To solve the problem, we need to identify the pattern in each sequence and use it to find the missing terms. Let's go through each sequence step by step.
---
Sequence (a): \( 1, 1, 2, 3, 5, 8, \_, \_, \_ \)
This is a classic Fibonacci sequence, where each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
- The next term after 8 is \( 5 + 8 = 13 \).
- The next term after 13 is \( 8 + 13 = 21 \).
- The next term after 21 is \( 13 + 21 = 34 \).
Thus, the missing terms are:
\[
13, 21, 34
\]
---
Sequence (b): \( 6, 9, 15, 24, \_, \_, \_ \)
Here, each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
- The next term after 24 is \( 15 + 24 = 39 \).
- The next term after 39 is \( 24 + 39 = 63 \).
- The next term after 63 is \( 39 + 63 = 102 \).
Thus, the missing terms are:
\[
39, 63, 102
\]
---
Sequence (c): \( \_, \_, \_, 12, 19, 31, \ldots \)
Again, this is a Fibonacci-type sequence where each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
We work backward to find the missing terms:
- The term before 19 is \( 31 - 19 = 12 \).
- The term before 12 is \( 19 - 12 = 7 \).
- The term before 7 is \( 12 - 7 = 5 \).
Thus, the missing terms are:
\[
5, 7, 12
\]
---
Sequence (d): \( 0.5, 1, 1.5, \_, 4, \_, \_ \)
This is also a Fibonacci-type sequence where each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
- The next term after 1.5 is \( 1 + 1.5 = 2.5 \).
- The next term after 2.5 is \( 1.5 + 2.5 = 4 \) (which is already given).
- The next term after 4 is \( 2.5 + 4 = 6.5 \).
- The next term after 6.5 is \( 4 + 6.5 = 10.5 \).
Thus, the missing terms are:
\[
2.5, 6.5, 10.5
\]
---
Sequence (e): \( 1, -1, 0, \_, -1, \_, \_ \)
This is a Fibonacci-type sequence where each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
- The next term after 0 is \( -1 + 0 = -1 \).
- The next term after -1 is \( 0 + (-1) = -1 \).
- The next term after -1 is \( -1 + (-1) = -2 \).
Thus, the missing terms are:
\[
-1, -1, -2
\]
---
Sequence (f): \( a, b, \_, \_, \_ \)
This is a Fibonacci-type sequence where each term is the sum of the two preceding terms:
\[
a_n = a_{n-1} + a_{n-2}
\]
- The next term after \( b \) is \( a + b \).
- The next term after \( a + b \) is \( b + (a + b) = a + 2b \).
- The next term after \( a + 2b \) is \( (a + b) + (a + 2b) = 2a + 3b \).
Thus, the missing terms are:
\[
a + b, a + 2b, 2a + 3b
\]
---
Final Answers:
\[
\boxed{
\begin{array}{ll}
(a) & 13, 21, 34 \\
(b) & 39, 63, 102 \\
(c) & 5, 7, 12 \\
(d) & 2.5, 6.5, 10.5 \\
(e) & -1, -1, -2 \\
(f) & a + b, a + 2b, 2a + 3b \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of fibonacci sequence worksheet.