Division worksheet for solving 1-digit divisor problems with 4-digit dividends and remainders.

Let’s solve each division problem step by step. We’re dividing a 2-digit number by a 1-digit divisor and finding the quotient with remainder (if any).

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Problem 1: 24 ÷ 4

4 × 6 = 24 → no remainder
→ Quotient: 6, Remainder: 0

Problem 2: 21 ÷ 3

3 × 7 = 21 → no remainder
→ Quotient: 7, Remainder: 0

Problem 3: 49 ÷ 7

7 × 7 = 49 → no remainder
→ Quotient: 7, Remainder: 0

Problem 4: 40 ÷ 5

5 × 8 = 40 → no remainder
→ Quotient: 8, Remainder: 0

Problem 5: 93 ÷ 3

3 × 30 = 90 → 93 - 90 = 3 → 3 ÷ 3 = 1 → total quotient = 31
Check: 3 × 31 = 93 → no remainder
→ Quotient: 31, Remainder: 0

Wait — let me double-check that.

Actually, 3 × 31 = 93? Let's compute:
3 × 30 = 90, plus 3 × 1 = 3 → 90 + 3 = 93 → yes. So remainder is 0.

But wait — maybe I should do it digit by digit for clarity.

Divide 9 by 3 → 3
Bring down 3 → 3 ÷ 3 = 1
So quotient is 31, remainder 0.

✔ Correct.

Problem 6: 40 ÷ 8

8 × 5 = 40 → no remainder
→ Quotient: 5, Remainder: 0

Problem 7: 72 ÷ 8

8 × 9 = 72 → no remainder
→ Quotient: 9, Remainder: 0

Problem 8: 78 ÷ 6

6 × 13 = ?

6 × 10 = 60
6 × 3 = 18 → 60 + 18 = 78 → so 13
→ Quotient: 13, Remainder: 0

Check: 6 × 13 = 78 → correct.

Problem 9: 18 ÷ 3

3 × 6 = 18 → no remainder
→ Quotient: 6, Remainder: 0

Problem 10: 36 ÷ 6

6 × 6 = 36 → no remainder
→ Quotient: 6, Remainder: 0

Problem 11: 48 ÷ 4

4 × 12 = 48 → because 4 × 10 = 40, 4 × 2 = 8 → 40 + 8 = 48
→ Quotient: 12, Remainder: 0

Problem 12: 18 ÷ 2

2 × 9 = 18 → no remainder
→ Quotient: 9, Remainder: 0

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Wait — all of these have zero remainders? That seems odd for a worksheet titled “With Remainders”. Let me recheck each one carefully.

Maybe I misread some numbers?

Looking back at the problems:

1. 24 ÷ 4 → 6 R0 ✔
2. 21 ÷ 3 → 7 R0 ✔
3. 49 ÷ 7 → 7 R0 ✔
4. 40 ÷ 5 → 8 R0 ✔
5. 93 ÷ 3 → 31 R0 ✔
6. 40 ÷ 8 → 5 R0 ✔
7. 72 ÷ 8 → 9 R0 ✔
8. 78 ÷ 6 → 13 R0 ✔
9. 18 ÷ 3 → 6 R0 ✔
10. 36 ÷ 6 → 6 R0 ✔
11. 48 ÷ 4 → 12 R0 ✔
12. 18 ÷ 2 → 9 R0 ✔

Hmm… actually, looking again — perhaps the title says “with remainders” but not every problem has one? Or maybe I made a mistake in reading the dividends?

Wait — let me check Problem 5 again: 93 ÷ 3.

Is 93 divisible by 3? Yes — 9+3=12, which is divisible by 3 → so yes, 31 exactly.

Problem 8: 78 ÷ 6 → 78 ÷ 6 = 13 → 6×13=78 → correct.

All are exact divisions. Maybe the worksheet includes some without remainders too? The instructions say “solve by finding the quotient with a remainder” — which could mean if there *is* a remainder, write it; if not, write 0.

In math, we often write remainder even if it’s zero.

So final answers should be written as:

Quotient R Remainder

Even if remainder is 0.

So let’s list them properly:

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Final Answers:

1. 6 R0
2. 7 R0
3. 7 R0
4. 8 R0
5. 31 R0
6. 5 R0
7. 9 R0
8. 13 R0
9. 6 R0
10. 6 R0
11. 12 R0
12. 9 R0

But wait — let me verify once more for possible errors.

Problem 5: 93 ÷ 3

Do long division:

3 into 9 → 3
3 into 3 → 1
So 31 → correct.

Problem 8: 78 ÷ 6

6 into 7 → 1 (write 1), 6×1=6, subtract → 1
Bring down 8 → 18
6 into 18 → 3
So 13 → correct.

All seem correct.

Perhaps the worksheet just happens to have all exact divisions? Unusual, but possible.

Alternatively — did I misread any dividend?

Looking again:

Problem 5: Is it 93 or 92? In the image description, user wrote “93” — assuming that’s accurate.

Same for others.

Given the data provided, all divisions result in whole numbers.

So final answer format per instruction: just provide the final correct answer — probably listing all 12 results.

Since the user didn’t specify format, but the worksheet asks to “write out each division equation... and solve”, likely expects 12 answers.

I’ll present them clearly.

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Final Answer:
1. 6 R0
2. 7 R0
3. 7 R0
4. 8 R0
5. 31 R0
6. 5 R0
7. 9 R0
8. 13 R0
9. 6 R0
10. 6 R0
11. 12 R0
12. 9 R0