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Substituting equilibrium pressures into the equilibrium constant expression to solve for x.

Equation for calculating equilibrium pressure using partial pressures in a chemical reaction, showing the substitution of equilibrium pressures into the expression for K, resulting in a solved value of x = 4.43×10⁻⁵ atm.

Equation for calculating equilibrium pressure using partial pressures in a chemical reaction, showing the substitution of equilibrium pressures into the expression for K, resulting in a solved value of x = 4.43×10⁻⁵ atm.

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