Ordering fractions worksheet with mixed numbers for math practice.
Worksheet titled "Ordering Fractions" with ten problems requiring students to order mixed numbers in increasing order.
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Step-by-step solution for: Ordering Fractions Worksheets - 15 Worksheets Library
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Show Answer Key & Explanations
Step-by-step solution for: Ordering Fractions Worksheets - 15 Worksheets Library
Let’s solve each problem step by step. We need to order the mixed numbers from smallest to largest (increasing order).
To compare mixed numbers, we can:
1. Look at the whole number part first — smaller whole number = smaller number.
2. If whole numbers are the same, compare the fractions by finding a common denominator or converting to decimals.
We’ll go one by one.
---
Problem 1:
2 ³⁄₁₀ , 3 ²⁄₅ , 1 ¹⁄₂₀ , 2 ²⁄₁₅
Whole numbers: 2, 3, 1, 2 → So 1 ¹⁄₂₀ is smallest.
Now compare the two with whole number 2: 2 ³⁄₁₀ and 2 ²⁄₁₅
Compare ³⁄₁₀ and ²⁄₁₅
LCM of 10 and 15 is 30.
³⁄₁₀ = 9⁄30, ²⁄₁₅ = 4⁄30 → so 2 ²⁄₁₅ < 2 ³⁄₁₀
Then 3 ²⁄₅ is largest.
Order:
1 ¹⁄₂₀ , 2 ²⁄₁₅ , 2 ³⁄₁₀ , 3 ²⁄₅
---
Problem 2:
1 ¹⁄₁₂ , 3 ⁵⁄₆ , 1 ⁷⁄₁₈ , 5 ²⁄₃
Whole numbers: 1, 3, 1, 5 → So 5 ²⁄₃ is largest, then 3 ⁵⁄₆.
Now compare the two with whole number 1: 1 ¹⁄₁₂ and 1 ⁷⁄₁₈
Compare ¹⁄₁₂ and ⁷⁄₁₈
LCM of 12 and 18 is 36.
¹⁄₁₂ = 3⁄36, ⁷⁄₁₈ = 14⁄36 → so 1 ¹⁄₁₂ < 1 ⁷⁄₁₈
Order:
1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 3 ⁵⁄₆ , 5 ²⁄₃
---
Problem 3:
1 ⁵⁄₈ , 2 ³⁄₄ , 3 ¹⁄₂ , 2 ³⁄₁₀
Whole numbers: 1, 2, 3, 2 → So 1 ⁵₈ is smallest, then 3 ¹⁄₂ is largest.
Now compare the two with whole number 2: 2 ³⁄₄ and 2 ³⁄₁₀
Compare ³⁄₄ and ³⁄₁₀ → since numerators are same, larger denominator = smaller fraction → ³⁄₁₀ < ³⁄₄
So order:
1 ⁵⁄ , 2 ³₁₀ , 2 ³⁄₄ , 3 ¹⁄₂
---
Problem 4:
5 ¹⁄₄ , 1 ³⁄₈ , 3 ¹⁄₂ , 2 ⁵₆
Whole numbers: 5, 1, 3, 2 → So order by whole numbers:
1 ³⁄₈ , 2 ⁵⁄ , 3 ¹₂ , 5 ¹⁄₄
No ties in whole numbers, so done.
---
Problem 5:
1 ¹⁄₁₂ , 3 ⁵⁄ , 2 ¹₁₂ , 1 ⁷⁄₁₈
Whole numbers: 1, 3, 2, 1 → So 3 ⁵₆ is largest.
Now group the 1s: 1 ¹⁄₁₂ and 1 ⁷₁₈
As before: ¹⁄₁₂ = 3⁄36, ⁷⁄₁₈ = 14⁄36 → so 1 ¹⁄₁₂ < 1 ⁷⁄₁₈
Then 2 ¹⁄₁₂ comes next.
Order:
1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 2 ¹⁄₁₂ , 3 ⁵⁄₆
---
Problem 6:
2 ³⁄₁₀ , 1 ³⁄₅ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
Whole numbers: 2, 1, 2, 3 → So 1 ³⁄₅ is smallest, 3 ²⁄₁₅ is largest.
Now compare the two 2s: 2 ³⁄₁₀ and 2 ¹¹₂₀
Convert to twentieths: ³⁄₁₀ = 6⁄20, ¹¹⁄₂₀ = 11⁄20 → so 2 ³⁄₁₀ < 2 ¹¹₂₀
Order:
1 ³⁄₅ , 2 ³⁄₁₀ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
---
Problem 7:
3 ¹⁄₁₀ , 2 ³⁄₂₀ , 5 ⁴⁄₅ , 1 ⁹⁄₂₅
Whole numbers: 3, 2, 5, 1 → Order by whole numbers:
1 ⁹₂₅ , 2³⁄₂₀ , 3 ¹⁄₁₀ , 5 ⁴₅
Done.
---
Problem 8:
2 ⁄₁₅ , 3 ²⁄₉ , 2 ⁵₁₂ , 1 ¹⁄₁₈
Whole numbers: 2, 3, 2, 1 → So 1 ¹⁄₁₈ is smallest, 3 ²⁄₉ is largest.
Now compare the two 2s: 2 ⁷₁₅ and 2⁵⁄₁₂
Find LCM of 15 and 12 → 60
⁷⁄₁₅ = 28⁄60, ⁵⁄₁₂ = 25⁄60 → so 2 ⁵₁₂ < 2 ⁷⁄₁₅
Order:
1 ¹⁄₁₈ , 2 ⁵⁄₁₂ , 2 ⁷₁₅ , 3²⁄₉
---
Problem 9:
2 ⁷⁄₈ , 1 ¹⁄₁₂ , 3 ⁵⁄₆ , 3 ³⁄₄
Whole numbers: 2, 1, 3, 3 → So 1 ¹⁄₁₂ is smallest.
Then 2 ⁷⁄₈.
Now compare the two 3s: 3 ⁵⁄ and 3 ³₄
LCM of 6 and 4 is 12.
⁵⁄₆ = 10⁄12, ³⁄₄ = 9⁄12 → so 3 ³⁄₄ < 3 ⁵₆
Order:
1 ¹⁄₁₂ , 2 ⁷⁄₈ , 3 ³⁄₄ , 3 ⁵₆
---
Problem 10:
2 ¹⁄₁₂ , 1 ⁵⁄₈ , 3 ¹⁄₄ , 1 ⁷⁄₁₆
Whole numbers: 2, 1, 3, 1 → So 3 ¹⁄₄ is largest.
Group the 1s: 1 ⁵₈ and 1 ⁷⁄₁₆
Convert to sixteenths: ⁵⁄₈ = 10⁄16, ⁷⁄₁₆ = 7⁄16 → so 1 ⁷⁄₁₆ < 1 ⁵⁄
Then 2 ¹⁄₁₂ comes next.
Order:
1 ⁷⁄₁₆ , 1 ⁵⁄₈ , 2 ¹⁄₁₂ , 3 ¹⁄₄
---
Final Answer:
1) 1 ¹⁄₂₀ , 2 ²⁄₁₅ , 2 ³⁄₁₀ , 3 ²⁄₅
2) 1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 3 ⁵⁄₆ , 5 ²⁄₃
3) 1 ⁵⁄₈ , 2 ³⁄₁₀ , 2 ³⁄₄ , 3 ¹⁄₂
4) 1 ³⁄₈ , 2 ⁵⁄₆ , 3 ¹⁄₂ , 5 ¹⁄₄
5) 1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 2 ¹⁄₁₂ , 3 ⁵⁄₆
6) 1 ³⁄₅ , 2 ³⁄₁₀ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
7) 1 ⁹⁄₂₅ , 2 ³⁄₂₀ , 3 ¹⁄₁₀ , 5 ⁴⁄₅
8) 1 ¹⁄₁₈ , 2 ⁵⁄₁₂ , 2 ⁷₁₅ , 3 ²⁄₉
9) 1 ¹⁄₁₂ , 2 ⁷⁄₈ , 3 ³⁄₄ , 3 ⁵₆
10) 1 ⁷⁄₁₆ , 1 ⁵⁄ , 2 ¹₁₂ , 3 ¹⁄₄
To compare mixed numbers, we can:
1. Look at the whole number part first — smaller whole number = smaller number.
2. If whole numbers are the same, compare the fractions by finding a common denominator or converting to decimals.
We’ll go one by one.
---
Problem 1:
2 ³⁄₁₀ , 3 ²⁄₅ , 1 ¹⁄₂₀ , 2 ²⁄₁₅
Whole numbers: 2, 3, 1, 2 → So 1 ¹⁄₂₀ is smallest.
Now compare the two with whole number 2: 2 ³⁄₁₀ and 2 ²⁄₁₅
Compare ³⁄₁₀ and ²⁄₁₅
LCM of 10 and 15 is 30.
³⁄₁₀ = 9⁄30, ²⁄₁₅ = 4⁄30 → so 2 ²⁄₁₅ < 2 ³⁄₁₀
Then 3 ²⁄₅ is largest.
Order:
1 ¹⁄₂₀ , 2 ²⁄₁₅ , 2 ³⁄₁₀ , 3 ²⁄₅
---
Problem 2:
1 ¹⁄₁₂ , 3 ⁵⁄₆ , 1 ⁷⁄₁₈ , 5 ²⁄₃
Whole numbers: 1, 3, 1, 5 → So 5 ²⁄₃ is largest, then 3 ⁵⁄₆.
Now compare the two with whole number 1: 1 ¹⁄₁₂ and 1 ⁷⁄₁₈
Compare ¹⁄₁₂ and ⁷⁄₁₈
LCM of 12 and 18 is 36.
¹⁄₁₂ = 3⁄36, ⁷⁄₁₈ = 14⁄36 → so 1 ¹⁄₁₂ < 1 ⁷⁄₁₈
Order:
1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 3 ⁵⁄₆ , 5 ²⁄₃
---
Problem 3:
1 ⁵⁄₈ , 2 ³⁄₄ , 3 ¹⁄₂ , 2 ³⁄₁₀
Whole numbers: 1, 2, 3, 2 → So 1 ⁵₈ is smallest, then 3 ¹⁄₂ is largest.
Now compare the two with whole number 2: 2 ³⁄₄ and 2 ³⁄₁₀
Compare ³⁄₄ and ³⁄₁₀ → since numerators are same, larger denominator = smaller fraction → ³⁄₁₀ < ³⁄₄
So order:
1 ⁵⁄ , 2 ³₁₀ , 2 ³⁄₄ , 3 ¹⁄₂
---
Problem 4:
5 ¹⁄₄ , 1 ³⁄₈ , 3 ¹⁄₂ , 2 ⁵₆
Whole numbers: 5, 1, 3, 2 → So order by whole numbers:
1 ³⁄₈ , 2 ⁵⁄ , 3 ¹₂ , 5 ¹⁄₄
No ties in whole numbers, so done.
---
Problem 5:
1 ¹⁄₁₂ , 3 ⁵⁄ , 2 ¹₁₂ , 1 ⁷⁄₁₈
Whole numbers: 1, 3, 2, 1 → So 3 ⁵₆ is largest.
Now group the 1s: 1 ¹⁄₁₂ and 1 ⁷₁₈
As before: ¹⁄₁₂ = 3⁄36, ⁷⁄₁₈ = 14⁄36 → so 1 ¹⁄₁₂ < 1 ⁷⁄₁₈
Then 2 ¹⁄₁₂ comes next.
Order:
1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 2 ¹⁄₁₂ , 3 ⁵⁄₆
---
Problem 6:
2 ³⁄₁₀ , 1 ³⁄₅ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
Whole numbers: 2, 1, 2, 3 → So 1 ³⁄₅ is smallest, 3 ²⁄₁₅ is largest.
Now compare the two 2s: 2 ³⁄₁₀ and 2 ¹¹₂₀
Convert to twentieths: ³⁄₁₀ = 6⁄20, ¹¹⁄₂₀ = 11⁄20 → so 2 ³⁄₁₀ < 2 ¹¹₂₀
Order:
1 ³⁄₅ , 2 ³⁄₁₀ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
---
Problem 7:
3 ¹⁄₁₀ , 2 ³⁄₂₀ , 5 ⁴⁄₅ , 1 ⁹⁄₂₅
Whole numbers: 3, 2, 5, 1 → Order by whole numbers:
1 ⁹₂₅ , 2³⁄₂₀ , 3 ¹⁄₁₀ , 5 ⁴₅
Done.
---
Problem 8:
2 ⁄₁₅ , 3 ²⁄₉ , 2 ⁵₁₂ , 1 ¹⁄₁₈
Whole numbers: 2, 3, 2, 1 → So 1 ¹⁄₁₈ is smallest, 3 ²⁄₉ is largest.
Now compare the two 2s: 2 ⁷₁₅ and 2⁵⁄₁₂
Find LCM of 15 and 12 → 60
⁷⁄₁₅ = 28⁄60, ⁵⁄₁₂ = 25⁄60 → so 2 ⁵₁₂ < 2 ⁷⁄₁₅
Order:
1 ¹⁄₁₈ , 2 ⁵⁄₁₂ , 2 ⁷₁₅ , 3²⁄₉
---
Problem 9:
2 ⁷⁄₈ , 1 ¹⁄₁₂ , 3 ⁵⁄₆ , 3 ³⁄₄
Whole numbers: 2, 1, 3, 3 → So 1 ¹⁄₁₂ is smallest.
Then 2 ⁷⁄₈.
Now compare the two 3s: 3 ⁵⁄ and 3 ³₄
LCM of 6 and 4 is 12.
⁵⁄₆ = 10⁄12, ³⁄₄ = 9⁄12 → so 3 ³⁄₄ < 3 ⁵₆
Order:
1 ¹⁄₁₂ , 2 ⁷⁄₈ , 3 ³⁄₄ , 3 ⁵₆
---
Problem 10:
2 ¹⁄₁₂ , 1 ⁵⁄₈ , 3 ¹⁄₄ , 1 ⁷⁄₁₆
Whole numbers: 2, 1, 3, 1 → So 3 ¹⁄₄ is largest.
Group the 1s: 1 ⁵₈ and 1 ⁷⁄₁₆
Convert to sixteenths: ⁵⁄₈ = 10⁄16, ⁷⁄₁₆ = 7⁄16 → so 1 ⁷⁄₁₆ < 1 ⁵⁄
Then 2 ¹⁄₁₂ comes next.
Order:
1 ⁷⁄₁₆ , 1 ⁵⁄₈ , 2 ¹⁄₁₂ , 3 ¹⁄₄
---
Final Answer:
1) 1 ¹⁄₂₀ , 2 ²⁄₁₅ , 2 ³⁄₁₀ , 3 ²⁄₅
2) 1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 3 ⁵⁄₆ , 5 ²⁄₃
3) 1 ⁵⁄₈ , 2 ³⁄₁₀ , 2 ³⁄₄ , 3 ¹⁄₂
4) 1 ³⁄₈ , 2 ⁵⁄₆ , 3 ¹⁄₂ , 5 ¹⁄₄
5) 1 ¹⁄₁₂ , 1 ⁷⁄₁₈ , 2 ¹⁄₁₂ , 3 ⁵⁄₆
6) 1 ³⁄₅ , 2 ³⁄₁₀ , 2 ¹¹⁄₂₀ , 3 ²⁄₁₅
7) 1 ⁹⁄₂₅ , 2 ³⁄₂₀ , 3 ¹⁄₁₀ , 5 ⁴⁄₅
8) 1 ¹⁄₁₈ , 2 ⁵⁄₁₂ , 2 ⁷₁₅ , 3 ²⁄₉
9) 1 ¹⁄₁₂ , 2 ⁷⁄₈ , 3 ³⁄₄ , 3 ⁵₆
10) 1 ⁷⁄₁₆ , 1 ⁵⁄ , 2 ¹₁₂ , 3 ¹⁄₄
Parent Tip: Review the logic above to help your child master the concept of comparing fractions same denominator worksheet.