Comparison of two triangles with given side lengths.
Triangle 1 with sides 18 in, 16 in, and 14 in; Triangle 2 with sides 9 in, 8 in, and unknown side, both labeled with vertices A, C, R and E, K, Y respectively.
PNG
418×257
6.5 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #922016
⭐
Show Answer Key & Explanations
Step-by-step solution for: Finding the Missing Side Length Given Two Similar Triangles ...
▼
Show Answer Key & Explanations
Step-by-step solution for: Finding the Missing Side Length Given Two Similar Triangles ...
Let’s solve this step by step.
We are given two triangles:
Triangle 1 (CAR):
- Side CA = 18 in
- Side AR = 14 in
- Side CR = 16 in
Triangle 2 (KEY):
- Side KE = 9 in
- Side EY = ? (we don’t know yet, but we can find it if needed)
- Side KY = 8 in
Wait — actually, looking at the labels:
In Triangle 2:
- K to E is 9 in
- K to Y is 8 in
- E to Y is not labeled — but we don’t need it for comparison.
The question is likely asking: Are these triangles similar?
To check if two triangles are similar, we compare the ratios of their corresponding sides. If all three ratios are equal, then the triangles are similar.
But first — which sides correspond?
Looking at the shape and labeling:
In Triangle 1:
Longest side = CA = 18 in
Middle side = CR = 16 in
Shortest side = AR = 14 in
In Triangle 2:
Longest side = KE = 9 in
Middle side = KY = 8 in
Shortest side = EY = ? → Wait, we don’t have EY labeled!
Hold on — maybe I misread. Let me look again.
Actually, in Triangle 2, the sides shown are:
- From K to E: 9 in
- From K to Y: 8 in
- From E to Y: not labeled — but perhaps we’re meant to assume correspondence based on position?
Alternatively, maybe the problem is just to compare the ratios of the sides that are given, assuming they correspond in order.
Let’s try matching the sides as labeled:
Assume:
- Side CA (18) corresponds to side KE (9)
- Side AR (14) corresponds to side EY (?) — but we don’t have EY
- Side CR (16) corresponds to side KY (8)
Wait — that doesn’t help because we’re missing one side.
But notice: 18 / 9 = 2
And 16 / 8 = 2
So if the third pair also has ratio 2, then they are similar.
What would the third side be? In Triangle 1, the remaining side is AR = 14 in.
If the triangles are similar with scale factor 2, then the corresponding side in Triangle 2 should be 14 / 2 = 7 in.
But in the diagram, the side from E to Y is not labeled — so maybe we’re supposed to infer that?
Alternatively, perhaps the problem is simply to check if the given sides are proportional.
Given:
CA = 18, KE = 9 → ratio = 18/9 = 2
CR = 16, KY = 8 → ratio = 16/8 = 2
AR = 14, and if EY were 7, then 14/7 = 2 → same ratio.
Since two pairs of sides have the same ratio, and if we assume the included angle is the same (which we can’t verify from image), but since this is a homework problem, likely we’re to assume that if two sides are proportional and the included angle is congruent, then SAS similarity applies.
But wait — do we know the angles? No.
Alternatively, maybe the problem expects us to see that all three sides are in proportion if we calculate the missing side.
But we don’t have enough info unless we assume correspondence.
Another approach: list the sides in order.
Triangle 1 sides: 14, 16, 18
Triangle 2 sides: 8, 9, and unknown.
If we sort them:
Triangle 1: 14, 16, 18
Triangle 2: 8, 9, x
Now, check ratios:
14 / 8 = 1.75
16 / 9 ≈ 1.777...
Not equal.
But earlier when we matched 18→9 and 16→8, we got ratio 2.
That suggests the correspondence is not by size order, but by vertex labeling.
Looking at the diagram:
In Triangle 1: vertices C, A, R
Sides: CA=18, AR=14, CR=16
In Triangle 2: vertices K, E, Y
Sides: KE=9, EY=?, KY=8
If we assume that:
- C corresponds to K
- A corresponds to E
- R corresponds to Y
Then:
- CA corresponds to KE → 18 to 9 → ratio 2
- AR corresponds to EY → 14 to ?
- CR corresponds to KY → 16 to 8 → ratio 2
So for similarity, EY must be 14 / 2 = 7 in.
Since the problem doesn't give EY, but asks to solve, perhaps the task is to determine if they are similar, and if so, what is the scale factor or missing side.
But the user didn't specify the exact question — only provided the image.
Re-reading the initial instruction: "Solve the problem accurately." But no explicit question is stated.
However, in such diagrams, the typical question is: "Are the triangles similar? If yes, what is the scale factor?" or "Find the missing side."
Given that, and since two sides are in ratio 2:1, and if we assume the third side follows, then yes, they are similar with scale factor 2.
Perhaps the problem is to find the length of EY.
Let me assume that's the case.
So, if Triangle CAR ~ Triangle KEY, with correspondence C→K, A→E, R→Y, then:
CA / KE = AR / EY = CR / KY
We have:
CA / KE = 18 / 9 = 2
CR / KY = 16 / 8 = 2
So AR / EY = 2 → 14 / EY = 2 → EY = 14 / 2 = 7 in
Therefore, the missing side EY is 7 inches.
And the triangles are similar with scale factor 2.
Since the problem says "solve the problem", and this is the only logical thing to solve, I'll go with finding the missing side.
Final Answer: 7 in
We are given two triangles:
Triangle 1 (CAR):
- Side CA = 18 in
- Side AR = 14 in
- Side CR = 16 in
Triangle 2 (KEY):
- Side KE = 9 in
- Side EY = ? (we don’t know yet, but we can find it if needed)
- Side KY = 8 in
Wait — actually, looking at the labels:
In Triangle 2:
- K to E is 9 in
- K to Y is 8 in
- E to Y is not labeled — but we don’t need it for comparison.
The question is likely asking: Are these triangles similar?
To check if two triangles are similar, we compare the ratios of their corresponding sides. If all three ratios are equal, then the triangles are similar.
But first — which sides correspond?
Looking at the shape and labeling:
In Triangle 1:
Longest side = CA = 18 in
Middle side = CR = 16 in
Shortest side = AR = 14 in
In Triangle 2:
Longest side = KE = 9 in
Middle side = KY = 8 in
Shortest side = EY = ? → Wait, we don’t have EY labeled!
Hold on — maybe I misread. Let me look again.
Actually, in Triangle 2, the sides shown are:
- From K to E: 9 in
- From K to Y: 8 in
- From E to Y: not labeled — but perhaps we’re meant to assume correspondence based on position?
Alternatively, maybe the problem is just to compare the ratios of the sides that are given, assuming they correspond in order.
Let’s try matching the sides as labeled:
Assume:
- Side CA (18) corresponds to side KE (9)
- Side AR (14) corresponds to side EY (?) — but we don’t have EY
- Side CR (16) corresponds to side KY (8)
Wait — that doesn’t help because we’re missing one side.
But notice: 18 / 9 = 2
And 16 / 8 = 2
So if the third pair also has ratio 2, then they are similar.
What would the third side be? In Triangle 1, the remaining side is AR = 14 in.
If the triangles are similar with scale factor 2, then the corresponding side in Triangle 2 should be 14 / 2 = 7 in.
But in the diagram, the side from E to Y is not labeled — so maybe we’re supposed to infer that?
Alternatively, perhaps the problem is simply to check if the given sides are proportional.
Given:
CA = 18, KE = 9 → ratio = 18/9 = 2
CR = 16, KY = 8 → ratio = 16/8 = 2
AR = 14, and if EY were 7, then 14/7 = 2 → same ratio.
Since two pairs of sides have the same ratio, and if we assume the included angle is the same (which we can’t verify from image), but since this is a homework problem, likely we’re to assume that if two sides are proportional and the included angle is congruent, then SAS similarity applies.
But wait — do we know the angles? No.
Alternatively, maybe the problem expects us to see that all three sides are in proportion if we calculate the missing side.
But we don’t have enough info unless we assume correspondence.
Another approach: list the sides in order.
Triangle 1 sides: 14, 16, 18
Triangle 2 sides: 8, 9, and unknown.
If we sort them:
Triangle 1: 14, 16, 18
Triangle 2: 8, 9, x
Now, check ratios:
14 / 8 = 1.75
16 / 9 ≈ 1.777...
Not equal.
But earlier when we matched 18→9 and 16→8, we got ratio 2.
That suggests the correspondence is not by size order, but by vertex labeling.
Looking at the diagram:
In Triangle 1: vertices C, A, R
Sides: CA=18, AR=14, CR=16
In Triangle 2: vertices K, E, Y
Sides: KE=9, EY=?, KY=8
If we assume that:
- C corresponds to K
- A corresponds to E
- R corresponds to Y
Then:
- CA corresponds to KE → 18 to 9 → ratio 2
- AR corresponds to EY → 14 to ?
- CR corresponds to KY → 16 to 8 → ratio 2
So for similarity, EY must be 14 / 2 = 7 in.
Since the problem doesn't give EY, but asks to solve, perhaps the task is to determine if they are similar, and if so, what is the scale factor or missing side.
But the user didn't specify the exact question — only provided the image.
Re-reading the initial instruction: "Solve the problem accurately." But no explicit question is stated.
However, in such diagrams, the typical question is: "Are the triangles similar? If yes, what is the scale factor?" or "Find the missing side."
Given that, and since two sides are in ratio 2:1, and if we assume the third side follows, then yes, they are similar with scale factor 2.
Perhaps the problem is to find the length of EY.
Let me assume that's the case.
So, if Triangle CAR ~ Triangle KEY, with correspondence C→K, A→E, R→Y, then:
CA / KE = AR / EY = CR / KY
We have:
CA / KE = 18 / 9 = 2
CR / KY = 16 / 8 = 2
So AR / EY = 2 → 14 / EY = 2 → EY = 14 / 2 = 7 in
Therefore, the missing side EY is 7 inches.
And the triangles are similar with scale factor 2.
Since the problem says "solve the problem", and this is the only logical thing to solve, I'll go with finding the missing side.
Final Answer: 7 in
Parent Tip: Review the logic above to help your child master the concept of finding missing sides of similar figures worksheet.