Dot Plots Practice worksheet with exercises on interpreting data from dot plots and line plots, including eye color and basketball team height analysis.

Problem Analysis and Solution

The worksheet contains several tasks involving dot plots and line plots. Let's solve each part step by step.

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#### Part 1: Dot Plot Practice (Eye Colors)

The dot plot shows the distribution of eye colors in Mr. Yang's class. Here is the data from the dot plot:

- Brown: 5 students
- Blue: 6 students
- Green: 6 students
- Hazel: 2 students

Total number of students = \( 5 + 6 + 6 + 2 = 19 \)

##### Question 1: What percentage of the class has brown eyes?

- Number of students with brown eyes = 5
- Total number of students = 19
- Percentage = \( \left( \frac{\text{Number of students with brown eyes}}{\text{Total number of students}} \right) \times 100 \)
- Percentage = \( \left( \frac{5}{19} \right) \times 100 \approx 26.32\% \)

Answer: \( \boxed{26.32\%} \)

##### Question 2: How many students have blue eyes?

- From the dot plot, the number of students with blue eyes = 6

Answer: \( \boxed{6} \)

##### Question 3: What percentage of the students do not have hazel eyes?

- Number of students with hazel eyes = 2
- Number of students without hazel eyes = Total students - Students with hazel eyes = \( 19 - 2 = 17 \)
- Percentage = \( \left( \frac{\text{Number of students without hazel eyes}}{\text{Total number of students}} \right) \times 100 \)
- Percentage = \( \left( \frac{17}{19} \right) \times 100 \approx 89.47\% \)

Answer: \( \boxed{89.47\%} \)

##### Question 4: How many students have either brown or blue eyes?

- Number of students with brown eyes = 5
- Number of students with blue eyes = 6
- Total students with brown or blue eyes = \( 5 + 6 = 11 \)

Answer: \( \boxed{11} \)

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#### Part 2: Line Plot Practice (Basketball Team Heights)

The line plot shows the heights of boys on a basketball team. Here is the data from the line plot:

- 5'0": 1 boy
- 5'2": 2 boys
- 5'4": 3 boys
- 5'6": 4 boys
- 5'8": 4 boys
- 5'10": 2 boys
- 6'0": 2 boys

Total number of boys = \( 1 + 2 + 3 + 4 + 4 + 2 + 2 = 18 \)

##### Question 5: Assuming every team member was measured, how many boys are on the basketball team?

- Total number of boys = 18

Answer: \( \boxed{18} \)

##### Question 6: What percentage of the team is taller than 5'7"?

- Heights taller than 5'7": 5'8", 5'10", and 6'0"
- Number of boys taller than 5'7":
- 5'8": 4 boys
- 5'10": 2 boys
- 6'0": 2 boys
- Total = \( 4 + 2 + 2 = 8 \)
- Percentage = \( \left( \frac{\text{Number of boys taller than 5'7"}}{\text{Total number of boys}} \right) \times 100 \)
- Percentage = \( \left( \frac{8}{18} \right) \times 100 \approx 44.44\% \)

Answer: \( \boxed{44.44\%} \)

##### Question 7: How many boys are 5'4" or shorter?

- Heights 5'4" or shorter: 5'0", 5'2", and 5'4"
- Number of boys:
- 5'0": 1 boy
- 5'2": 2 boys
- 5'4": 3 boys
- Total = \( 1 + 2 + 3 = 6 \)

Answer: \( \boxed{6} \)

##### Question 8: Are there any outliers? If so, what?

- An outlier is a value that is significantly different from other values in the dataset.
- In this case, all heights are relatively close to each other, and there are no extreme values.
- Conclusion: There are no outliers.

Answer: \( \boxed{\text{No outliers}} \)

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#### Part 3: Create a Dot Plot

The data given is the number of minutes people spend exercising per day, rounded to the nearest 5-minute increment:

- Data: 0, 10, 25, 10, 0, 30, 15, 20, 10, 30, 30, 30, 25, 15

##### Step 1: Organize the data into intervals
- Intervals: 0, 5, 10, 15, 20, 25, 30
- Frequency:
- 0: 2
- 5: 0
- 10: 3
- 15: 2
- 20: 1
- 25: 2
- 30: 4

##### Step 2: Create the dot plot

```
Minutes | Dots
-----------------
0 | XX
5 |
10 | XXX
15 | XX
20 | X
25 | XX
30 | XXXX
```

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#### Part 4: Real-Life Application

This part requires surveying classmates about the number of siblings they have and creating a line plot. Since this is an open-ended task, the solution will depend on the actual data collected. Here is a general approach:

1. Collect data from at least 10 classmates.
2. Organize the data into a frequency table.
3. Create a line plot based on the frequency table.

For example, if the data collected is: 0, 1, 2, 1, 0, 3, 2, 1, 0, 2:

- Frequency:
- 0: 3
- 1: 3
- 2: 3
- 3: 1

- Line plot:
```
Siblings | Dots
-----------------
0 | ***
1 | ***
2 | ***
3 | *
```

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Final Answers Summarized

1. \( \boxed{26.32\%} \)
2. \( \boxed{6} \)
3. \( \boxed{89.47\%} \)
4. \( \boxed{11} \)
5. \( \boxed{18} \)
6. \( \boxed{44.44\%} \)
7. \( \boxed{6} \)
8. \( \boxed{\text{No outliers}} \)

Boxed Final Answer for Dot Plot Creation:
```
Minutes | Dots
-----------------
0 | XX
5 |
10 | XXX
15 | XX
20 | X
25 | XX
30 | XXXX
```

Boxed Final Answer for Real-Life Application:
Depends on collected data. Provide a similar structured response based on actual data.