Worksheet titled "Cross Multiplication" featuring five word problems that require solving using cross multiplication, including scenarios about a truck's fuel efficiency, factory production, taxi fare, apple cost, and ship travel distance.

To solve these problems using cross multiplication, we will set up proportions for each problem and solve them step by step. Let's go through each question:

---

Problem 1:

A truck covers 432 miles in 36 gallons of fuel. How much distance would it cover in 25 gallons of fuel?

#### Step 1: Set up the proportion
The relationship between distance and fuel is proportional:
\[
\frac{\text{Distance}}{\text{Fuel}} = \frac{\text{Distance}}{\text{Fuel}}
\]
Given:
\[
\frac{432 \text{ miles}}{36 \text{ gallons}} = \frac{x \text{ miles}}{25 \text{ gallons}}
\]

#### Step 2: Cross-multiply
\[
432 \times 25 = 36 \times x
\]

#### Step 3: Solve for \( x \)
\[
10800 = 36x
\]
\[
x = \frac{10800}{36}
\]
\[
x = 300
\]

#### Answer:
\[
\boxed{300 \text{ miles}}
\]

---

Problem 2:

A factory can produce 20 boxes of pencils in a minute. How many boxes does the factory make in 30 minutes?

#### Step 1: Set up the proportion
The relationship between time and production is proportional:
\[
\frac{\text{Boxes}}{\text{Time}} = \frac{\text{Boxes}}{\text{Time}}
\]
Given:
\[
\frac{20 \text{ boxes}}{1 \text{ minute}} = \frac{x \text{ boxes}}{30 \text{ minutes}}
\]

#### Step 2: Cross-multiply
\[
20 \times 30 = 1 \times x
\]

#### Step 3: Solve for \( x \)
\[
x = 600
\]

#### Answer:
\[
\boxed{600 \text{ boxes}}
\]

---

Problem 3:

A taxi charges a fare of $1275 for a journey of 150 miles. How much would it charge for a journey of 124 miles?

#### Step 1: Set up the proportion
The relationship between fare and distance is proportional:
\[
\frac{\text{Fare}}{\text{Distance}} = \frac{\text{Fare}}{\text{Distance}}
\]
Given:
\[
\frac{1275 \text{ dollars}}{150 \text{ miles}} = \frac{x \text{ dollars}}{124 \text{ miles}}
\]

#### Step 2: Cross-multiply
\[
1275 \times 124 = 150 \times x
\]

#### Step 3: Solve for \( x \)
\[
158100 = 150x
\]
\[
x = \frac{158100}{150}
\]
\[
x = 1054
\]

#### Answer:
\[
\boxed{1054 \text{ dollars}}
\]

---

Problem 4:

If 8 apples cost $4, how much would 40 apples cost?

#### Step 1: Set up the proportion
The relationship between the number of apples and cost is proportional:
\[
\frac{\text{Apples}}{\text{Cost}} = \frac{\text{Apples}}{\text{Cost}}
\]
Given:
\[
\frac{8 \text{ apples}}{4 \text{ dollars}} = \frac{40 \text{ apples}}{x \text{ dollars}}
\]

#### Step 2: Cross-multiply
\[
8 \times x = 4 \times 40
\]

#### Step 3: Solve for \( x \)
\[
8x = 160
\]
\[
x = \frac{160}{8}
\]
\[
x = 20
\]

#### Answer:
\[
\boxed{20 \text{ dollars}}
\]

---

Problem 5:

A ship covers 16 miles in 25 minutes. At the same speed, how far can it travel in 5 hours?

#### Step 1: Convert 5 hours to minutes
Since there are 60 minutes in an hour:
\[
5 \text{ hours} = 5 \times 60 = 300 \text{ minutes}
\]

#### Step 2: Set up the proportion
The relationship between distance and time is proportional:
\[
\frac{\text{Distance}}{\text{Time}} = \frac{\text{Distance}}{\text{Time}}
\]
Given:
\[
\frac{16 \text{ miles}}{25 \text{ minutes}} = \frac{x \text{ miles}}{300 \text{ minutes}}
\]

#### Step 3: Cross-multiply
\[
16 \times 300 = 25 \times x
\]

#### Step 4: Solve for \( x \)
\[
4800 = 25x
\]
\[
x = \frac{4800}{25}
\]
\[
x = 192
\]

#### Answer:
\[
\boxed{192 \text{ miles}}
\]

---

Final Answers:

1. \(\boxed{300 \text{ miles}}\)
2. \(\boxed{600 \text{ boxes}}\)
3. \(\boxed{1054 \text{ dollars}}\)
4. \(\boxed{20 \text{ dollars}}\)
5. \(\boxed{192 \text{ miles}}\)