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End Behavior Practice.pdf - Name: Period: Dalise Chhe Date: 3 ... - Free Printable

End Behavior Practice.pdf - Name: Period: Dalise Chhe Date: 3 ...

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Show Answer Key & Explanations Step-by-step solution for: End Behavior Practice.pdf - Name: Period: Dalise Chhe Date: 3 ...
It looks like you've uploaded an image containing a math problem related to graphing polynomial functions, specifically focusing on identifying the correct graph based on given characteristics of the function.

Since I can't view images directly, I’ll need you to describe the content of the image or provide the text and details of the problem. However, based on your description and typical structure of such problems, here’s how we can approach it:

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Common Type of Problem:


You're likely given a polynomial function (e.g., in factored form) and asked to match it with its correct graph from several options.

For example:
> Given:
> $ f(x) = (x + 2)(x - 1)^2 $

And four graphs labeled A, B, C, D — choose the one that matches this function.

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Steps to Solve:



1. Determine the Degree and Leading Coefficient:
- The degree tells us the general shape (odd/even degree).
- The leading coefficient determines end behavior.

2. Find the Zeros (x-intercepts):
- Factor the polynomial.
- Use multiplicity to determine how the graph behaves at each zero:
- Odd multiplicity: crosses the x-axis.
- Even multiplicity: touches and turns around.

3. Analyze End Behavior:
- If degree is even:
- Positive leading coefficient → both ends go up.
- Negative → both ends go down.
- If degree is odd:
- Positive → left down, right up.
- Negative → left up, right down.

4. Look for Turning Points:
- A polynomial of degree $ n $ has at most $ n-1 $ turning points.

5. Match Graph Features:
- Check zeros and their multiplicities.
- Confirm end behavior.
- Look for symmetry (if applicable).

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Example Walkthrough:



Suppose the function is:
$$
f(x) = (x + 2)(x - 1)^2
$$

- Zeros: $ x = -2 $ (multiplicity 1), $ x = 1 $ (multiplicity 2)
- At $ x = -2 $: crosses x-axis.
- At $ x = 1 $: touches and turns (even multiplicity).
- Degree: 3 → odd → end behavior: left down, right up.
- Leading term: $ x^3 $ → positive coefficient → left down, right up.

Now look for a graph that:
- Crosses at $ x = -2 $
- Touches and turns at $ x = 1 $
- Goes down on the left, up on the right

That would be the correct graph.

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Please describe the function(s) and the graphs shown in your image (or type out the problem), and I’ll help you solve it step by step!
Parent Tip: Review the logic above to help your child master the concept of end behavior worksheet.
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