Let’s solve this step by step.
We’re working with fruit fly genetics. The worksheet gives us three traits: Body Color, Eye Color, and Wing Type. For each trait, there’s a dominant allele (capital letter) and a recessive allele (lowercase letter):
- Body Color: B (dominant), b (recessive)
- Eye Color: E (dominant), e (recessive)
- Wing Type: W (dominant), w (recessive)
The “First Generation” section shows Punnett squares for each trait. Each square has parents that are both heterozygous — meaning they have one dominant and one recessive allele. So:
- Body Color parent genotypes: Bb × Bb
- Eye Color parent genotypes: Ee × Ee
- Wing Type parent genotypes: Ww × Ww
We need to fill in the Punnett squares first, then calculate the predicted percentages for each genotype type (heterozygous, homozygous dominant, homozygous recessive).
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Step 1: Fill in the Punnett Squares
For any trait where both parents are heterozygous (like Bb × Bb), the Punnett square looks like this:
Parent 1 gametes on top: B and b
Parent 2 gametes on side: B and b
So the four boxes are:
Top-left: B from mom + B from dad → BB
Top-right: B from mom + b from dad → Bb
Bottom-left: b from mom + B from dad → Bb
Bottom-right: b from mom + b from dad → bb
Same pattern applies to all three traits since they’re all set up the same way.
So for each trait:
- Homozygous Dominant (BB, EE, WW): 1 out of 4 = 25%
- Heterozygous (Bb, Ee, Ww): 2 out of 4 = 50%
- Homozygous Recessive (bb, ee, ww): 1 out of 4 = 25%
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Step 2: Fill in Predicted Results Table
Now we plug those percentages into the table under “Predicted Results”.
For
Body:
- Heterozygous Ff → 50%
- Homozygous Dominant FF → 25%
- Homozygous Recessive ff → 25%
Same for
Eyes and
Wings, because all three crosses are identical in setup.
So every column gets:
- Heterozygous: 50%
- Homozygous Dominant: 25%
- Homozygous Recessive: 25%
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Step 3: Real Results Section
This part is meant for actual experimental data — you’d count real flies and record how many fall into each category. Since no real data is given here, we leave it blank or write “N/A” if required. But since the question doesn’t give numbers, we just note that this section is for observed results, not calculated ones.
But wait — looking back at the worksheet, the “Real Results” table has empty cells. Since we don’t have any real fly counts, we can’t fill them in. So we’ll only complete the “Predicted Results” section as asked.
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✔ Final Check:
Each Punnett square for a heterozygous cross (Aa x Aa) always gives:
- 25% AA
- 50% Aa
- 25% aa
That’s standard Mendelian inheritance for a monohybrid cross.
All three traits follow this rule.
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Final Answer:
Predicted Results Table:
| Genotype | Body | Eyes | Wings |
|-----------------------|------|------|-------|
| Heterozygous Ff | 50% | 50% | 50% |
| Homozygous Dominant FF| 25% | 25% | 25% |
| Homozygous Recessive ff| 25% | 25% | 25% |
(Leave “Real Results” table blank unless actual data is provided.)
Parent Tip: Review the logic above to help your child master the concept of dominant and recessive worksheet.