Find the Slope of Each Line worksheet with eight graphs for calculating slope.
Graph paper with eight coordinate planes, each showing a line with two points marked. Students are to find the slope of each line.
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Step-by-step solution for: Algebra 1 Worksheets | Linear Equations Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Algebra 1 Worksheets | Linear Equations Worksheets
Let's solve each problem step by step to find the slope of each line. The slope of a line is calculated using the formula:
$$
\text{slope} = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}
$$
We'll pick two points on each line from the graph and compute the slope.
---
Line goes from $(-4, 0)$ to $(2, 3)$
$$
\text{slope} = \frac{3 - 0}{2 - (-4)} = \frac{3}{6} = \frac{1}{2}
$$
✔ Slope = $ \frac{1}{2} $
---
Line goes from $(-5, -1)$ to $(4, 0)$
$$
\text{slope} = \frac{0 - (-1)}{4 - (-5)} = \frac{1}{9}
$$
✔ Slope = $ \frac{1}{9} $
---
Line goes from $(-1, 4)$ to $(2, -2)$
$$
\text{slope} = \frac{-2 - 4}{2 - (-1)} = \frac{-6}{3} = -2
$$
✔ Slope = $ -2 $
---
Line goes from $(1, 4)$ to $(1, -2)$ → Vertical line
Since $x$ doesn't change (same $x$-coordinate), the run is 0 → undefined slope
✔ Slope = undefined
> Note: Vertical lines have undefined slope.
---
Line goes from $(-5, 1)$ to $(3, 2)$
$$
\text{slope} = \frac{2 - 1}{3 - (-5)} = \frac{1}{8}
$$
✔ Slope = $ \frac{1}{8} $
---
Line goes from $(-2, -2)$ to $(2, 4)$
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
✔ Slope = $ \frac{3}{2} $
---
Line goes from $(-2, -2)$ to $(2, 4)$
Wait — same as #6? Let’s double-check.
Actually, this one appears to go from $(-2, -2)$ to $(2, 4)$ — yes, same points.
But let's verify visually: it passes through origin?
Yes! From $(-2, -2)$ to $(2, 4)$:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
Wait — but actually, if it goes through origin $(0,0)$, then from $(0,0)$ to $(2,4)$: $\frac{4}{2} = 2$
Wait — let’s recheck coordinates.
Looking at graph 7: line goes from $(-2, -2)$ to $(2, 4)$?
From $(-2,-2)$ to $(2,4)$: rise = 6, run = 4 → slope = $ \frac{6}{4} = \frac{3}{2} $
But wait — does it pass through $(0,0)$?
Yes: $(-2,-2)$ to $(2,4)$: from $(-2,-2)$ to $(0,0)$: rise = 2, run = 2 → slope = 1
Wait — that can’t be. If from $(-2,-2)$ to $(0,0)$, slope = $ \frac{0 - (-2)}{0 - (-2)} = \frac{2}{2} = 1 $
And from $(0,0)$ to $(2,4)$: $ \frac{4}{2} = 2 $
That’s inconsistent — so not straight?
Wait — maybe I misread.
Look carefully: in graph 7, the line goes from $(-2, -2)$ to $(2, 4)$? But let’s check:
At $x = -2$, $y = -2$
At $x = 0$, $y = 0$
At $x = 2$, $y = 4$
So: from $(-2, -2)$ to $(2, 4)$:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
But from $(-2, -2)$ to $(0,0)$: $\frac{0 - (-2)}{0 - (-2)} = \frac{2}{2} = 1$
Contradiction — unless the point at $x=2$ is not $y=4$
Wait — look at grid: each square is 1 unit.
In graph 7: line starts at $(-2, -2)$, goes through $(0,0)$, and ends at $(2, 2)$?
Wait — no, at $x=2$, $y=4$? That would be above.
But the line seems to go from $(-2, -2)$ to $(2, 4)$ — but that would require going up 6 units over 4 units → slope $3/2$
But visually, it looks like it goes through $(1,1.5)$, etc.
But let's trust the graph.
Wait — actually, looking again: at $x=2$, $y=4$? No — the line ends at approximately $(2, 4)$? Wait, the grid goes up to $y=5$, and the line ends at $y=4$ when $x=2$?
Yes — so point $(2,4)$
And $(-2,-2)$
So:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
But earlier we thought it passed through origin — does it?
From $(-2,-2)$ to $(0,0)$: rise = 2, run = 2 → slope = 1
But from $(0,0)$ to $(2,4)$: rise = 4, run = 2 → slope = 2
Not consistent — so either the line isn't straight or my reading is off.
Wait — perhaps the line goes from $(-2, -2)$ to $(2, 2)$? But at $x=2$, $y=2$?
No — in graph 7, the line goes from bottom-left to top-right, passing through origin, and ends at $(2, 4)$?
Wait — no — look closely:
The line goes from $(-2, -2)$ to $(2, 2)$? At $x=2$, $y=2$? But the dot is at $y=4$?
Wait — I think I made an error.
Let me re-express:
Each graph has a grid from $-5$ to $5$ on both axes.
Let’s carefully read each point.
---
#### 7)
Line passes through:
- $(-2, -2)$
- $(0, 0)$
- $(2, 2)$
Wait — at $x=2$, $y=2$? Yes — the line ends at $(2, 2)$
So from $(-2, -2)$ to $(2, 2)$:
$$
\text{slope} = \frac{2 - (-2)}{2 - (-2)} = \frac{4}{4} = 1
$$
Or from $(0,0)$ to $(2,2)$: $\frac{2}{2} = 1$
✔ Slope = $ 1 $
Earlier mistake — I thought it went to $y=4$, but no — at $x=2$, $y=2$
So correct slope is 1
---
Line goes from $(-4, 3)$ to $(4, -1)$
Check: at $x=-4$, $y=3$; at $x=4$, $y=-1$
$$
\text{slope} = \frac{-1 - 3}{4 - (-4)} = \frac{-4}{8} = -\frac{1}{2}
$$
✔ Slope = $ -\frac{1}{2} $
---
| Problem | Slope |
|--------|-------|
| 1) | $ \frac{1}{2} $ |
| 2) | $ \frac{1}{9} $ |
| 3) | $ -2 $ |
| 4) | undefined |
| 5) | $ \frac{1}{8} $ |
| 6) | $ \frac{3}{2} $ |
| 7) | $ 1 $ |
| 8) | $ -\frac{1}{2} $ |
---
1) $ \frac{1}{2} $
2) $ \frac{1}{9} $
3) $ -2 $
4) undefined
5) $ \frac{1}{8} $
6) $ \frac{3}{2} $
7) $ 1 $
8) $ -\frac{1}{2} $
---
Let me know if you'd like these explained with visual steps or graphs!
$$
\text{slope} = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}
$$
We'll pick two points on each line from the graph and compute the slope.
---
1)
Line goes from $(-4, 0)$ to $(2, 3)$
$$
\text{slope} = \frac{3 - 0}{2 - (-4)} = \frac{3}{6} = \frac{1}{2}
$$
✔ Slope = $ \frac{1}{2} $
---
2)
Line goes from $(-5, -1)$ to $(4, 0)$
$$
\text{slope} = \frac{0 - (-1)}{4 - (-5)} = \frac{1}{9}
$$
✔ Slope = $ \frac{1}{9} $
---
3)
Line goes from $(-1, 4)$ to $(2, -2)$
$$
\text{slope} = \frac{-2 - 4}{2 - (-1)} = \frac{-6}{3} = -2
$$
✔ Slope = $ -2 $
---
4)
Line goes from $(1, 4)$ to $(1, -2)$ → Vertical line
Since $x$ doesn't change (same $x$-coordinate), the run is 0 → undefined slope
✔ Slope = undefined
> Note: Vertical lines have undefined slope.
---
5)
Line goes from $(-5, 1)$ to $(3, 2)$
$$
\text{slope} = \frac{2 - 1}{3 - (-5)} = \frac{1}{8}
$$
✔ Slope = $ \frac{1}{8} $
---
6)
Line goes from $(-2, -2)$ to $(2, 4)$
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
✔ Slope = $ \frac{3}{2} $
---
7)
Line goes from $(-2, -2)$ to $(2, 4)$
Wait — same as #6? Let’s double-check.
Actually, this one appears to go from $(-2, -2)$ to $(2, 4)$ — yes, same points.
But let's verify visually: it passes through origin?
Yes! From $(-2, -2)$ to $(2, 4)$:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
Wait — but actually, if it goes through origin $(0,0)$, then from $(0,0)$ to $(2,4)$: $\frac{4}{2} = 2$
Wait — let’s recheck coordinates.
Looking at graph 7: line goes from $(-2, -2)$ to $(2, 4)$?
From $(-2,-2)$ to $(2,4)$: rise = 6, run = 4 → slope = $ \frac{6}{4} = \frac{3}{2} $
But wait — does it pass through $(0,0)$?
Yes: $(-2,-2)$ to $(2,4)$: from $(-2,-2)$ to $(0,0)$: rise = 2, run = 2 → slope = 1
Wait — that can’t be. If from $(-2,-2)$ to $(0,0)$, slope = $ \frac{0 - (-2)}{0 - (-2)} = \frac{2}{2} = 1 $
And from $(0,0)$ to $(2,4)$: $ \frac{4}{2} = 2 $
That’s inconsistent — so not straight?
Wait — maybe I misread.
Look carefully: in graph 7, the line goes from $(-2, -2)$ to $(2, 4)$? But let’s check:
At $x = -2$, $y = -2$
At $x = 0$, $y = 0$
At $x = 2$, $y = 4$
So: from $(-2, -2)$ to $(2, 4)$:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
But from $(-2, -2)$ to $(0,0)$: $\frac{0 - (-2)}{0 - (-2)} = \frac{2}{2} = 1$
Contradiction — unless the point at $x=2$ is not $y=4$
Wait — look at grid: each square is 1 unit.
In graph 7: line starts at $(-2, -2)$, goes through $(0,0)$, and ends at $(2, 2)$?
Wait — no, at $x=2$, $y=4$? That would be above.
But the line seems to go from $(-2, -2)$ to $(2, 4)$ — but that would require going up 6 units over 4 units → slope $3/2$
But visually, it looks like it goes through $(1,1.5)$, etc.
But let's trust the graph.
Wait — actually, looking again: at $x=2$, $y=4$? No — the line ends at approximately $(2, 4)$? Wait, the grid goes up to $y=5$, and the line ends at $y=4$ when $x=2$?
Yes — so point $(2,4)$
And $(-2,-2)$
So:
$$
\text{slope} = \frac{4 - (-2)}{2 - (-2)} = \frac{6}{4} = \frac{3}{2}
$$
But earlier we thought it passed through origin — does it?
From $(-2,-2)$ to $(0,0)$: rise = 2, run = 2 → slope = 1
But from $(0,0)$ to $(2,4)$: rise = 4, run = 2 → slope = 2
Not consistent — so either the line isn't straight or my reading is off.
Wait — perhaps the line goes from $(-2, -2)$ to $(2, 2)$? But at $x=2$, $y=2$?
No — in graph 7, the line goes from bottom-left to top-right, passing through origin, and ends at $(2, 4)$?
Wait — no — look closely:
The line goes from $(-2, -2)$ to $(2, 2)$? At $x=2$, $y=2$? But the dot is at $y=4$?
Wait — I think I made an error.
Let me re-express:
Each graph has a grid from $-5$ to $5$ on both axes.
Let’s carefully read each point.
---
Re-evaluate with accurate point reading:
#### 7)
Line passes through:
- $(-2, -2)$
- $(0, 0)$
- $(2, 2)$
Wait — at $x=2$, $y=2$? Yes — the line ends at $(2, 2)$
So from $(-2, -2)$ to $(2, 2)$:
$$
\text{slope} = \frac{2 - (-2)}{2 - (-2)} = \frac{4}{4} = 1
$$
Or from $(0,0)$ to $(2,2)$: $\frac{2}{2} = 1$
✔ Slope = $ 1 $
Earlier mistake — I thought it went to $y=4$, but no — at $x=2$, $y=2$
So correct slope is 1
---
8)
Line goes from $(-4, 3)$ to $(4, -1)$
Check: at $x=-4$, $y=3$; at $x=4$, $y=-1$
$$
\text{slope} = \frac{-1 - 3}{4 - (-4)} = \frac{-4}{8} = -\frac{1}{2}
$$
✔ Slope = $ -\frac{1}{2} $
---
Final Answers:
| Problem | Slope |
|--------|-------|
| 1) | $ \frac{1}{2} $ |
| 2) | $ \frac{1}{9} $ |
| 3) | $ -2 $ |
| 4) | undefined |
| 5) | $ \frac{1}{8} $ |
| 6) | $ \frac{3}{2} $ |
| 7) | $ 1 $ |
| 8) | $ -\frac{1}{2} $ |
---
✔ Summary of Answers:
1) $ \frac{1}{2} $
2) $ \frac{1}{9} $
3) $ -2 $
4) undefined
5) $ \frac{1}{8} $
6) $ \frac{3}{2} $
7) $ 1 $
8) $ -\frac{1}{2} $
---
Let me know if you'd like these explained with visual steps or graphs!
Parent Tip: Review the logic above to help your child master the concept of find the slope and y intercept worksheet.