Grade 5 Division Worksheet 1: Solve the division equations.
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Show Answer Key & Explanations
Step-by-step solution for: Grade 4 Division Worksheets | Free Printables | Math Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Grade 4 Division Worksheets | Free Printables | Math Worksheets
The task involves solving division problems. Below, I will solve each problem step by step and explain the process.
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Solution:
1. Divide 340 by 8.
2. Perform long division:
- 8 goes into 34 (the first two digits) 4 times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
- Bring down the next digit (0), making it 20.
- 8 goes into 20 two times (since \( 8 \times 2 = 16 \)).
- Subtract \( 16 \) from \( 20 \) to get a remainder of \( 4 \).
Thus, \( 340 \div 8 = 42 \) with a remainder of 4.
Answer: \( 42 \text{ R } 4 \)
---
Solution:
1. Divide 5996 by 8.
2. Perform long division:
- 8 goes into 59 (the first two digits) 7 times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 59 \) to get a remainder of \( 3 \).
- Bring down the next digit (9), making it 39.
- 8 goes into 39 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 39 \) to get a remainder of \( 7 \).
- Bring down the next digit (6), making it 76.
- 8 goes into 76 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 76 \) to get a remainder of \( 4 \).
Thus, \( 5996 \div 8 = 749 \) with a remainder of 4.
Answer: \( 749 \text{ R } 4 \)
---
Solution:
1. Divide 684 by 8.
2. Perform long division:
- 8 goes into 68 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 68 \) to get a remainder of \( 4 \).
- Bring down the next digit (4), making it 44.
- 8 goes into 44 five times (since \( 8 \times 5 = 40 \)).
- Subtract \( 40 \) from \( 44 \) to get a remainder of \( 4 \).
Thus, \( 684 \div 8 = 85 \) with a remainder of 4.
Answer: \( 85 \text{ R } 4 \)
---
Solution:
1. Divide 2353 by 4.
2. Perform long division:
- 4 goes into 23 (the first two digits) 5 times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 23 \) to get a remainder of \( 3 \).
- Bring down the next digit (5), making it 35.
- 4 goes into 35 eight times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 35 \) to get a remainder of \( 3 \).
- Bring down the next digit (3), making it 33.
- 4 goes into 33 eight times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 33 \) to get a remainder of \( 1 \).
Thus, \( 2353 \div 4 = 588 \) with a remainder of 1.
Answer: \( 588 \text{ R } 1 \)
---
Solution:
1. Divide 674 by 8.
2. Perform long division:
- 8 goes into 67 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 67 \) to get a remainder of \( 3 \).
- Bring down the next digit (4), making it 34.
- 8 goes into 34 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
Thus, \( 674 \div 8 = 84 \) with a remainder of 2.
Answer: \( 84 \text{ R } 2 \)
---
Solution:
1. Divide 4628 by 8.
2. Perform long division:
- 8 goes into 46 (the first two digits) 5 times (since \( 8 \times 5 = 40 \)).
- Subtract \( 40 \) from \( 46 \) to get a remainder of \( 6 \).
- Bring down the next digit (2), making it 62.
- 8 goes into 62 seven times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 62 \) to get a remainder of \( 6 \).
- Bring down the next digit (8), making it 68.
- 8 goes into 68 eight times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 68 \) to get a remainder of \( 4 \).
Thus, \( 4628 \div 8 = 578 \) with a remainder of 4.
Answer: \( 578 \text{ R } 4 \)
---
Solution:
1. Divide 2059 by 5.
2. Perform long division:
- 5 goes into 20 (the first two digits) 4 times (since \( 5 \times 4 = 20 \)).
- Subtract \( 20 \) from \( 20 \) to get a remainder of \( 0 \).
- Bring down the next digit (5), making it 5.
- 5 goes into 5 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 5 \) to get a remainder of \( 0 \).
- Bring down the next digit (9), making it 9.
- 5 goes into 9 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 9 \) to get a remainder of \( 4 \).
Thus, \( 2059 \div 5 = 411 \) with a remainder of 4.
Answer: \( 411 \text{ R } 4 \)
---
Solution:
1. Divide 3581 by 4.
2. Perform long division:
- 4 goes into 35 (the first two digits) 8 times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 35 \) to get a remainder of \( 3 \).
- Bring down the next digit (8), making it 38.
- 4 goes into 38 nine times (since \( 4 \times 9 = 36 \)).
- Subtract \( 36 \) from \( 38 \) to get a remainder of \( 2 \).
- Bring down the next digit (1), making it 21.
- 4 goes into 21 five times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 21 \) to get a remainder of \( 1 \).
Thus, \( 3581 \div 4 = 895 \) with a remainder of 1.
Answer: \( 895 \text{ R } 1 \)
---
Solution:
1. Divide 6634 by 8.
2. Perform long division:
- 8 goes into 66 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 66 \) to get a remainder of \( 2 \).
- Bring down the next digit (3), making it 23.
- 8 goes into 23 two times (since \( 8 \times 2 = 16 \)).
- Subtract \( 16 \) from \( 23 \) to get a remainder of \( 7 \).
- Bring down the next digit (4), making it 74.
- 8 goes into 74 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 74 \) to get a remainder of \( 2 \).
Thus, \( 6634 \div 8 = 829 \) with a remainder of 2.
Answer: \( 829 \text{ R } 2 \)
---
Solution:
1. Divide 7711 by 10.
2. Perform long division:
- 10 goes into 77 (the first two digits) 7 times (since \( 10 \times 7 = 70 \)).
- Subtract \( 70 \) from \( 77 \) to get a remainder of \( 7 \).
- Bring down the next digit (1), making it 71.
- 10 goes into 71 seven times (since \( 10 \times 7 = 70 \)).
- Subtract \( 70 \) from \( 71 \) to get a remainder of \( 1 \).
- Bring down the next digit (1), making it 11.
- 10 goes into 11 one time (since \( 10 \times 1 = 10 \)).
- Subtract \( 10 \) from \( 11 \) to get a remainder of \( 1 \).
Thus, \( 7711 \div 10 = 771 \) with a remainder of 1.
Answer: \( 771 \text{ R } 1 \)
---
Solution:
1. Divide 1661 by 4.
2. Perform long division:
- 4 goes into 16 (the first two digits) 4 times (since \( 4 \times 4 = 16 \)).
- Subtract \( 16 \) from \( 16 \) to get a remainder of \( 0 \).
- Bring down the next digit (6), making it 6.
- 4 goes into 6 one time (since \( 4 \times 1 = 4 \)).
- Subtract \( 4 \) from \( 6 \) to get a remainder of \( 2 \).
- Bring down the next digit (6), making it 26.
- 4 goes into 26 six times (since \( 4 \times 6 = 24 \)).
- Subtract \( 24 \) from \( 26 \) to get a remainder of \( 2 \).
- Bring down the next digit (1), making it 21.
- 4 goes into 21 five times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 21 \) to get a remainder of \( 1 \).
Thus, \( 1661 \div 4 = 415 \) with a remainder of 1.
Answer: \( 415 \text{ R } 1 \)
---
Solution:
1. Divide 2359 by 5.
2. Perform long division:
- 5 goes into 23 (the first two digits) 4 times (since \( 5 \times 4 = 20 \)).
- Subtract \( 20 \) from \( 23 \) to get a remainder of \( 3 \).
- Bring down the next digit (5), making it 35.
- 5 goes into 35 seven times (since \( 5 \times 7 = 35 \)).
- Subtract \( 35 \) from \( 35 \) to get a remainder of \( 0 \).
- Bring down the next digit (9), making it 9.
- 5 goes into 9 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 9 \) to get a remainder of \( 4 \).
Thus, \( 2359 \div 5 = 471 \) with a remainder of 4.
Answer: \( 471 \text{ R } 4 \)
---
Solution:
1. Divide 5948 by 8.
2. Perform long division:
- 8 goes into 59 (the first two digits) 7 times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 59 \) to get a remainder of \( 3 \).
- Bring down the next digit (4), making it 34.
- 8 goes into 34 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
- Bring down the next digit (8), making it 28.
- 8 goes into 28 three times (since \( 8 \times 3 = 24 \)).
- Subtract \( 24 \) from \( 28 \) to get a remainder of \( 4 \).
Thus, \( 5948 \div 8 = 743 \) with a remainder of 4.
Answer: \( 743 \text{ R } 4 \)
---
Solution:
1. Divide 4319 by 10.
2. Perform long division:
- 10 goes into 43 (the first two digits) 4 times (since \( 10 \times 4 = 40 \)).
- Subtract \( 40 \) from \( 43 \) to get a remainder of \( 3 \).
- Bring down the next digit (1), making it 31.
- 10 goes into 31 three times (since \( 10 \times 3 = 30 \)).
- Subtract \( 30 \) from \( 31 \) to get a remainder of \( 1 \).
- Bring down the next digit (9), making it 19.
- 10 goes into 19 one time (since \( 10 \times 1 = 10 \)).
- Subtract \( 10 \) from \( 19 \) to get a remainder of \( 9 \).
Thus, \( 4319 \div 10 = 431 \) with a remainder of 9.
Answer: \( 431 \text{ R } 9 \)
---
Solution:
1. Divide 7146 by 8.
2. Perform long division:
- 8 goes into 71 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 71 \) to get a remainder of \( 7 \).
- Bring down the next digit (4), making it 74.
- 8 goes into 74 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 74 \) to get a remainder of \( 2 \).
- Bring down the next digit (6), making it 26.
- 8 goes into 26 three times (since \( 8 \times 3 = 24 \)).
- Subtract \( 24 \) from \( 26 \) to get a remainder of \( 2 \).
Thus, \( 7146 \div 8 = 893 \) with a remainder of 2.
Answer: \( 893 \text{ R } 2 \)
---
\[
\boxed{
\begin{aligned}
1. & \ 42 \text{ R } 4 \\
2. & \ 749 \text{ R } 4 \\
3. & \ 85 \text{ R } 4 \\
4. & \ 588 \text{ R } 1 \\
5. & \ 84 \text{ R } 2 \\
6. & \ 578 \text{ R } 4 \\
7. & \ 411 \text{ R } 4 \\
8. & \ 895 \text{ R } 1 \\
9. & \ 829 \text{ R } 2 \\
10. & \ 771 \text{ R } 1 \\
11. & \ 415 \text{ R } 1 \\
12. & \ 471 \text{ R } 4 \\
13. & \ 743 \text{ R } 4 \\
14. & \ 431 \text{ R } 9 \\
15. & \ 893 \text{ R } 2 \\
\end{aligned}
}
\]
---
Problem 1: \( 8 \div 340 \)
Solution:
1. Divide 340 by 8.
2. Perform long division:
- 8 goes into 34 (the first two digits) 4 times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
- Bring down the next digit (0), making it 20.
- 8 goes into 20 two times (since \( 8 \times 2 = 16 \)).
- Subtract \( 16 \) from \( 20 \) to get a remainder of \( 4 \).
Thus, \( 340 \div 8 = 42 \) with a remainder of 4.
Answer: \( 42 \text{ R } 4 \)
---
Problem 2: \( 8 \div 5996 \)
Solution:
1. Divide 5996 by 8.
2. Perform long division:
- 8 goes into 59 (the first two digits) 7 times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 59 \) to get a remainder of \( 3 \).
- Bring down the next digit (9), making it 39.
- 8 goes into 39 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 39 \) to get a remainder of \( 7 \).
- Bring down the next digit (6), making it 76.
- 8 goes into 76 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 76 \) to get a remainder of \( 4 \).
Thus, \( 5996 \div 8 = 749 \) with a remainder of 4.
Answer: \( 749 \text{ R } 4 \)
---
Problem 3: \( 8 \div 684 \)
Solution:
1. Divide 684 by 8.
2. Perform long division:
- 8 goes into 68 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 68 \) to get a remainder of \( 4 \).
- Bring down the next digit (4), making it 44.
- 8 goes into 44 five times (since \( 8 \times 5 = 40 \)).
- Subtract \( 40 \) from \( 44 \) to get a remainder of \( 4 \).
Thus, \( 684 \div 8 = 85 \) with a remainder of 4.
Answer: \( 85 \text{ R } 4 \)
---
Problem 4: \( 4 \div 2353 \)
Solution:
1. Divide 2353 by 4.
2. Perform long division:
- 4 goes into 23 (the first two digits) 5 times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 23 \) to get a remainder of \( 3 \).
- Bring down the next digit (5), making it 35.
- 4 goes into 35 eight times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 35 \) to get a remainder of \( 3 \).
- Bring down the next digit (3), making it 33.
- 4 goes into 33 eight times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 33 \) to get a remainder of \( 1 \).
Thus, \( 2353 \div 4 = 588 \) with a remainder of 1.
Answer: \( 588 \text{ R } 1 \)
---
Problem 5: \( 8 \div 674 \)
Solution:
1. Divide 674 by 8.
2. Perform long division:
- 8 goes into 67 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 67 \) to get a remainder of \( 3 \).
- Bring down the next digit (4), making it 34.
- 8 goes into 34 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
Thus, \( 674 \div 8 = 84 \) with a remainder of 2.
Answer: \( 84 \text{ R } 2 \)
---
Problem 6: \( 8 \div 4628 \)
Solution:
1. Divide 4628 by 8.
2. Perform long division:
- 8 goes into 46 (the first two digits) 5 times (since \( 8 \times 5 = 40 \)).
- Subtract \( 40 \) from \( 46 \) to get a remainder of \( 6 \).
- Bring down the next digit (2), making it 62.
- 8 goes into 62 seven times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 62 \) to get a remainder of \( 6 \).
- Bring down the next digit (8), making it 68.
- 8 goes into 68 eight times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 68 \) to get a remainder of \( 4 \).
Thus, \( 4628 \div 8 = 578 \) with a remainder of 4.
Answer: \( 578 \text{ R } 4 \)
---
Problem 7: \( 5 \div 2059 \)
Solution:
1. Divide 2059 by 5.
2. Perform long division:
- 5 goes into 20 (the first two digits) 4 times (since \( 5 \times 4 = 20 \)).
- Subtract \( 20 \) from \( 20 \) to get a remainder of \( 0 \).
- Bring down the next digit (5), making it 5.
- 5 goes into 5 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 5 \) to get a remainder of \( 0 \).
- Bring down the next digit (9), making it 9.
- 5 goes into 9 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 9 \) to get a remainder of \( 4 \).
Thus, \( 2059 \div 5 = 411 \) with a remainder of 4.
Answer: \( 411 \text{ R } 4 \)
---
Problem 8: \( 4 \div 3581 \)
Solution:
1. Divide 3581 by 4.
2. Perform long division:
- 4 goes into 35 (the first two digits) 8 times (since \( 4 \times 8 = 32 \)).
- Subtract \( 32 \) from \( 35 \) to get a remainder of \( 3 \).
- Bring down the next digit (8), making it 38.
- 4 goes into 38 nine times (since \( 4 \times 9 = 36 \)).
- Subtract \( 36 \) from \( 38 \) to get a remainder of \( 2 \).
- Bring down the next digit (1), making it 21.
- 4 goes into 21 five times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 21 \) to get a remainder of \( 1 \).
Thus, \( 3581 \div 4 = 895 \) with a remainder of 1.
Answer: \( 895 \text{ R } 1 \)
---
Problem 9: \( 8 \div 6634 \)
Solution:
1. Divide 6634 by 8.
2. Perform long division:
- 8 goes into 66 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 66 \) to get a remainder of \( 2 \).
- Bring down the next digit (3), making it 23.
- 8 goes into 23 two times (since \( 8 \times 2 = 16 \)).
- Subtract \( 16 \) from \( 23 \) to get a remainder of \( 7 \).
- Bring down the next digit (4), making it 74.
- 8 goes into 74 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 74 \) to get a remainder of \( 2 \).
Thus, \( 6634 \div 8 = 829 \) with a remainder of 2.
Answer: \( 829 \text{ R } 2 \)
---
Problem 10: \( 10 \div 7711 \)
Solution:
1. Divide 7711 by 10.
2. Perform long division:
- 10 goes into 77 (the first two digits) 7 times (since \( 10 \times 7 = 70 \)).
- Subtract \( 70 \) from \( 77 \) to get a remainder of \( 7 \).
- Bring down the next digit (1), making it 71.
- 10 goes into 71 seven times (since \( 10 \times 7 = 70 \)).
- Subtract \( 70 \) from \( 71 \) to get a remainder of \( 1 \).
- Bring down the next digit (1), making it 11.
- 10 goes into 11 one time (since \( 10 \times 1 = 10 \)).
- Subtract \( 10 \) from \( 11 \) to get a remainder of \( 1 \).
Thus, \( 7711 \div 10 = 771 \) with a remainder of 1.
Answer: \( 771 \text{ R } 1 \)
---
Problem 11: \( 4 \div 1661 \)
Solution:
1. Divide 1661 by 4.
2. Perform long division:
- 4 goes into 16 (the first two digits) 4 times (since \( 4 \times 4 = 16 \)).
- Subtract \( 16 \) from \( 16 \) to get a remainder of \( 0 \).
- Bring down the next digit (6), making it 6.
- 4 goes into 6 one time (since \( 4 \times 1 = 4 \)).
- Subtract \( 4 \) from \( 6 \) to get a remainder of \( 2 \).
- Bring down the next digit (6), making it 26.
- 4 goes into 26 six times (since \( 4 \times 6 = 24 \)).
- Subtract \( 24 \) from \( 26 \) to get a remainder of \( 2 \).
- Bring down the next digit (1), making it 21.
- 4 goes into 21 five times (since \( 4 \times 5 = 20 \)).
- Subtract \( 20 \) from \( 21 \) to get a remainder of \( 1 \).
Thus, \( 1661 \div 4 = 415 \) with a remainder of 1.
Answer: \( 415 \text{ R } 1 \)
---
Problem 12: \( 5 \div 2359 \)
Solution:
1. Divide 2359 by 5.
2. Perform long division:
- 5 goes into 23 (the first two digits) 4 times (since \( 5 \times 4 = 20 \)).
- Subtract \( 20 \) from \( 23 \) to get a remainder of \( 3 \).
- Bring down the next digit (5), making it 35.
- 5 goes into 35 seven times (since \( 5 \times 7 = 35 \)).
- Subtract \( 35 \) from \( 35 \) to get a remainder of \( 0 \).
- Bring down the next digit (9), making it 9.
- 5 goes into 9 one time (since \( 5 \times 1 = 5 \)).
- Subtract \( 5 \) from \( 9 \) to get a remainder of \( 4 \).
Thus, \( 2359 \div 5 = 471 \) with a remainder of 4.
Answer: \( 471 \text{ R } 4 \)
---
Problem 13: \( 8 \div 5948 \)
Solution:
1. Divide 5948 by 8.
2. Perform long division:
- 8 goes into 59 (the first two digits) 7 times (since \( 8 \times 7 = 56 \)).
- Subtract \( 56 \) from \( 59 \) to get a remainder of \( 3 \).
- Bring down the next digit (4), making it 34.
- 8 goes into 34 four times (since \( 8 \times 4 = 32 \)).
- Subtract \( 32 \) from \( 34 \) to get a remainder of \( 2 \).
- Bring down the next digit (8), making it 28.
- 8 goes into 28 three times (since \( 8 \times 3 = 24 \)).
- Subtract \( 24 \) from \( 28 \) to get a remainder of \( 4 \).
Thus, \( 5948 \div 8 = 743 \) with a remainder of 4.
Answer: \( 743 \text{ R } 4 \)
---
Problem 14: \( 10 \div 4319 \)
Solution:
1. Divide 4319 by 10.
2. Perform long division:
- 10 goes into 43 (the first two digits) 4 times (since \( 10 \times 4 = 40 \)).
- Subtract \( 40 \) from \( 43 \) to get a remainder of \( 3 \).
- Bring down the next digit (1), making it 31.
- 10 goes into 31 three times (since \( 10 \times 3 = 30 \)).
- Subtract \( 30 \) from \( 31 \) to get a remainder of \( 1 \).
- Bring down the next digit (9), making it 19.
- 10 goes into 19 one time (since \( 10 \times 1 = 10 \)).
- Subtract \( 10 \) from \( 19 \) to get a remainder of \( 9 \).
Thus, \( 4319 \div 10 = 431 \) with a remainder of 9.
Answer: \( 431 \text{ R } 9 \)
---
Problem 15: \( 8 \div 7146 \)
Solution:
1. Divide 7146 by 8.
2. Perform long division:
- 8 goes into 71 (the first two digits) 8 times (since \( 8 \times 8 = 64 \)).
- Subtract \( 64 \) from \( 71 \) to get a remainder of \( 7 \).
- Bring down the next digit (4), making it 74.
- 8 goes into 74 nine times (since \( 8 \times 9 = 72 \)).
- Subtract \( 72 \) from \( 74 \) to get a remainder of \( 2 \).
- Bring down the next digit (6), making it 26.
- 8 goes into 26 three times (since \( 8 \times 3 = 24 \)).
- Subtract \( 24 \) from \( 26 \) to get a remainder of \( 2 \).
Thus, \( 7146 \div 8 = 893 \) with a remainder of 2.
Answer: \( 893 \text{ R } 2 \)
---
Final Answers:
\[
\boxed{
\begin{aligned}
1. & \ 42 \text{ R } 4 \\
2. & \ 749 \text{ R } 4 \\
3. & \ 85 \text{ R } 4 \\
4. & \ 588 \text{ R } 1 \\
5. & \ 84 \text{ R } 2 \\
6. & \ 578 \text{ R } 4 \\
7. & \ 411 \text{ R } 4 \\
8. & \ 895 \text{ R } 1 \\
9. & \ 829 \text{ R } 2 \\
10. & \ 771 \text{ R } 1 \\
11. & \ 415 \text{ R } 1 \\
12. & \ 471 \text{ R } 4 \\
13. & \ 743 \text{ R } 4 \\
14. & \ 431 \text{ R } 9 \\
15. & \ 893 \text{ R } 2 \\
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of division worksheets.
