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Area and Perimeter worksheet with six geometry problems for calculating area and perimeter of rectangles and triangles.

A math worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions, asking students to calculate area and perimeter. The worksheet includes a space for the student's name and is labeled "Worksheet 1" at the bottom.

A math worksheet titled "Area & Perimeter" with six geometry problems involving rectangles and triangles, each with given dimensions, asking students to calculate area and perimeter. The worksheet includes a space for the student's name and is labeled "Worksheet 1" at the bottom.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 Area and Perimeter Worksheets | Free Math Worksheets
Let's solve each problem step by step using the formulas for area and perimeter of different shapes.

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🔷 Formulas:



- Rectangle:
- Area = length × width
- Perimeter = 2 × (length + width)

- Square:
- Area = side × side (or $ s^2 $)
- Perimeter = 4 × side

- Triangle:
- Area = $ \frac{1}{2} \times \text{base} \times \text{height} $
- Perimeter = sum of all three sides *(Note: Only base and height are given in some cases, so we assume only area is required unless all sides are known)*

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Now let’s go through each question:

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1. Rectangle: 10m × 4m



- Area = length × width = $ 10 \times 4 = 40 \, \text{m}^2 $
- Perimeter = $ 2 \times (10 + 4) = 2 \times 14 = 28 \, \text{m} $

Answer:
Area = 40 m², Perimeter = 28 m

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2. Triangle: Base = 9m, Height = 6m



- Area = $ \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 9 \times 6 = 27 \, \text{m}^2 $

⚠️ We don't have the lengths of the other two sides, so perimeter cannot be calculated with given info.

Answer:
Area = 27 m², Perimeter = Not enough info

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3. Square: Side = 7m



- Area = $ 7 \times 7 = 49 \, \text{m}^2 $
- Perimeter = $ 4 \times 7 = 28 \, \text{m} $

Answer:
Area = 49 m², Perimeter = 28 m

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4. Triangle: Base = 8m, Height = 12m



- Area = $ \frac{1}{2} \times 8 \times 12 = 4 \times 12 = 48 \, \text{m}^2 $

⚠️ Again, only base and height are given. No side lengths → perimeter not possible.

Answer:
Area = 48 m², Perimeter = Not enough info

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5. Rectangle: 20m × 7m



- Area = $ 20 \times 7 = 140 \, \text{m}^2 $
- Perimeter = $ 2 \times (20 + 7) = 2 \times 27 = 54 \, \text{m} $

Answer:
Area = 140 m², Perimeter = 54 m

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6. Rectangle: 11m × 8m



- Area = $ 11 \times 8 = 88 \, \text{m}^2 $
- Perimeter = $ 2 \times (11 + 8) = 2 \times 19 = 38 \, \text{m} $

Answer:
Area = 88 m², Perimeter = 38 m

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Final Answers Summary:



| Problem | Shape | Area | Perimeter |
|--------|--------------|------------|---------------|
| 1 | Rectangle | 40 m² | 28 m |
| 2 | Triangle | 27 m² | Not enough info |
| 3 | Square | 49 m² | 28 m |
| 4 | Triangle | 48 m² | Not enough info |
| 5 | Rectangle | 140 m² | 54 m |
| 6 | Rectangle | 88 m² | 38 m |

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💡 Note: For triangles #2 and #4, only base and height are provided, so we can compute area, but perimeter requires knowing all three side lengths — which aren’t given. So those perimeters are not solvable with current information.

Let me know if you'd like to estimate perimeter assuming it's an isosceles triangle!
Parent Tip: Review the logic above to help your child master the concept of find the area worksheet.
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