Adding Fractions Worksheets - Free Printable
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Step-by-step solution for: Adding Fractions Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Adding Fractions Worksheets
To solve the problems involving adding and subtracting fractions with unlike denominators, we need to follow these steps:
1. Find a Common Denominator: The least common denominator (LCD) is the smallest number that is a multiple of all the denominators involved.
2. Adjust the Fractions: Rewrite each fraction with the common denominator by multiplying both the numerator and the denominator by the necessary factor.
3. Add or Subtract the Numerators: Once the denominators are the same, add or subtract the numerators as needed.
4. Simplify the Result: Reduce the resulting fraction to its simplest form if possible.
Let's solve each problem step by step.
---
1. Find the LCD: The denominators are 3 and 5. The LCD is $3 \times 5 = 15$.
2. Adjust the fractions:
- $\frac{4}{3} = \frac{4 \times 5}{3 \times 5} = \frac{20}{15}$
- $\frac{2}{5} = \frac{2 \times 3}{5 \times 3} = \frac{6}{15}$
3. Add the fractions:
$$
\frac{20}{15} + \frac{6}{15} = \frac{20 + 6}{15} = \frac{26}{15}
$$
4. Simplify: $\frac{26}{15}$ is already in simplest form.
Answer: $\boxed{\frac{26}{15}}$
---
1. Find the LCD: The denominators are 10 and 5. The LCD is 10.
2. Adjust the fractions:
- $\frac{7}{10}$ remains $\frac{7}{10}$.
- $\frac{2}{5} = \frac{2 \times 2}{5 \times 2} = \frac{4}{10}$
3. Subtract the fractions:
$$
\frac{7}{10} - \frac{4}{10} = \frac{7 - 4}{10} = \frac{3}{10}
$$
4. Simplify: $\frac{3}{10}$ is already in simplest form.
Answer: $\boxed{\frac{3}{10}}$
---
1. Find the LCD: The denominators are 9 and 7. The LCD is $9 \times 7 = 63$.
2. Adjust the fractions:
- $\frac{5}{9} = \frac{5 \times 7}{9 \times 7} = \frac{35}{63}$
- $\frac{2}{7} = \frac{2 \times 9}{7 \times 9} = \frac{18}{63}$
3. Add the fractions:
$$
\frac{35}{63} + \frac{18}{63} = \frac{35 + 18}{63} = \frac{53}{63}
$$
4. Simplify: $\frac{53}{63}$ is already in simplest form.
Answer: $\boxed{\frac{53}{63}}$
---
1. Find the LCD: The denominators are 8 and 4. The LCD is 8.
2. Adjust the fractions:
- $\frac{4}{8}$ remains $\frac{4}{8}$.
- $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$
3. Subtract the fractions:
$$
\frac{4}{8} - \frac{2}{8} = \frac{4 - 2}{8} = \frac{2}{8}
$$
4. Simplify: $\frac{2}{8} = \frac{1}{4}$.
Answer: $\boxed{\frac{1}{4}}$
---
1. Find the LCD: The denominators are 9 and 3. The LCD is 9.
2. Adjust the fractions:
- $\frac{3}{9}$ remains $\frac{3}{9}$.
- $\frac{1}{3} = \frac{1 \times 3}{3 \times 3} = \frac{3}{9}$
3. Add the fractions:
$$
\frac{3}{9} + \frac{3}{9} = \frac{3 + 3}{9} = \frac{6}{9}
$$
4. Simplify: $\frac{6}{9} = \frac{2}{3}$.
Answer: $\boxed{\frac{2}{3}}$
---
1. Find the LCD: The denominators are 5 and 10. The LCD is 10.
2. Adjust the fractions:
- $\frac{2}{5} = \frac{2 \times 2}{5 \times 2} = \frac{4}{10}$
- $\frac{1}{10}$ remains $\frac{1}{10}$.
3. Add the fractions:
$$
\frac{4}{10} + \frac{1}{10} = \frac{4 + 1}{10} = \frac{5}{10}
$$
4. Simplify: $\frac{5}{10} = \frac{1}{2}$.
Answer: $\boxed{\frac{1}{2}}$
---
1. Find the LCD: The denominators are 5 and 10. The LCD is 10.
2. Adjust the fractions:
- $\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10}$
- $\frac{9}{10}$ remains $\frac{9}{10}$.
3. Add the fractions:
$$
\frac{8}{10} + \frac{9}{10} = \frac{8 + 9}{10} = \frac{17}{10}
$$
4. Simplify: $\frac{17}{10}$ is already in simplest form.
Answer: $\boxed{\frac{17}{10}}$
---
1. Find the LCD: The denominators are 6 and 3. The LCD is 6.
2. Adjust the fractions:
- $\frac{4}{6}$ remains $\frac{4}{6}$.
- $\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}$
3. Subtract the fractions:
$$
\frac{4}{6} - \frac{2}{6} = \frac{4 - 2}{6} = \frac{2}{6}
$$
4. Simplify: $\frac{2}{6} = \frac{1}{3}$.
Answer: $\boxed{\frac{1}{3}}$
---
1. Find the LCD: The denominators are 12 and 4. The LCD is 12.
2. Adjust the fractions:
- $\frac{3}{12}$ remains $\frac{3}{12}$.
- $\frac{2}{4} = \frac{2 \times 3}{4 \times 3} = \frac{6}{12}$
3. Add the fractions:
$$
\frac{3}{12} + \frac{6}{12} = \frac{3 + 6}{12} = \frac{9}{12}
$$
4. Simplify: $\frac{9}{12} = \frac{3}{4}$.
Answer: $\boxed{\frac{3}{4}}$
---
1. Find the LCD: The denominators are 12 and 6. The LCD is 12.
2. Adjust the fractions:
- $\frac{5}{12}$ remains $\frac{5}{12}$.
- $\frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}$
3. Subtract the fractions:
$$
\frac{5}{12} - \frac{2}{12} = \frac{5 - 2}{12} = \frac{3}{12}
$$
4. Simplify: $\frac{3}{12} = \frac{1}{4}$.
Answer: $\boxed{\frac{1}{4}}$
---
1. Find the LCD: The denominators are 8 and 9. The LCD is $8 \times 9 = 72$.
2. Adjust the fractions:
- $\frac{2}{8} = \frac{2 \times 9}{8 \times 9} = \frac{18}{72}$
- $\frac{3}{9} = \frac{3 \times 8}{9 \times 8} = \frac{24}{72}$
3. Add the fractions:
$$
\frac{18}{72} + \frac{24}{72} = \frac{18 + 24}{72} = \frac{42}{72}
$$
4. Simplify: $\frac{42}{72} = \frac{7}{12}$.
Answer: $\boxed{\frac{7}{12}}$
---
1. Find the LCD: The denominators are 4 and 8. The LCD is 8.
2. Adjust the fractions:
- $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$
- $\frac{1}{8}$ remains $\frac{1}{8}$.
3. Subtract the fractions:
$$
\frac{2}{8} - \frac{1}{8} = \frac{2 - 1}{8} = \frac{1}{8}
$$
4. Simplify: $\frac{1}{8}$ is already in simplest form.
Answer: $\boxed{\frac{1}{8}}$
---
1. Find the LCD: The denominators are 7 and 6. The LCD is $7 \times 6 = 42$.
2. Adjust the fractions:
- $\frac{6}{7} = \frac{6 \times 6}{7 \times 6} = \frac{36}{42}$
- $\frac{2}{6} = \frac{2 \times 7}{6 \times 7} = \frac{14}{42}$
3. Add the fractions:
$$
\frac{36}{42} + \frac{14}{42} = \frac{36 + 14}{42} = \frac{50}{42}
$$
4. Simplify: $\frac{50}{42} = \frac{25}{21}$.
Answer: $\boxed{\frac{25}{21}}$
---
1. Find the LCD: The denominators are 3 and 7. The LCD is $3 \times 7 = 21$.
2. Adjust the fractions:
- $\frac{1}{3} = \frac{1 \times 7}{3 \times 7} = \frac{7}{21}$
- $\frac{1}{7} = \frac{1 \times 3}{7 \times 3} = \frac{3}{21}$
3. Subtract the fractions:
$$
\frac{7}{21} - \frac{3}{21} = \frac{7 - 3}{21} = \frac{4}{21}
$$
4. Simplify: $\frac{4}{21}$ is already in simplest form.
Answer: $\boxed{\frac{4}{21}}$
---
1. Find the LCD: The denominators are 8 and 5. The LCD is $8 \times 5 = 40$.
2. Adjust the fractions:
- $\frac{7}{8} = \frac{7 \times 5}{8 \times 5} = \frac{35}{40}$
- $\frac{4}{5} = \frac{4 \times 8}{5 \times 8} = \frac{32}{40}$
3. Add the fractions:
$$
\frac{35}{40} + \frac{32}{40} = \frac{35 + 32}{40} = \frac{67}{40}
$$
4. Simplify: $\frac{67}{40}$ is already in simplest form.
Answer: $\boxed{\frac{67}{40}}$
---
1. $\boxed{\frac{26}{15}}$
2. $\boxed{\frac{3}{10}}$
3. $\boxed{\frac{53}{63}}$
4. $\boxed{\frac{1}{4}}$
5. $\boxed{\frac{2}{3}}$
6. $\boxed{\frac{1}{2}}$
7. $\boxed{\frac{17}{10}}$
8. $\boxed{\frac{1}{3}}$
9. $\boxed{\frac{3}{4}}$
10. $\boxed{\frac{1}{4}}$
11. $\boxed{\frac{7}{12}}$
12. $\boxed{\frac{1}{8}}$
13. $\boxed{\frac{25}{21}}$
14. $\boxed{\frac{4}{21}}$
15. $\boxed{\frac{67}{40}}$
1. Find a Common Denominator: The least common denominator (LCD) is the smallest number that is a multiple of all the denominators involved.
2. Adjust the Fractions: Rewrite each fraction with the common denominator by multiplying both the numerator and the denominator by the necessary factor.
3. Add or Subtract the Numerators: Once the denominators are the same, add or subtract the numerators as needed.
4. Simplify the Result: Reduce the resulting fraction to its simplest form if possible.
Let's solve each problem step by step.
---
Problem 1: $\frac{4}{3} + \frac{2}{5}$
1. Find the LCD: The denominators are 3 and 5. The LCD is $3 \times 5 = 15$.
2. Adjust the fractions:
- $\frac{4}{3} = \frac{4 \times 5}{3 \times 5} = \frac{20}{15}$
- $\frac{2}{5} = \frac{2 \times 3}{5 \times 3} = \frac{6}{15}$
3. Add the fractions:
$$
\frac{20}{15} + \frac{6}{15} = \frac{20 + 6}{15} = \frac{26}{15}
$$
4. Simplify: $\frac{26}{15}$ is already in simplest form.
Answer: $\boxed{\frac{26}{15}}$
---
Problem 2: $\frac{7}{10} - \frac{2}{5}$
1. Find the LCD: The denominators are 10 and 5. The LCD is 10.
2. Adjust the fractions:
- $\frac{7}{10}$ remains $\frac{7}{10}$.
- $\frac{2}{5} = \frac{2 \times 2}{5 \times 2} = \frac{4}{10}$
3. Subtract the fractions:
$$
\frac{7}{10} - \frac{4}{10} = \frac{7 - 4}{10} = \frac{3}{10}
$$
4. Simplify: $\frac{3}{10}$ is already in simplest form.
Answer: $\boxed{\frac{3}{10}}$
---
Problem 3: $\frac{5}{9} + \frac{2}{7}$
1. Find the LCD: The denominators are 9 and 7. The LCD is $9 \times 7 = 63$.
2. Adjust the fractions:
- $\frac{5}{9} = \frac{5 \times 7}{9 \times 7} = \frac{35}{63}$
- $\frac{2}{7} = \frac{2 \times 9}{7 \times 9} = \frac{18}{63}$
3. Add the fractions:
$$
\frac{35}{63} + \frac{18}{63} = \frac{35 + 18}{63} = \frac{53}{63}
$$
4. Simplify: $\frac{53}{63}$ is already in simplest form.
Answer: $\boxed{\frac{53}{63}}$
---
Problem 4: $\frac{4}{8} - \frac{1}{4}$
1. Find the LCD: The denominators are 8 and 4. The LCD is 8.
2. Adjust the fractions:
- $\frac{4}{8}$ remains $\frac{4}{8}$.
- $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$
3. Subtract the fractions:
$$
\frac{4}{8} - \frac{2}{8} = \frac{4 - 2}{8} = \frac{2}{8}
$$
4. Simplify: $\frac{2}{8} = \frac{1}{4}$.
Answer: $\boxed{\frac{1}{4}}$
---
Problem 5: $\frac{3}{9} + \frac{1}{3}$
1. Find the LCD: The denominators are 9 and 3. The LCD is 9.
2. Adjust the fractions:
- $\frac{3}{9}$ remains $\frac{3}{9}$.
- $\frac{1}{3} = \frac{1 \times 3}{3 \times 3} = \frac{3}{9}$
3. Add the fractions:
$$
\frac{3}{9} + \frac{3}{9} = \frac{3 + 3}{9} = \frac{6}{9}
$$
4. Simplify: $\frac{6}{9} = \frac{2}{3}$.
Answer: $\boxed{\frac{2}{3}}$
---
Problem 6: $\frac{2}{5} + \frac{1}{10}$
1. Find the LCD: The denominators are 5 and 10. The LCD is 10.
2. Adjust the fractions:
- $\frac{2}{5} = \frac{2 \times 2}{5 \times 2} = \frac{4}{10}$
- $\frac{1}{10}$ remains $\frac{1}{10}$.
3. Add the fractions:
$$
\frac{4}{10} + \frac{1}{10} = \frac{4 + 1}{10} = \frac{5}{10}
$$
4. Simplify: $\frac{5}{10} = \frac{1}{2}$.
Answer: $\boxed{\frac{1}{2}}$
---
Problem 7: $\frac{4}{5} + \frac{9}{10}$
1. Find the LCD: The denominators are 5 and 10. The LCD is 10.
2. Adjust the fractions:
- $\frac{4}{5} = \frac{4 \times 2}{5 \times 2} = \frac{8}{10}$
- $\frac{9}{10}$ remains $\frac{9}{10}$.
3. Add the fractions:
$$
\frac{8}{10} + \frac{9}{10} = \frac{8 + 9}{10} = \frac{17}{10}
$$
4. Simplify: $\frac{17}{10}$ is already in simplest form.
Answer: $\boxed{\frac{17}{10}}$
---
Problem 8: $\frac{4}{6} - \frac{1}{3}$
1. Find the LCD: The denominators are 6 and 3. The LCD is 6.
2. Adjust the fractions:
- $\frac{4}{6}$ remains $\frac{4}{6}$.
- $\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}$
3. Subtract the fractions:
$$
\frac{4}{6} - \frac{2}{6} = \frac{4 - 2}{6} = \frac{2}{6}
$$
4. Simplify: $\frac{2}{6} = \frac{1}{3}$.
Answer: $\boxed{\frac{1}{3}}$
---
Problem 9: $\frac{3}{12} + \frac{2}{4}$
1. Find the LCD: The denominators are 12 and 4. The LCD is 12.
2. Adjust the fractions:
- $\frac{3}{12}$ remains $\frac{3}{12}$.
- $\frac{2}{4} = \frac{2 \times 3}{4 \times 3} = \frac{6}{12}$
3. Add the fractions:
$$
\frac{3}{12} + \frac{6}{12} = \frac{3 + 6}{12} = \frac{9}{12}
$$
4. Simplify: $\frac{9}{12} = \frac{3}{4}$.
Answer: $\boxed{\frac{3}{4}}$
---
Problem 10: $\frac{5}{12} - \frac{1}{6}$
1. Find the LCD: The denominators are 12 and 6. The LCD is 12.
2. Adjust the fractions:
- $\frac{5}{12}$ remains $\frac{5}{12}$.
- $\frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12}$
3. Subtract the fractions:
$$
\frac{5}{12} - \frac{2}{12} = \frac{5 - 2}{12} = \frac{3}{12}
$$
4. Simplify: $\frac{3}{12} = \frac{1}{4}$.
Answer: $\boxed{\frac{1}{4}}$
---
Problem 11: $\frac{2}{8} + \frac{3}{9}$
1. Find the LCD: The denominators are 8 and 9. The LCD is $8 \times 9 = 72$.
2. Adjust the fractions:
- $\frac{2}{8} = \frac{2 \times 9}{8 \times 9} = \frac{18}{72}$
- $\frac{3}{9} = \frac{3 \times 8}{9 \times 8} = \frac{24}{72}$
3. Add the fractions:
$$
\frac{18}{72} + \frac{24}{72} = \frac{18 + 24}{72} = \frac{42}{72}
$$
4. Simplify: $\frac{42}{72} = \frac{7}{12}$.
Answer: $\boxed{\frac{7}{12}}$
---
Problem 12: $\frac{1}{4} - \frac{1}{8}$
1. Find the LCD: The denominators are 4 and 8. The LCD is 8.
2. Adjust the fractions:
- $\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}$
- $\frac{1}{8}$ remains $\frac{1}{8}$.
3. Subtract the fractions:
$$
\frac{2}{8} - \frac{1}{8} = \frac{2 - 1}{8} = \frac{1}{8}
$$
4. Simplify: $\frac{1}{8}$ is already in simplest form.
Answer: $\boxed{\frac{1}{8}}$
---
Problem 13: $\frac{6}{7} + \frac{2}{6}$
1. Find the LCD: The denominators are 7 and 6. The LCD is $7 \times 6 = 42$.
2. Adjust the fractions:
- $\frac{6}{7} = \frac{6 \times 6}{7 \times 6} = \frac{36}{42}$
- $\frac{2}{6} = \frac{2 \times 7}{6 \times 7} = \frac{14}{42}$
3. Add the fractions:
$$
\frac{36}{42} + \frac{14}{42} = \frac{36 + 14}{42} = \frac{50}{42}
$$
4. Simplify: $\frac{50}{42} = \frac{25}{21}$.
Answer: $\boxed{\frac{25}{21}}$
---
Problem 14: $\frac{1}{3} - \frac{1}{7}$
1. Find the LCD: The denominators are 3 and 7. The LCD is $3 \times 7 = 21$.
2. Adjust the fractions:
- $\frac{1}{3} = \frac{1 \times 7}{3 \times 7} = \frac{7}{21}$
- $\frac{1}{7} = \frac{1 \times 3}{7 \times 3} = \frac{3}{21}$
3. Subtract the fractions:
$$
\frac{7}{21} - \frac{3}{21} = \frac{7 - 3}{21} = \frac{4}{21}
$$
4. Simplify: $\frac{4}{21}$ is already in simplest form.
Answer: $\boxed{\frac{4}{21}}$
---
Problem 15: $\frac{7}{8} + \frac{4}{5}$
1. Find the LCD: The denominators are 8 and 5. The LCD is $8 \times 5 = 40$.
2. Adjust the fractions:
- $\frac{7}{8} = \frac{7 \times 5}{8 \times 5} = \frac{35}{40}$
- $\frac{4}{5} = \frac{4 \times 8}{5 \times 8} = \frac{32}{40}$
3. Add the fractions:
$$
\frac{35}{40} + \frac{32}{40} = \frac{35 + 32}{40} = \frac{67}{40}
$$
4. Simplify: $\frac{67}{40}$ is already in simplest form.
Answer: $\boxed{\frac{67}{40}}$
---
Final Answers
1. $\boxed{\frac{26}{15}}$
2. $\boxed{\frac{3}{10}}$
3. $\boxed{\frac{53}{63}}$
4. $\boxed{\frac{1}{4}}$
5. $\boxed{\frac{2}{3}}$
6. $\boxed{\frac{1}{2}}$
7. $\boxed{\frac{17}{10}}$
8. $\boxed{\frac{1}{3}}$
9. $\boxed{\frac{3}{4}}$
10. $\boxed{\frac{1}{4}}$
11. $\boxed{\frac{7}{12}}$
12. $\boxed{\frac{1}{8}}$
13. $\boxed{\frac{25}{21}}$
14. $\boxed{\frac{4}{21}}$
15. $\boxed{\frac{67}{40}}$
Parent Tip: Review the logic above to help your child master the concept of common denominator worksheets.