Balanced equations worksheets | TPT - Free Printable
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Step-by-step solution for: Balanced equations worksheets | TPT
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Show Answer Key & Explanations
Step-by-step solution for: Balanced equations worksheets | TPT
To balance chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how to solve each equation step by step:
---
- Reactants: 2 H atoms, 2 O atoms
- Products: 2 H atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to get 2 O atoms on the product side.
- The balanced equation is:
\[
\boxed{2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}}
\]
---
- Reactants: 2 H atoms, 2 O atoms
- Products: 2 H atoms, 3 O atoms (2 from \( \text{O}_2 \) and 1 from \( \text{H}_2\text{O} \))
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to get 4 O atoms on the product side.
- Adjust the coefficients to balance all elements.
- The balanced equation is:
\[
\boxed{2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2}
\]
---
- Reactants: 1 Na atom, 2 O atoms
- Products: 2 Na atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{Na} \) to balance Na atoms.
- Add a coefficient of 2 in front of \( \text{Na}_2\text{O} \) to balance O atoms.
- The balanced equation is:
\[
\boxed{4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O}}
\]
---
- Reactants: 2 N atoms, 2 H atoms
- Products: 1 N atom, 3 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{NH}_3 \) to balance N atoms.
- Adjust the coefficients to balance H atoms.
- The balanced equation is:
\[
\boxed{\text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3}
\]
---
- Reactants: 4 P atoms, 2 O atoms
- Products: 4 P atoms, 10 O atoms
To balance:
- Add a coefficient of 5 in front of \( \text{O}_2 \) to balance O atoms.
- The balanced equation is:
\[
\boxed{\text{P}_4 + 5 \text{O}_2 \rightarrow \text{P}_4\text{O}_{10}}
\]
---
- Reactants: 1 Fe atom, 2 H atoms, 1 O atom
- Products: 3 Fe atoms, 4 O atoms, 2 H atoms
To balance:
- Add a coefficient of 3 in front of \( \text{Fe} \) to balance Fe atoms.
- Add a coefficient of 4 in front of \( \text{H}_2\text{O} \) to balance O atoms.
- Adjust the coefficients to balance H atoms.
- The balanced equation is:
\[
\boxed{3 \text{Fe} + 4 \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4 \text{H}_2}
\]
---
- Reactants: 1 C atom, 2 H atoms
- Products: 1 C atom, 4 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2 \) to balance H atoms.
- The balanced equation is:
\[
\boxed{\text{C} + 2 \text{H}_2 \rightarrow \text{CH}_4}
\]
---
- Reactants: 2 Na atoms, 1 S atom, 4 O atoms, 1 Ca atom, 2 Cl atoms
- Products: 1 Ca atom, 1 S atom, 4 O atoms, 1 Na atom, 1 Cl atom
To balance:
- Add a coefficient of 2 in front of \( \text{NaCl} \) to balance Na and Cl atoms.
- The balanced equation is:
\[
\boxed{\text{Na}_2\text{SO}_4 + \text{CaCl}_2 \rightarrow \text{CaSO}_4 + 2 \text{NaCl}}
\]
---
- Reactants: 2 C atoms, 6 H atoms, 2 O atoms
- Products: 2 C atoms, 2 O atoms, 6 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{CO}_2 \) to balance C atoms.
- Add a coefficient of 3 in front of \( \text{H}_2\text{O} \) to balance H atoms.
- Adjust the coefficients to balance O atoms.
- The balanced equation is:
\[
\boxed{2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O}}
\]
---
- Reactants: 2 Al atoms, 3 O atoms
- Products: 1 Al atom, 2 O atoms
To balance:
- Add a coefficient of 2 in front of \( \text{Al} \) to balance Al atoms.
- Add a coefficient of \( \frac{3}{2} \) or 3/2 in front of \( \text{O}_2 \) to balance O atoms. Multiply through by 2 to remove the fraction.
- The balanced equation is:
\[
\boxed{2 \text{Al}_2\text{O}_3 \rightarrow 4 \text{Al} + 3 \text{O}_2}
\]
---
- Reactants: 4 C atoms, 12 H atoms, 1 O atom
- Products: 2 C atoms, 6 H atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{C}_2\text{H}_5\text{OH} \) to balance C atoms.
- Adjust the coefficients to balance H and O atoms.
- The balanced equation is:
\[
\boxed{\text{C}_4\text{H}_{10} + \text{H}_2\text{O} \rightarrow 2 \text{C}_2\text{H}_5\text{OH}}
\]
---
- Reactants: 2 C atoms, 4 H atoms, 2 O atoms
- Products: 2 C atoms, 2 O atoms, 4 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{CO}_2 \) to balance C atoms.
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to balance H atoms.
- Adjust the coefficients to balance O atoms.
- The balanced equation is:
\[
\boxed{\text{C}_2\text{H}_4 + 3 \text{O}_2 \rightarrow 2 \text{CO}_2 + 2 \text{H}_2\text{O}}
\]
---
\[
\boxed{
\begin{aligned}
1. & \quad 2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O} \\
2. & \quad 2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2 \\
3. & \quad 4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O} \\
4. & \quad \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \\
5. & \quad \text{P}_4 + 5 \text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \\
6. & \quad 3 \text{Fe} + 4 \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4 \text{H}_2 \\
7. & \quad \text{C} + 2 \text{H}_2 \rightarrow \text{CH}_4 \\
8. & \quad \text{Na}_2\text{SO}_4 + \text{CaCl}_2 \rightarrow \text{CaSO}_4 + 2 \text{NaCl} \\
9. & \quad 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} \\
10. & \quad 2 \text{Al}_2\text{O}_3 \rightarrow 4 \text{Al} + 3 \text{O}_2 \\
11. & \quad \text{C}_4\text{H}_{10} + \text{H}_2\text{O} \rightarrow 2 \text{C}_2\text{H}_5\text{OH} \\
12. & \quad \text{C}_2\text{H}_4 + 3 \text{O}_2 \rightarrow 2 \text{CO}_2 + 2 \text{H}_2\text{O}
\end{aligned}
}
\]
---
1. \( \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} \)
- Reactants: 2 H atoms, 2 O atoms
- Products: 2 H atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to get 2 O atoms on the product side.
- The balanced equation is:
\[
\boxed{2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O}}
\]
---
2. \( \text{H}_2\text{O}_2 \rightarrow \text{H}_2\text{O} + \text{O}_2 \)
- Reactants: 2 H atoms, 2 O atoms
- Products: 2 H atoms, 3 O atoms (2 from \( \text{O}_2 \) and 1 from \( \text{H}_2\text{O} \))
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to get 4 O atoms on the product side.
- Adjust the coefficients to balance all elements.
- The balanced equation is:
\[
\boxed{2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2}
\]
---
3. \( \text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O} \)
- Reactants: 1 Na atom, 2 O atoms
- Products: 2 Na atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{Na} \) to balance Na atoms.
- Add a coefficient of 2 in front of \( \text{Na}_2\text{O} \) to balance O atoms.
- The balanced equation is:
\[
\boxed{4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O}}
\]
---
4. \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \)
- Reactants: 2 N atoms, 2 H atoms
- Products: 1 N atom, 3 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{NH}_3 \) to balance N atoms.
- Adjust the coefficients to balance H atoms.
- The balanced equation is:
\[
\boxed{\text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3}
\]
---
5. \( \text{P}_4 + \text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \)
- Reactants: 4 P atoms, 2 O atoms
- Products: 4 P atoms, 10 O atoms
To balance:
- Add a coefficient of 5 in front of \( \text{O}_2 \) to balance O atoms.
- The balanced equation is:
\[
\boxed{\text{P}_4 + 5 \text{O}_2 \rightarrow \text{P}_4\text{O}_{10}}
\]
---
6. \( \text{Fe} + \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + \text{H}_2 \)
- Reactants: 1 Fe atom, 2 H atoms, 1 O atom
- Products: 3 Fe atoms, 4 O atoms, 2 H atoms
To balance:
- Add a coefficient of 3 in front of \( \text{Fe} \) to balance Fe atoms.
- Add a coefficient of 4 in front of \( \text{H}_2\text{O} \) to balance O atoms.
- Adjust the coefficients to balance H atoms.
- The balanced equation is:
\[
\boxed{3 \text{Fe} + 4 \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4 \text{H}_2}
\]
---
7. \( \text{C} + \text{H}_2 \rightarrow \text{CH}_4 \)
- Reactants: 1 C atom, 2 H atoms
- Products: 1 C atom, 4 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{H}_2 \) to balance H atoms.
- The balanced equation is:
\[
\boxed{\text{C} + 2 \text{H}_2 \rightarrow \text{CH}_4}
\]
---
8. \( \text{Na}_2\text{SO}_4 + \text{CaCl}_2 \rightarrow \text{CaSO}_4 + \text{NaCl} \)
- Reactants: 2 Na atoms, 1 S atom, 4 O atoms, 1 Ca atom, 2 Cl atoms
- Products: 1 Ca atom, 1 S atom, 4 O atoms, 1 Na atom, 1 Cl atom
To balance:
- Add a coefficient of 2 in front of \( \text{NaCl} \) to balance Na and Cl atoms.
- The balanced equation is:
\[
\boxed{\text{Na}_2\text{SO}_4 + \text{CaCl}_2 \rightarrow \text{CaSO}_4 + 2 \text{NaCl}}
\]
---
9. \( \text{C}_2\text{H}_6 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)
- Reactants: 2 C atoms, 6 H atoms, 2 O atoms
- Products: 2 C atoms, 2 O atoms, 6 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{CO}_2 \) to balance C atoms.
- Add a coefficient of 3 in front of \( \text{H}_2\text{O} \) to balance H atoms.
- Adjust the coefficients to balance O atoms.
- The balanced equation is:
\[
\boxed{2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O}}
\]
---
10. \( \text{Al}_2\text{O}_3 \rightarrow \text{Al} + \text{O}_2 \)
- Reactants: 2 Al atoms, 3 O atoms
- Products: 1 Al atom, 2 O atoms
To balance:
- Add a coefficient of 2 in front of \( \text{Al} \) to balance Al atoms.
- Add a coefficient of \( \frac{3}{2} \) or 3/2 in front of \( \text{O}_2 \) to balance O atoms. Multiply through by 2 to remove the fraction.
- The balanced equation is:
\[
\boxed{2 \text{Al}_2\text{O}_3 \rightarrow 4 \text{Al} + 3 \text{O}_2}
\]
---
11. \( \text{C}_4\text{H}_{10} + \text{H}_2\text{O} \rightarrow \text{C}_2\text{H}_5\text{OH} \)
- Reactants: 4 C atoms, 12 H atoms, 1 O atom
- Products: 2 C atoms, 6 H atoms, 1 O atom
To balance:
- Add a coefficient of 2 in front of \( \text{C}_2\text{H}_5\text{OH} \) to balance C atoms.
- Adjust the coefficients to balance H and O atoms.
- The balanced equation is:
\[
\boxed{\text{C}_4\text{H}_{10} + \text{H}_2\text{O} \rightarrow 2 \text{C}_2\text{H}_5\text{OH}}
\]
---
12. \( \text{C}_2\text{H}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)
- Reactants: 2 C atoms, 4 H atoms, 2 O atoms
- Products: 2 C atoms, 2 O atoms, 4 H atoms
To balance:
- Add a coefficient of 2 in front of \( \text{CO}_2 \) to balance C atoms.
- Add a coefficient of 2 in front of \( \text{H}_2\text{O} \) to balance H atoms.
- Adjust the coefficients to balance O atoms.
- The balanced equation is:
\[
\boxed{\text{C}_2\text{H}_4 + 3 \text{O}_2 \rightarrow 2 \text{CO}_2 + 2 \text{H}_2\text{O}}
\]
---
Final Answer:
\[
\boxed{
\begin{aligned}
1. & \quad 2 \text{H}_2 + \text{O}_2 \rightarrow 2 \text{H}_2\text{O} \\
2. & \quad 2 \text{H}_2\text{O}_2 \rightarrow 2 \text{H}_2\text{O} + \text{O}_2 \\
3. & \quad 4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O} \\
4. & \quad \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \\
5. & \quad \text{P}_4 + 5 \text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \\
6. & \quad 3 \text{Fe} + 4 \text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4 \text{H}_2 \\
7. & \quad \text{C} + 2 \text{H}_2 \rightarrow \text{CH}_4 \\
8. & \quad \text{Na}_2\text{SO}_4 + \text{CaCl}_2 \rightarrow \text{CaSO}_4 + 2 \text{NaCl} \\
9. & \quad 2 \text{C}_2\text{H}_6 + 7 \text{O}_2 \rightarrow 4 \text{CO}_2 + 6 \text{H}_2\text{O} \\
10. & \quad 2 \text{Al}_2\text{O}_3 \rightarrow 4 \text{Al} + 3 \text{O}_2 \\
11. & \quad \text{C}_4\text{H}_{10} + \text{H}_2\text{O} \rightarrow 2 \text{C}_2\text{H}_5\text{OH} \\
12. & \quad \text{C}_2\text{H}_4 + 3 \text{O}_2 \rightarrow 2 \text{CO}_2 + 2 \text{H}_2\text{O}
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of easy balancing equations worksheet.