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Math worksheet for writing equations of parallel and perpendicular lines, including steps and examples.

A worksheet titled "Writing Equations of Parallel and Perpendicular Lines" with sections on slope-intercept form, steps, and examples for writing equations of lines parallel and perpendicular to given lines.

A worksheet titled "Writing Equations of Parallel and Perpendicular Lines" with sections on slope-intercept form, steps, and examples for writing equations of lines parallel and perpendicular to given lines.

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Show Answer Key & Explanations Step-by-step solution for: Writing Equations of Parallel and Perpendicular Lines Notes ...
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Let's solve the problem step by step, filling in the blanks and working through both examples. This worksheet is about writing equations of lines that are parallel or perpendicular to a given line and passing through a specific point.

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🔷 Key Concepts Recap



- Slope-Intercept Form: $ y = mx + b $
- $ m $ = slope
- $ b $ = y-intercept

- Parallel Lines: Same slope → $ m_{\text{parallel}} = m_{\text{original}} $

- Perpendicular Lines: Opposite reciprocal slopes
→ If original slope is $ m $, then perpendicular slope is $ -\frac{1}{m} $

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✔ Steps (Fill in the blanks)



1. Determine the slope of the parallel or perpendicular line
2. Plug in your $ x $ and $ y $ value in the given ordered pair
3. Substitute the $ x $, $ y $, and slope $ m $ into the slope-intercept form equation
4. Solve for $ b $
5. Substitute the slope, $ m $, and y-int, $ b $, into the slope-intercept form equation

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## 🟦 Example 1: Parallel Line

> Write the equation of a line that is parallel to $ y = 4x + 9 $ and passes through $ (0, 2) $

Step-by-step:



- Given line: $ y = 4x + 9 $ → slope $ m = 4 $
- Since it's parallel, the new line has the same slope: $ m = 4 $
- Point: $ (0, 2) $ → so $ x = 0 $, $ y = 2 $

Now plug into $ y = mx + b $:

$$
y = mx + b \\
2 = 4(0) + b \\
2 = 0 + b \\
b = 2
$$

So:
- $ m = 4 $
- $ b = 2 $

Final equation:
$$
y = 4x + 2
$$

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✔ Filled-in Example 1:



```
x = 0 y = 2 m = 4

y = mx + b
2 = 4(0) + b
2 = 0 + b
2 = b

m = 4 b = 2

y = mx + b
y = 4x + 2
```

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## 🟨 Example 2: Perpendicular Line

> Write the equation of a line that is perpendicular to $ y = -6x + 12 $ and passes through $ (12, -5) $

Step-by-step:



- Given line: $ y = -6x + 12 $ → slope $ m = -6 $
- For perpendicular, use opposite reciprocal:
- Reciprocal of $ -6 $ is $ -\frac{1}{6} $
- Opposite of that is $ \frac{1}{6} $
- So, $ m = \frac{1}{6} $

Point: $ (12, -5) $ → $ x = 12 $, $ y = -5 $

Now plug into $ y = mx + b $:

$$
y = mx + b \\
-5 = \frac{1}{6}(12) + b \\
-5 = 2 + b \\
b = -5 - 2 = -7
$$

So:
- $ m = \frac{1}{6} $
- $ b = -7 $

Final equation:
$$
y = \frac{1}{6}x - 7
$$

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✔ Filled-in Example 2:



```
x = 12 y = -5 m = 1/6

y = mx + b
-5 = (1/6)(12) + b
-5 = 2 + b
-7 = b

m = 1/6 b = -7

y = mx + b
y = (1/6)x - 7
```

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✔ Final Answers:



#### Example 1 (Parallel):
- Equation: $ \boxed{y = 4x + 2} $

#### Example 2 (Perpendicular):
- Equation: $ \boxed{y = \frac{1}{6}x - 7} $

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📌 Summary



| Type | Slope Rule | Example Slope |
|-------------|------------------------|---------------|
| Parallel | Same slope | $ m = 4 $ |
| Perpendicular | Opposite reciprocal | $ m = \frac{1}{6} $ |

Always:
1. Use the correct slope based on relationship.
2. Plug in the point $ (x, y) $ to find $ b $.
3. Write final equation in $ y = mx + b $ form.

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