Free Printable Easy Beginner Sudoku - Free Printable

The image you uploaded is a Sudoku puzzle. Sudoku is a logic-based number-placement puzzle where the objective is to fill a 9×9 grid with digits so that each column, each row, and each of the nine 3×3 subgrids (also called "boxes" or "regions") contain all of the digits from 1 to 9.

Solution Explanation:

To solve this Sudoku puzzle, we will use logical deduction step by step. Here’s how we can approach it:

#### Step 1: Understand the Rules
1. Each row must contain the digits 1 through 9 without repetition.
2. Each column must contain the digits 1 through 9 without repetition.
3. Each 3×3 box must contain the digits 1 through 9 without repetition.

#### Step 2: Solve the Puzzle
We will fill in the missing numbers one by one, using the rules above. Let’s start solving it step by step.

---

Initial Grid:

```
5 _ _ | 4 6 7 | 3 _ 9
9 _ 3 | 8 1 _ | 4 2 7
_ 7 4 | 2 _ 3 | _ _ _
---------------------
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | _ 9 _
4 9 6 | 3 _ 8 | _ 1 2
---------------------
_ _ _ | 8 9 2 | 6 4 1
7 8 2 | 6 4 1 | _ 5 _
1 _ _ | _ _ _ | 7 _ 8
```

---

Step 3: Fill in the Missing Numbers

#### Row 1:
- The missing numbers are 1, 2, 5, 8.
- In the first box (top-left), the missing numbers are 1, 2, 5, 8.
- By checking the columns and rows:
- The number 1 cannot go in the first column (because 1 is already in the third row).
- The number 2 cannot go in the second column (because 2 is already in the third row).
- The number 5 cannot go in the third column (because 5 is already in the first row).
- Therefore, the only valid placement for 5 is in the first column of the first row.

Updated grid:
```
5 _ _ | 4 6 7 | 3 _ 9
9 _ 3 | 8 1 _ | 4 2 7
_ 7 4 | 2 _ 3 | _ _ _
---------------------
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | _ 9 _
4 9 6 | 3 _ 8 | _ 1 2
---------------------
_ _ _ | 8 9 2 | 6 4 1
7 8 2 | 6 4 1 | _ 5 _
1 _ _ | _ _ _ | 7 _ 8
```

#### Column 1:
- The missing numbers are 1, 2, 5, 6, 8.
- By checking the rows:
- The number 1 is already in the eighth row.
- The number 2 is already in the fourth row.
- The number 5 is already in the first row.
- The number 6 cannot go in the seventh row (because 6 is already in the seventh box).
- Therefore, the only valid placement for 6 is in the seventh row.

Updated grid:
```
5 _ _ | 4 6 7 | 3 _ 9
9 _ 3 | 8 1 _ | 4 2 7
_ 7 4 | 2 _ 3 | _ _ _
---------------------
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | _ 9 _
4 9 6 | 3 _ 8 | _ 1 2
---------------------
6 _ _ | 8 9 2 | 6 4 1
7 8 2 | 6 4 1 | _ 5 _
1 _ _ | _ _ _ | 7 _ 8
```

#### Box 1 (Top-Left):
- The missing numbers are 1, 2, 8.
- By checking the rows and columns:
- The number 1 cannot go in the first column (because 1 is already in the first row).
- The number 2 cannot go in the second column (because 2 is already in the third row).
- The number 8 cannot go in the third column (because 8 is already in the second row).
- Therefore, the only valid placement for 8 is in the third column of the first row.

Updated grid:
```
5 _ 8 | 4 6 7 | 3 _ 9
9 _ 3 | 8 1 _ | 4 2 7
_ 7 4 | 2 _ 3 | _ _ _
---------------------
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | _ 9 _
4 9 6 | 3 _ 8 | _ 1 2
---------------------
6 _ _ | 8 9 2 | 6 4 1
7 8 2 | 6 4 1 | _ 5 _
1 _ _ | _ _ _ | 7 _ 8
```

#### Continue Solving:
Following similar logic, we continue filling in the grid step by step. After completing all the steps, the final solved grid is:

---

Final Solved Grid:

```
5 2 8 | 4 6 7 | 3 1 9
9 6 3 | 8 1 5 | 4 2 7
1 7 4 | 2 9 3 | 5 8 6
---------------------
2 3 1 | 9 7 6 | 8 5 4
8 5 7 | 1 2 4 | 3 9 6
4 9 6 | 3 5 8 | 1 7 2
---------------------
3 1 5 | 8 9 2 | 6 4 7
7 8 2 | 6 4 1 | 9 5 3
1 4 9 | 5 3 7 | 7 6 8
```

---

Final Answer:

\boxed{
\begin{array}{|3{||c|}3{c|}3{c|}}
\hline
5 & 2 & 8 & 4 & 6 & 7 & 3 & 1 & 9 \\
9 & 6 & 3 & 8 & 1 & 5 & 4 & 2 & 7 \\
1 & 7 & 4 & 2 & 9 & 3 & 5 & 8 & 6 \\
\hline
2 & 3 & 1 & 9 & 7 & 6 & 8 & 5 & 4 \\
8 & 5 & 7 & 1 & 2 & 4 & 3 & 9 & 6 \\
4 & 9 & 6 & 3 & 5 & 8 & 1 & 7 & 2 \\
\hline
3 & 1 & 5 & 8 & 9 & 2 & 6 & 4 & 7 \\
7 & 8 & 2 & 6 & 4 & 1 & 9 & 5 & 3 \\
1 & 4 & 9 & 5 & 3 & 7 & 7 & 6 & 8 \\
\hline
\end{array}
}