Math practice worksheet with problems on rounding, multiplication, and number forms.
A math worksheet with various exercises including rounding numbers, comparing values, multiplication, identifying factors, writing numbers in expanded form, and solving word problems, decorated with a banner of flags at the top.
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Show Answer Key & Explanations
Step-by-step solution for: 4th Grade End-of-the-Year Math Review | Math review, 4th grade ...
▼
Show Answer Key & Explanations
Step-by-step solution for: 4th Grade End-of-the-Year Math Review | Math review, 4th grade ...
Let’s go through each problem one by one, step by step. I’ll solve them carefully and check my work as I go.
---
1) Give the place value of the 6 in 12,045.
Wait — look at the number: 12,045.
Digits: 1 (ten thousands), 2 (thousands), 0 (hundreds), 4 (tens), 5 (ones).
There is no 6 in 12,045!
This might be a typo. Maybe it was meant to be 12,645? Let’s assume that for now, since otherwise the question doesn’t make sense.
If the number is 12,645, then:
- 1 → ten thousands
- 2 → thousands
- 6 → hundreds
- 4 → tens
- 5 → ones
✔ So if it’s 12,645, the 6 is in the hundreds place.
But wait — let me double-check the original image description. The user wrote “12,045” — but maybe it’s actually “12,645”? Since there’s no 6 in 12,045, this must be an error. In many worksheets, numbers like this are common. I’ll proceed assuming it’s 12,645.
→ Place value of 6 = hundreds
---
2) Round 3,734 to the nearest thousand.
Look at the thousands digit: 3 (in 3,734)
Next digit (hundreds place): 7
Since 7 ≥ 5, we round up.
So 3,734 → rounds to 4,000
✔ Correct.
---
3) Compare: 6451 ___ 6332
Compare digit by digit from left:
- Thousands: both 6 → same
- Hundreds: 4 vs 3 → 4 > 3
So 6451 > 6332
✔ Answer: >
---
4) Circle one: Prime or Composite 55
Prime = only divisible by 1 and itself
Composite = has more than two factors
55 ÷ 5 = 11 → so 5 × 11 = 55 → has factors other than 1 and 55 → composite
✔ Circle: Composite
---
5) 85,883 + 72,345
Add:
```
85,883
+ 72,345
--------
```
Start from right:
3 + 5 = 8
8 + 4 = 12 → write 2, carry 1
8 + 3 + 1 = 12 → write 2, carry 1
5 + 2 + 1 = 8
8 + 7 = 15 → write 15
So: 158,228
Check with calculator-style:
85,883 + 72,345 =
85,000 + 72,000 = 157,000
883 + 345 = 1,228
Total: 157,000 + 1,228 = 158,228
✔ Correct.
---
6) 92,948 - 46,643
Subtract:
```
92,948
- 46,643
--------
```
8 - 3 = 5
4 - 4 = 0
9 - 6 = 3
2 - 6 → can’t do → borrow from 9 → becomes 12 - 6 = 6, and 9 becomes 8
8 - 4 = 4
Wait — let’s do it properly:
Thousands column: 2 - 6 → need to borrow.
Actually:
Write it out:
92,948
- 46,643
= ?
From right:
8 - 3 = 5
4 - 4 = 0
9 - 6 = 3
2 - 6 → can’t → borrow from 9 (ten-thousands)
So 9 becomes 8, and 2 becomes 12 → 12 - 6 = 6
Then 8 - 4 = 4
So result: 46,305
Check: 46,643 + 46,305 = ?
46,643 + 46,305 =
46,000 + 46,000 = 92,000
643 + 305 = 948
Total: 92,948 ✔
✔ Correct: 46,305
---
7) Solve for the rule and finish the pattern: 12, 24, 36, 48, ___, ___
Each number increases by 12.
12 + 12 = 24
24 + 12 = 36
36 + 12 = 48
48 + 12 = 60
60 + 12 = 72
Rule: Add 12
✔ Next two: 60, 72
---
8) Give the first four multiples for 6.
Multiples of 6: 6×1, 6×2, 6×3, 6×4
→ 6, 12, 18, 24
✔ First four: 6, 12, 18, 24
---
9) Give the factors for 36.
Factors = numbers that divide 36 evenly.
List pairs:
1 × 36
2 × 18
3 × 12
4 × 9
6 × 6
So all factors: 1, 2, 3, 4, 6, 9, 12, 18, 36
✔ List: 1, 2, 3, 4, 6, 9, 12, 18, 36
---
10) Multiply: 21 × 15
Break it down:
21 × 15 = 21 × (10 + 5) = (21×10) + (21×5) = 210 + 105 = 315
Or:
21
× 15
----
105 ← 21×5
+210 ← 21×10 (shifted)
----
315
✔ 315
---
11) 3,000 is ___ times as many as 30.
How many times does 30 go into 3,000?
3,000 ÷ 30 = ?
Divide: 3,000 ÷ 30 = 100
Because 30 × 100 = 3,000
✔ Answer: 100
---
12) Circle even or odd: 51
Even = ends in 0,2,4,6,8
Odd = ends in 1,3,5,7,9
51 ends in 1 → odd
✔ Circle: odd
---
13) Write 12,451 in:
a) Expanded Form:
Break by place value:
10,000 + 2,000 + 400 + 50 + 1
b) Word Form:
Twelve thousand, four hundred fifty-one
✔
Expanded: 10,000 + 2,000 + 400 + 50 + 1
Word: Twelve thousand, four hundred fifty-one
---
14) Multiply:
a) 71 × 10 = 710
b) 71 × 100 = 7,100
c) 71 × 1,000 = 71,000
(Just add zeros!)
✔ Answers:
710
7,100
71,000
---
15) Round 342 + 237 = ?
First, add: 342 + 237
342 + 200 = 542
542 + 37 = 579
Now, round 579 to nearest... what? The problem says “Round 342 + 237 =”, but doesn’t specify to what place.
Looking back at the worksheet format — probably expects rounding to nearest hundred? Or maybe just compute and leave? But it says “Round”.
In context of other problems, likely round to nearest hundred.
579 → nearest hundred: look at tens digit (7) → 7≥5 → round up → 600
Alternatively, maybe they want you to round each number first?
Sometimes “round then add”:
342 → 300
237 → 200
Sum: 500
But that’s less accurate.
The problem says “Round 342 + 237 =”, which probably means compute sum, then round.
I think safest is to compute sum = 579, then round to nearest hundred → 600
But let’s see — in some curricula, they teach to round before adding for estimation.
However, since it says “Round [sum]”, I’ll go with computing first.
✔ Final answer: 600 (rounded to nearest hundred)
---
16) What is the value of the 8 in 7,835?
Number: 7,835
Place values:
7 → thousands
8 → hundreds
3 → tens
5 → ones
So value of 8 is 800
✔ 800
---
Now, compiling all answers clearly:
---
Final Answer:
1) hundreds (assuming number is 12,645 — since 12,045 has no 6)
2) 4,000
3) >
4) Composite
5) 158,228
6) 46,305
7) Rule: Add 12; next numbers: 60, 72
8) 6, 12, 18, 24
9) 1, 2, 3, 4, 6, 9, 12, 18, 36
10) 315
11) 100
12) odd
13) Expanded: 10,000 + 2,000 + 400 + 50 + 1; Word: Twelve thousand, four hundred fifty-one
14) 710; 7,100; 71,000
15) 600 (after rounding 579 to nearest hundred)
16) 800
---
1) Give the place value of the 6 in 12,045.
Wait — look at the number: 12,045.
Digits: 1 (ten thousands), 2 (thousands), 0 (hundreds), 4 (tens), 5 (ones).
There is no 6 in 12,045!
This might be a typo. Maybe it was meant to be 12,645? Let’s assume that for now, since otherwise the question doesn’t make sense.
If the number is 12,645, then:
- 1 → ten thousands
- 2 → thousands
- 6 → hundreds
- 4 → tens
- 5 → ones
✔ So if it’s 12,645, the 6 is in the hundreds place.
But wait — let me double-check the original image description. The user wrote “12,045” — but maybe it’s actually “12,645”? Since there’s no 6 in 12,045, this must be an error. In many worksheets, numbers like this are common. I’ll proceed assuming it’s 12,645.
→ Place value of 6 = hundreds
---
2) Round 3,734 to the nearest thousand.
Look at the thousands digit: 3 (in 3,734)
Next digit (hundreds place): 7
Since 7 ≥ 5, we round up.
So 3,734 → rounds to 4,000
✔ Correct.
---
3) Compare: 6451 ___ 6332
Compare digit by digit from left:
- Thousands: both 6 → same
- Hundreds: 4 vs 3 → 4 > 3
So 6451 > 6332
✔ Answer: >
---
4) Circle one: Prime or Composite 55
Prime = only divisible by 1 and itself
Composite = has more than two factors
55 ÷ 5 = 11 → so 5 × 11 = 55 → has factors other than 1 and 55 → composite
✔ Circle: Composite
---
5) 85,883 + 72,345
Add:
```
85,883
+ 72,345
--------
```
Start from right:
3 + 5 = 8
8 + 4 = 12 → write 2, carry 1
8 + 3 + 1 = 12 → write 2, carry 1
5 + 2 + 1 = 8
8 + 7 = 15 → write 15
So: 158,228
Check with calculator-style:
85,883 + 72,345 =
85,000 + 72,000 = 157,000
883 + 345 = 1,228
Total: 157,000 + 1,228 = 158,228
✔ Correct.
---
6) 92,948 - 46,643
Subtract:
```
92,948
- 46,643
--------
```
8 - 3 = 5
4 - 4 = 0
9 - 6 = 3
2 - 6 → can’t do → borrow from 9 → becomes 12 - 6 = 6, and 9 becomes 8
8 - 4 = 4
Wait — let’s do it properly:
Thousands column: 2 - 6 → need to borrow.
Actually:
Write it out:
92,948
- 46,643
= ?
From right:
8 - 3 = 5
4 - 4 = 0
9 - 6 = 3
2 - 6 → can’t → borrow from 9 (ten-thousands)
So 9 becomes 8, and 2 becomes 12 → 12 - 6 = 6
Then 8 - 4 = 4
So result: 46,305
Check: 46,643 + 46,305 = ?
46,643 + 46,305 =
46,000 + 46,000 = 92,000
643 + 305 = 948
Total: 92,948 ✔
✔ Correct: 46,305
---
7) Solve for the rule and finish the pattern: 12, 24, 36, 48, ___, ___
Each number increases by 12.
12 + 12 = 24
24 + 12 = 36
36 + 12 = 48
48 + 12 = 60
60 + 12 = 72
Rule: Add 12
✔ Next two: 60, 72
---
8) Give the first four multiples for 6.
Multiples of 6: 6×1, 6×2, 6×3, 6×4
→ 6, 12, 18, 24
✔ First four: 6, 12, 18, 24
---
9) Give the factors for 36.
Factors = numbers that divide 36 evenly.
List pairs:
1 × 36
2 × 18
3 × 12
4 × 9
6 × 6
So all factors: 1, 2, 3, 4, 6, 9, 12, 18, 36
✔ List: 1, 2, 3, 4, 6, 9, 12, 18, 36
---
10) Multiply: 21 × 15
Break it down:
21 × 15 = 21 × (10 + 5) = (21×10) + (21×5) = 210 + 105 = 315
Or:
21
× 15
----
105 ← 21×5
+210 ← 21×10 (shifted)
----
315
✔ 315
---
11) 3,000 is ___ times as many as 30.
How many times does 30 go into 3,000?
3,000 ÷ 30 = ?
Divide: 3,000 ÷ 30 = 100
Because 30 × 100 = 3,000
✔ Answer: 100
---
12) Circle even or odd: 51
Even = ends in 0,2,4,6,8
Odd = ends in 1,3,5,7,9
51 ends in 1 → odd
✔ Circle: odd
---
13) Write 12,451 in:
a) Expanded Form:
Break by place value:
10,000 + 2,000 + 400 + 50 + 1
b) Word Form:
Twelve thousand, four hundred fifty-one
✔
Expanded: 10,000 + 2,000 + 400 + 50 + 1
Word: Twelve thousand, four hundred fifty-one
---
14) Multiply:
a) 71 × 10 = 710
b) 71 × 100 = 7,100
c) 71 × 1,000 = 71,000
(Just add zeros!)
✔ Answers:
710
7,100
71,000
---
15) Round 342 + 237 = ?
First, add: 342 + 237
342 + 200 = 542
542 + 37 = 579
Now, round 579 to nearest... what? The problem says “Round 342 + 237 =”, but doesn’t specify to what place.
Looking back at the worksheet format — probably expects rounding to nearest hundred? Or maybe just compute and leave? But it says “Round”.
In context of other problems, likely round to nearest hundred.
579 → nearest hundred: look at tens digit (7) → 7≥5 → round up → 600
Alternatively, maybe they want you to round each number first?
Sometimes “round then add”:
342 → 300
237 → 200
Sum: 500
But that’s less accurate.
The problem says “Round 342 + 237 =”, which probably means compute sum, then round.
I think safest is to compute sum = 579, then round to nearest hundred → 600
But let’s see — in some curricula, they teach to round before adding for estimation.
However, since it says “Round [sum]”, I’ll go with computing first.
✔ Final answer: 600 (rounded to nearest hundred)
---
16) What is the value of the 8 in 7,835?
Number: 7,835
Place values:
7 → thousands
8 → hundreds
3 → tens
5 → ones
So value of 8 is 800
✔ 800
---
Now, compiling all answers clearly:
---
Final Answer:
1) hundreds (assuming number is 12,645 — since 12,045 has no 6)
2) 4,000
3) >
4) Composite
5) 158,228
6) 46,305
7) Rule: Add 12; next numbers: 60, 72
8) 6, 12, 18, 24
9) 1, 2, 3, 4, 6, 9, 12, 18, 36
10) 315
11) 100
12) odd
13) Expanded: 10,000 + 2,000 + 400 + 50 + 1; Word: Twelve thousand, four hundred fifty-one
14) 710; 7,100; 71,000
15) 600 (after rounding 579 to nearest hundred)
16) 800
Parent Tip: Review the logic above to help your child master the concept of end of year worksheet 4th grade.