Dot plot worksheets for analyzing student data on shoe sizes and sock day participation.

Here are the step-by-step solutions for the problems on your worksheet.

Problem 1: Dot Plot of Pets

a) How many students were surveyed?
To find this, count every dot on the number line. Each dot represents one student.
* At 0 pets: 2 dots
* At 2 pets: 4 dots
* At 3 pets: 1 dot
* At 4 pets: 2 dots
* At 5 pets: 1 dot
* At 6 pets: 1 dot
* At 7 pets: 1 dot
* At 8 pets: 1 dot
* At 9 pets: 1 dot
Total: $2 + 4 + 1 + 2 + 1 + 1 + 1 + 1 + 1 = 14$
Answer: 14 students

b) Is there an outlier? If so, what is it?
An outlier is a number that is far away from the rest of the data. Most students have between 0 and 5 pets. The numbers 6, 7, 8, and 9 are separated from the main group. Usually, in these simple plots, the furthest point is considered the outlier.
Answer: Yes, 9 is an outlier. (Note: Depending on your teacher's strictness, 6, 7, and 8 could also be considered outliers because they don't touch the main cluster at 0-5).

c) How many of the people surveyed own more than 4 pairs of shoes?
*Correction:* The question asks about "pairs of shoes," but the graph title says "pets." Assuming this is a typo and it means "more than 4 pets":
Look at the numbers greater than 4 on the number line: 5, 6, 7, 8, and 9.
* At 5: 1 student
* At 6: 1 student
* At 7: 1 student
* At 8: 1 student
* At 9: 1 student
Total: $1 + 1 + 1 + 1 + 1 = 5$
Answer: 5 people

d) What is the mode of the data?
The mode is the number with the most dots (the highest stack).
The tallest stack is at the number 2, which has 4 dots.
Answer: 2

e) What is the median of the data?
The median is the middle number. Since there are 14 students (an even number), we need to find the average of the 7th and 8th student when lined up in order.
Let's list them out:
0, 0, 2, 2, 2, 2, 2, 3, 4, 4, 5, 6, 7, 8, 9
Wait, let me recount the list carefully based on the dots:
Values: 0, 0, 2, 2, 2, 2, 3, 4, 4, 5, 6, 7, 8, 9
There are 14 values.
The 7th value is 3.
The 8th value is 4.
To find the median of an even set, add them and divide by 2: $(3 + 4) / 2 = 3.5$.
Answer: 3.5

f) What is the mean of the data?
The mean is the average. Add all the values together and divide by the total number of students (14).
Sum: $(0\times2) + (2\times4) + (3\times1) + (4\times2) + (5\times1) + (6\times1) + (7\times1) + (8\times1) + (9\times1)$
Sum: $0 + 8 + 3 + 8 + 5 + 6 + 7 + 8 + 9 = 54$
Mean: $54 / 14 \approx 3.86$
Answer: Approximately 3.86 (or $27/7$)

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Problem 2: Dot Plot of Coby Sox Day Participation

a) Which teacher had the least participation for Coby Sox Day?
Look for the teacher with the shortest stack of dots.
* Pogue: 2 dots
* Prine: 1 dot
* Mann: 5 dots
* Yang: 5 dots
* Bagby: 2 dots
* Greenwood: 1 dot
Both Prine and Greenwood have only 1 dot.
Answer: Prine and Greenwood (tie)

b) How many students participated in Mrs. Prine's class?
Count the dots above "Prine". There is only 1 dot.
Answer: 1 student

c) How many teachers participated in Coby Sox Day? (How many classes like Ms. Nguyen's class?)
Count how many different teacher names are listed on the bottom axis.
Names: Pogue, Prine, Mann, Yang, Bagby, Greenwood.
Answer: 6 teachers

d) How many total students participated in Coby Sox Day?
Add up all the dots for every teacher.
* Pogue: 2
* Prine: 1
* Mann: 5
* Yang: 5
* Bagby: 2
* Greenwood: 1
Total: $2 + 1 + 5 + 5 + 2 + 1 = 16$
Answer: 16 students

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Final Answer:

1. Pet Ownership Data
a) 14 students
b) Yes, 9 (and potentially 6, 7, 8)
c) 5 people
d) 2
e) 3.5
f) ~3.86

2. Coby Sox Day Participation
a) Prine and Greenwood
b) 1 student
c) 6 teachers
d) 16 students