Force and Momentum Problems Worksheet | PDF - Free Printable

Here is the completed Force and Momentum Problems Worksheet with full solutions, explanations, and boxed final answers.

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## ✔ Part 1: Complete the Data Table

| Measurement | Unit | Measurement | Unit |
|-------------|------------|-------------|--------------|
| Mass | kg | Time | s |
| Momentum | kg·m/s | Acceleration| m/s² |
| Distance | m | Velocity | m/s |
| Force | N (Newton) | Weight | N (Newton) |

> Note: Weight is a force, so its unit is Newtons (N), not kg. It’s calculated as `Weight = m × g`, where `g ≈ 9.8 m/s²`.

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## ✔ Part 2: Solve the Problems (SHOW YOUR WORK)

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Problem 1:

> How much force is needed to accelerate a 100 kg mass at a rate of 2.5 m/s²?

Formula:
`F = m × a`

Plug in values:
`F = 100 kg × 2.5 m/s² = 250 N`

✔ Answer: $\boxed{250 \text{ N}}$

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Problem 2:

> What is the force acting on a 0.5 kg object moving at a rate of 100 m/s²?

Formula:
`F = m × a`

Plug in values:
`F = 0.5 kg × 100 m/s² = 50 N`

✔ Answer: $\boxed{50 \text{ N}}$

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Problem 3:

> What is the mass of an object that is accelerating at a rate of 25 m/s² and is using 15 N of force?

Formula:
`F = m × a` → Rearranged: `m = F / a`

Plug in values:
`m = 15 N / 25 m/s² = 0.6 kg`

✔ Answer: $\boxed{0.6 \text{ kg}}$

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Problem 4:

> Timmy pushes off of the pool wall with a force of 2300 N and accelerates at 15 m/s², what is Timmy’s mass? (ignore water resistance)

Formula:
`F = m × a` → `m = F / a`

Plug in values:
`m = 2300 N / 15 m/s² ≈ 153.33 kg`

✔ Answer: $\boxed{153.3 \text{ kg}}$ (rounded to one decimal place)

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Problem 5:

> Tonya uses a 418 N force to move a 56 kg mass, at what rate does the object accelerate?

Formula:
`F = m × a` → `a = F / m`

Plug in values:
`a = 418 N / 56 kg ≈ 7.46 m/s²`

✔ Answer: $\boxed{7.46 \text{ m/s}^2}$

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Problem 6:

> How much momentum does a 25 kg mass moving at 25 m/s have?

Formula:
`p = m × v`

Plug in values:
`p = 25 kg × 25 m/s = 625 kg·m/s`

✔ Answer: $\boxed{625 \text{ kg·m/s}}$

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Problem 7:

> How much momentum does a stationary 5500 kg mass have?

Explanation:
Stationary means velocity `v = 0 m/s`

Formula:
`p = m × v = 5500 kg × 0 m/s = 0 kg·m/s`

✔ Answer: $\boxed{0 \text{ kg·m/s}}$

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Problem 8:

> What is the velocity of a 5.5 kg object that has a momentum of 550 kg·m/s?

Formula:
`p = m × v` → `v = p / m`

Plug in values:
`v = 550 kg·m/s / 5.5 kg = 100 m/s`

✔ Answer: $\boxed{100 \text{ m/s}}$

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Problem 9:

> Compare the momentums of a 50 kg dolphin swimming at 16.4 m/s and a 4100 kg elephant walking 0.20 m/s.

Calculate each momentum:

- Dolphin:
`p = 50 kg × 16.4 m/s = 820 kg·m/s`

- Elephant:
`p = 4100 kg × 0.20 m/s = 820 kg·m/s`

✔ Answer: Both have the same momentum: $\boxed{820 \text{ kg·m/s}}$

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Problem 10:

> An object has a momentum of 55 kg·m/s and hits a stationary object making the second object start to move. If the first object ends with a momentum of 13 kg·m/s, what is the momentum of the second object?

Principle: Conservation of Momentum
Total momentum before collision = Total momentum after collision

Before:
- Object 1: 55 kg·m/s
- Object 2: 0 kg·m/s (stationary)
→ Total initial momentum = 55 kg·m/s

After:
- Object 1: 13 kg·m/s
- Object 2: ? (let’s call it `p₂`)
→ Total final momentum = 13 + p₂

Set equal:
`55 = 13 + p₂`
→ `p₂ = 55 - 13 = 42 kg·m/s`

✔ Answer: $\boxed{42 \text{ kg·m/s}}$

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## 🎯 Final Summary:

All problems solved using Newton’s Second Law (`F = ma`) and Momentum formula (`p = mv`), plus conservation of momentum for Problem 10.

Let me know if you’d like diagrams or further explanations!