Division crossword puzzle worksheet - Free Printable

Problem Description:

The task is to solve a math crossword puzzle where you need to fill in the blanks to make all the division equations true. The puzzle consists of horizontal and vertical equations that intersect, and the goal is to find numbers that satisfy all the given divisions.

Puzzle Layout:

The puzzle is divided into two sections:
1. Left Section:
- Top row: \( 20 \div \_\_ = 4 \)
- Middle row: \( \_\_ \div \_\_ = 2 \)
- Bottom row: \( \_\_ \div \_\_ = 6 \)
- Left column: \( 20 \div \_\_ = 5 \)

2. Right Section:
- Top row: \( \_\_ \div 2 = 9 \)
- Middle row: \( \_\_ \div 3 = \_\_ \)
- Bottom row: \( \_\_ = 9 \)

Solution Approach:

We will solve each equation step by step, ensuring that the intersecting values are consistent across both sections.

---

#### Step 1: Solve the Left Section

1. Top Row: \( 20 \div \_\_ = 4 \)
- To find the missing number, we use the formula: \( \text{Dividend} \div \text{Divisor} = \text{Quotient} \).
- Here, \( 20 \div x = 4 \). Solving for \( x \):
\[
x = \frac{20}{4} = 5
\]
- So, the top row becomes: \( 20 \div 5 = 4 \).

2. Left Column: \( 20 \div \_\_ = 5 \)
- Similarly, \( 20 \div y = 5 \). Solving for \( y \):
\[
y = \frac{20}{5} = 4
\]
- So, the left column becomes: \( 20 \div 4 = 5 \).

3. Middle Row: \( \_\_ \div \_\_ = 2 \)
- From the left column, we know the first blank in the middle row is \( 4 \). So, the equation becomes: \( 4 \div z = 2 \). Solving for \( z \):
\[
z = \frac{4}{2} = 2
\]
- So, the middle row becomes: \( 4 \div 2 = 2 \).

4. Bottom Row: \( \_\_ \div \_\_ = 6 \)
- From the top row, we know the first blank in the bottom row is \( 5 \). So, the equation becomes: \( 5 \div w = 6 \). Solving for \( w \):
\[
w = \frac{5}{6}
\]
- However, since the puzzle likely involves whole numbers, let's recheck the consistency. The bottom row should be consistent with the rest of the puzzle. Given the structure, it seems there might be an error in interpretation. Let's assume the bottom row is independent and solve it separately if needed.

---

#### Step 2: Solve the Right Section

1. Top Row: \( \_\_ \div 2 = 9 \)
- To find the missing number, we use the formula: \( x \div 2 = 9 \). Solving for \( x \):
\[
x = 9 \times 2 = 18
\]
- So, the top row becomes: \( 18 \div 2 = 9 \).

2. Bottom Row: \( \_\_ = 9 \)
- This is straightforward: the missing number is \( 9 \).

3. Middle Row: \( \_\_ \div 3 = \_\_ \)
- From the top row, we know the first blank in the middle row is \( 18 \). So, the equation becomes: \( 18 \div 3 = y \). Solving for \( y \):
\[
y = \frac{18}{3} = 6
\]
- So, the middle row becomes: \( 18 \div 3 = 6 \).

---

#### Step 3: Verify Consistency
- Left Section:
- Top row: \( 20 \div 5 = 4 \) (correct)
- Middle row: \( 4 \div 2 = 2 \) (correct)
- Bottom row: \( 5 \div \frac{5}{6} = 6 \) (not whole number, but consistent with division)
- Left column: \( 20 \div 4 = 5 \) (correct)

- Right Section:
- Top row: \( 18 \div 2 = 9 \) (correct)
- Middle row: \( 18 \div 3 = 6 \) (correct)
- Bottom row: \( 9 = 9 \) (correct)

---

Final Answer:

The completed crossword puzzle is:

\[
\begin{array}{|c|c|c|c|}
\hline
20 & \div & 5 & = & 4 \\
\hline
\div & 4 & \div & 2 \\
\hline
= & 2 & = & 2 \\
\hline
5 & \div & \frac{5}{6} & = & 6 \\
\hline
\end{array}
\quad
\begin{array}{|c|c|c|c|}
\hline
18 & \div & 2 & = & 9 \\
\hline
\div & 18 & \div & 3 \\
\hline
= & 6 & = & 6 \\
\hline
9 & & & & 9 \\
\hline
\end{array}
\]

\[
\boxed{
\begin{array}{|c|c|c|c|}
\hline
20 & \div & 5 & = & 4 \\
\hline
\div & 4 & \div & 2 \\
\hline
= & 2 & = & 2 \\
\hline
5 & \div & \frac{5}{6} & = & 6 \\
\hline
\end{array}
\quad
\begin{array}{|c|c|c|c|}
\hline
18 & \div & 2 & = & 9 \\
\hline
\div & 18 & \div & 3 \\
\hline
= & 6 & = & 6 \\
\hline
9 & & & & 9 \\
\hline
\end{array}
}
\]