + 6 - 2 = \)

#### Step-by-Step Solution:
1. Perform multiplication and division from left to right:
- \( 12 \times 36 = 432 \)
- \( 432 \div 12 = 36 \)
- \( 36 \div 3 = 12 \)

2. Now, substitute this value back and perform addition and subtraction:
\[
12 + 5 + 6 - 2
\]
- \( 12 + 5 = 17 \)
- \( 17 + 6 = 23 \)
- \( 23 - 2 = 21 \)

#### Final Answer:
\[
\boxed{21}
\]

---

3. \( 15 - [7 + 30 \div 6 - (6 + 6) + 7] = \)

#### Step-by-Step Solution:
1. Solve the innermost brackets first:
- \( 6 + 6 = 12 \)

2. Substitute this value back and solve the next level of brackets:
\[
7 + 30 \div 6 - 12 + 7
\]
- Perform division: \( 30 \div 6 = 5 \)
- Substitute: \( 7 + 5 - 12 + 7 \)

3. Perform addition and subtraction from left to right:
- \( 7 + 5 = 12 \)
- \( 12 - 12 = 0 \)
- \( 0 + 7 = 7 \)

4. Now, substitute this value back into the main expression:
\[
15 - 7
\]
- \( 15 - 7 = 8 \)

#### Final Answer:
\[
\boxed{8}
\]

---

4. \( 4 - (8 \times 8) + 11 - 13 = \)

#### Step-by-Step Solution:
1. Solve the expression inside the brackets:
- \( 8 \times 8 = 64 \)

2. Substitute this value back into the expression:
\[
4 - 64 + 11 - 13
\]

3. Perform addition and subtraction from left to right:
- \( 4 - 64 = -60 \)
- \( -60 + 11 = -49 \)
- \( -49 - 13 = -62 \)

#### Final Answer:
\[
\boxed{-62}
\]

---

5. \( 10 - (-11) + 60 \div (-5) + 7 - 12 = \)

#### Step-by-Step Solution:
1. Simplify the subtraction of a negative number:
- \( 10 - (-11) = 10 + 11 = 21 \)

2. Perform the division:
- \( 60 \div (-5) = -12 \)

3. Substitute these values back into the expression:
\[
21 + (-12) + 7 - 12
\]

4. Perform addition and subtraction from left to right:
- \( 21 + (-12) = 21 - 12 = 9 \)
- \( 9 + 7 = 16 \)
- \( 16 - 12 = 4 \)

#### Final Answer:
\[
\boxed{4}
\]

---

6. \( -10 + 6 + 3 = \)

#### Step-by-Step Solution:
1. Perform addition from left to right:
- \( -10 + 6 = -4 \)
- \( -4 + 3 = -1 \)

#### Final Answer:
\[
\boxed{-1}
\]

---

7. \( 12 \times 2 \div 2 = \)

#### Step-by-Step Solution:
1. Perform multiplication and division from left to right:
- \( 12 \times 2 = 24 \)
- \( 24 \div 2 = 12 \)

#### Final Answer:
\[
\boxed{12}
\]

---

8. \( 2 - [8 - \{8 \div 4 - (15 + 27 \div 3) + 2\}] = \)

#### Step-by-Step Solution:
1. Solve the innermost brackets first:
- \( 27 \div 3 = 9 \)
- \( 15 + 9 = 24 \)

2. Substitute this value back and solve the next level of brackets:
\[
8 \div 4 - 24 + 2
\]
- \( 8 \div 4 = 2 \)
- \( 2 - 24 = -22 \)
- \( -22 + 2 = -20 \)

3. Substitute this value back into the outer brackets:
\[
8 - (-20)
\]
- \( 8 - (-20) = 8 + 20 = 28 \)

4. Finally, substitute this value back into the main expression:
\[
2 - 28
\]
- \( 2 - 28 = -26 \)

#### Final Answer:
\[
\boxed{-26}
\]

---

9. \( 4 \div 2 + 4 = \)

#### Step-by-Step Solution:
1. Perform division first:
- \( 4 \div 2 = 2 \)

2. Perform addition:
- \( 2 + 4 = 6 \)

#### Final Answer:
\[
\boxed{6}
\]

---

Final Answers:

1. \( \boxed{13} \)
2. \( \boxed{21} \)
3. \( \boxed{8} \)
4. \( \boxed{-62} \)
5. \( \boxed{4} \)
6. \( \boxed{-1} \)
7. \( \boxed{12} \)
8. \( \boxed{-26} \)
9. \( \boxed{6} \)