Absolutely! Let’s solve the problem shown in the image using the
Break Apart Method (Partial Sums), which is a great strategy for understanding place value and regrouping in addition.
---
🎯 Problem to Solve:
682 + 248
We’ll break each number into its hundreds, tens, and ones, then add those parts separately.
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## ✏️ Step-by-Step Solution Using Break Apart Method:
Step 1: Break apart each number by place value
-
682 = 600 (hundreds) + 80 (tens) + 2 (ones)
-
248 = 200 (hundreds) + 40 (tens) + 8 (ones)
We write this as:
```
600 + 80 + 2
+ 200 + 40 + 8
------------------------
```
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Step 2: Add the hundreds, tens, and ones separately
-
Hundreds: 600 + 200 =
800
-
Tens: 80 + 40 =
120
-
Ones: 2 + 8 =
10
---
Step 3: Add the partial sums together
Now we add the results from each place:
> 800 + 120 + 10
Let’s do it step by step:
- 800 + 120 =
920
- 920 + 10 =
930
✔ So,
682 + 248 = 930
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## 🔍 Why This Works (Explanation):
The Break Apart Method helps students understand
place value — that each digit represents a different value (hundreds, tens, ones). Instead of just “carrying” numbers like in the standard algorithm, you’re adding similar place values together first. This makes regrouping more intuitive because you can see *why* you might need to regroup (e.g., 120 in the tens place means you have 1 hundred and 20 tens).
In this case:
- The tens sum was 120 → that’s 100 + 20 → so you’d regroup 100 to the hundreds.
- The ones sum was 10 → that’s 10 → you’d regroup 10 to the tens (but since we already added everything, we just combine all partial sums).
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## 🧩 Final Answer:
>
682 + 248 = 930
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## 💡 Tip for Students:
When using the Break Apart Method, always line up the same place values when adding — hundreds with hundreds, tens with tens, etc. This prevents mistakes and builds strong number sense!
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Let me know if you’d like to see this solved with the standard algorithm too — or try another problem! 😊
Parent Tip: Review the logic above to help your child master the concept of breaking apart worksheet.
