To solve the problem of finding the area of each rectangle (and one parallelogram), we will use the formula for the area of a rectangle:
\[
\text{Area} = \text{length} \times \text{width}
\]
For the parallelogram, we will use the formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
Let's solve each problem step by step.
---
Problem 1:
- Dimensions: \(9 \, \text{cm}\) and \(7 \, \text{cm}\)
- Area:
\[
\text{Area} = 9 \, \text{cm} \times 7 \, \text{cm} = 63 \, \text{cm}^2
\]
Problem 2:
- Dimensions: \(4 \, \text{mm}\) and \(8 \, \text{mm}\)
- Area:
\[
\text{Area} = 4 \, \text{mm} \times 8 \, \text{mm} = 32 \, \text{mm}^2
\]
Problem 3:
- Dimensions: \(6 \, \text{km}\) and \(3 \, \text{km}\)
- Area:
\[
\text{Area} = 6 \, \text{km} \times 3 \, \text{km} = 18 \, \text{km}^2
\]
Problem 4:
- Dimensions: \(15 \, \text{in}\) and \(5 \, \text{in}\)
- Area:
\[
\text{Area} = 15 \, \text{in} \times 5 \, \text{in} = 75 \, \text{in}^2
\]
Problem 5:
- This is a parallelogram with base \(11 \, \text{ft}\) and height \(7 \, \text{ft}\).
- Area:
\[
\text{Area} = 11 \, \text{ft} \times 7 \, \text{ft} = 77 \, \text{ft}^2
\]
Problem 6:
- Dimensions: \(5 \, \text{yd}\) and \(9 \, \text{yd}\)
- Area:
\[
\text{Area} = 5 \, \text{yd} \times 9 \, \text{yd} = 45 \, \text{yd}^2
\]
Problem 7:
- Dimensions: \(12 \, \text{km}\) and \(6 \, \text{km}\)
- Area:
\[
\text{Area} = 12 \, \text{km} \times 6 \, \text{km} = 72 \, \text{km}^2
\]
Problem 8:
- Dimensions: \(6 \, \text{m}\) and \(5 \, \text{m}\)
- Area:
\[
\text{Area} = 6 \, \text{m} \times 5 \, \text{m} = 30 \, \text{m}^2
\]
---
Final Answers:
\[
\boxed{
\begin{array}{ll}
1. & 63 \, \text{cm}^2 \\
2. & 32 \, \text{mm}^2 \\
3. & 18 \, \text{km}^2 \\
4. & 75 \, \text{in}^2 \\
5. & 77 \, \text{ft}^2 \\
6. & 45 \, \text{yd}^2 \\
7. & 72 \, \text{km}^2 \\
8. & 30 \, \text{m}^2 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of finding the area worksheet.
