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Quadratic equations worksheet with square roots, where students solve equations and color by number based on the positive root.

Worksheet titled "Quadratic Equations with Square Roots Color by Number" with instructions and 12 quadratic equations to solve by taking square roots, each with a corresponding color.

Worksheet titled "Quadratic Equations with Square Roots Color by Number" with instructions and 12 quadratic equations to solve by taking square roots, each with a corresponding color.

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Show Answer Key & Explanations Step-by-step solution for: Quadratic Equations With Square Roots Color by Number
Let's solve each quadratic equation by isolating \( x^2 \) and then taking the square root. We are only interested in the positive root for coloring, as per the directions.

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1. \( x^2 + 6 = 6 \)

Subtract 6 from both sides:

\( x^2 = 0 \)

Take square root:

\( x = \sqrt{0} = 0 \)

Positive root: 0 — Color: Yellow

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2. \( x^2 + 4 = 40 \)

Subtract 4:

\( x^2 = 36 \)

Take square root:

\( x = \sqrt{36} = 6 \)

Positive root: 6 — Color: Purple

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3. \( -3x^2 = 147 \)

Divide both sides by -3:

\( x^2 = -49 \)

Take square root:

\( x = \sqrt{-49} \) → Not real (imaginary)

But the worksheet says “solve by taking the square root” and “leave answers in simplest fraction/radical form.” Since it’s imaginary, and we’re coloring a picture (likely expecting real numbers), this might be an error or trick. However, if we proceed formally:

\( x = \pm \sqrt{-49} = \pm 7i \)

There is no positive real root. But since the instructions say to color the *positive* root, and there isn’t one, perhaps skip? Or maybe the problem expects us to note no real solution.

However, let’s check the original problem again — maybe I misread.

Wait — -3x² = 147 → x² = -49 → no real solution.

So technically, no positive real root. But since the worksheet likely expects real roots, perhaps double-check if the equation was meant to be different? But as written, we must report:

No real positive root — but the instruction says to color the positive root. This may be a trick question. Let’s leave it blank for now and come back if needed.

But wait — perhaps the problem is designed to have real solutions only? Let me verify others first.

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4. \( -5x^2 + 2 = -1088 \)

Subtract 2:

\( -5x^2 = -1090 \)

Divide by -5:

\( x^2 = 218 \)

Take square root:

\( x = \sqrt{218} \)

Can we simplify? 218 = 2 × 109 → both prime → cannot simplify.

Positive root: \( \sqrt{218} \) — Color: Blue

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5. \( x^2 + 2 = 16 \)

Subtract 2:

\( x^2 = 14 \)

Take square root:

\( x = \sqrt{14} \)

Positive root: \( \sqrt{14} \) — Color: Black

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6. \( -10 - 5x^2 = -330 \)

Add 10 to both sides:

\( -5x^2 = -320 \)

Divide by -5:

\( x^2 = 64 \)

Take square root:

\( x = \sqrt{64} = 8 \)

Positive root: 8 — Color: Yellow

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7. \( -8x^2 - 7 = 193 \)

Add 7:

\( -8x^2 = 200 \)

Divide by -8:

\( x^2 = -25 \)

Again, negative → imaginary.

\( x = \pm 5i \)

No real positive root.

Same issue as #3. Perhaps these are mistakes? Or maybe we're supposed to write the principal square root even if complex? But coloring suggests real numbers.

We’ll flag these and continue.

---

8. \( 8x^2 + 4 = 164 \)

Subtract 4:

\( 8x^2 = 160 \)

Divide by 8:

\( x^2 = 20 \)

Take square root:

\( x = \sqrt{20} = \sqrt{4 \cdot 5} = 2\sqrt{5} \)

Positive root: \( 2\sqrt{5} \) — Color: Green

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9. \( 6x^2 + 7 = 607 \)

Subtract 7:

\( 6x^2 = 600 \)

Divide by 6:

\( x^2 = 100 \)

Take square root:

\( x = \sqrt{100} = 10 \)

Positive root: 10 — Color: Blue

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10. \( -9x^2 + 10 = 91 \)

Subtract 10:

\( -9x^2 = 81 \)

Divide by -9:

\( x^2 = -9 \)

Again, negative → imaginary.

\( x = \pm 3i \)

No real positive root.

---

11. \( 13 - 8x^2 = -1139 \)

Subtract 13:

\( -8x^2 = -1152 \)

Divide by -8:

\( x^2 = 144 \)

Take square root:

\( x = \sqrt{144} = 12 \)

Positive root: 12 — Color: Yellow

---

12. \( -4x^2 = 96 \)

Divide by -4:

\( x^2 = -24 \)

Again, negative → imaginary.

\( x = \pm \sqrt{-24} = \pm 2i\sqrt{6} \)

No real positive root.

---

## Summary of Positive Real Roots:

| Problem | Positive Root | Color |
|---------|----------------------|---------|
| 1 | 0 | Yellow |
| 2 | 6 | Purple |
| 3 | No real root | Green |
| 4 | √218 | Blue |
| 5 | √14 | Black |
| 6 | 8 | Yellow |
| 7 | No real root | Purple |
| 8 | 2√5 | Green |
| 9 | 10 | Blue |
| 10 | No real root | Black |
| 11 | 12 | Yellow |
| 12 | No real root | Blue |

---

## Final Answer (for coloring):

You should fill in the "Square Roots" column with the positive real roots where they exist:

1. 0
2. 6
3. *(No real root — perhaps leave blank or write “no real solution”)*
4. √218
5. √14
6. 8
7. *(No real root)*
8. 2√5
9. 10
10. *(No real root)*
11. 12
12. *(No real root)*

---

## Coloring Instructions:

Color the positive root on the picture using the indicated color:

- Yellow: Problems 1, 6, 11 → roots: 0, 8, 12
- Purple: Problems 2, 7 → root: 6 (and 7 has no real root — maybe skip or color nothing)
- Green: Problems 3, 8 → root: 2√5 (and 3 has no real root)
- Blue: Problems 4, 9, 12 → roots: √218, 10 (and 12 has no real root)
- Black: Problems 5, 10 → root: √14 (and 10 has no real root)

⚠️ Note: Problems 3, 7, 10, and 12 have no real positive roots, so you may need to leave those uncolored or consult your teacher. It’s possible there’s a typo in the worksheet (e.g., sign errors). For example, if problem 3 were `3x² = 147`, then x = 7 — which would make sense.

But based on what’s written, we solved correctly.

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Final Boxed Answers for Square Roots Column (only real positive roots):

1. \( \boxed{0} \)
2. \( \boxed{6} \)
3. No real solution
4. \( \boxed{\sqrt{218}} \)
5. \( \boxed{\sqrt{14}} \)
6. \( \boxed{8} \)
7. No real solution
8. \( \boxed{2\sqrt{5}} \)
9. \( \boxed{10} \)
10. No real solution
11. \( \boxed{12} \)
12. No real solution

Use these to color the picture accordingly.
Parent Tip: Review the logic above to help your child master the concept of equations with square roots worksheet.
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