Solved Net Force Worksheet The force that results from all | Chegg.com - Free Printable

Let's solve each problem step by step. The net force is the vector sum of all forces acting on an object. Since all forces are along a straight line (left or right), we can assign:

- Right as positive (+)
- Left as negative (−)

We’ll add up the forces accordingly and determine the net force, including direction.

---

1.

```
4 N ← [ ]
```
- Only one force: 4 N to the left → −4 N
- Net Force: −4 N → 4 N to the left

---

2.

```
7 N ← [ ] → 2 N
```
- Left: −7 N
- Right: +2 N
- Net = −7 + 2 = −5 N
- Net Force: 5 N to the left

---

3.

```
4 N → [ ] ← 4 N
```
- Right: +4 N
- Left: −4 N
- Net = 4 − 4 = 0 N
- Net Force: 0 N (no net force)

---

4.

```
6 N → [ ] → 3 N
```
- Both to the right: +6 + 3 = +9 N
- Net Force: 9 N to the right

---

5.

```
8 N ← [ ] → 4 N
```
- Left: −8 N
- Right: +4 N
- Net = −8 + 4 = −4 N
- Net Force: 4 N to the left

---

6.

```
4 N → [ ] ← 5 N
```
- Right: +4 N
- Left: −5 N
- Net = 4 − 5 = −1 N
- Net Force: 1 N to the left

---

7.

```
[ ] ← 3 N
← 3 N
```
- Two forces to the left: −3 N and −3 N
- Net = −3 − 3 = −6 N
- Net Force: 6 N to the left

---

8.

```
2 N → [ ] ← 5 N
4 N →
```
- Right: +2 N and +4 N → total +6 N
- Left: −5 N
- Net = 6 − 5 = +1 N
- Net Force: 1 N to the right

---

9.

```
6 N ← [ ] → 3 N
↑
3 N →
```
Wait — actually, it shows:
```
6 N ← [ ] → 3 N
↓
3 N →
```
But this seems like two forces to the right: 3 N and 3 N? Let’s clarify.

Looking at the diagram:
- One arrow pointing left: 6 N
- Two arrows pointing right: 3 N and 3 N? Or just one?

Actually, based on standard formatting in such worksheets, likely:
- 6 N to the left
- 3 N to the right
- Another 3 N to the right?

But the image shows:
```
6 N ← [ ] → 3 N
↓
3 N →
```

So:
- Left: −6 N
- Right: +3 N (from top) + 3 N (from bottom) = +6 N
- Net = −6 + 6 = 0 N
- Net Force: 0 N

Wait — but the downward arrow might be ambiguous.

Alternatively, maybe it's:
- A single 3 N to the right, and another 3 N to the right? But that would be redundant.

But if both forces on the right are 3 N each, then yes, total right = 6 N.

So:
- Left: −6 N
- Right: +3 N + 3 N = +6 N
- Net = 0 N
- Net Force: 0 N

But let's assume the diagram has:
- 6 N to the left
- 3 N to the right
- And another 3 N to the right (from below)

Yes, so total right = 6 N, left = 6 N → balanced.

✔ Net Force: 0 N

---

10.

```
7 N ← [ ] → 4 N
↑
4 N →
```
Wait — again, looks like:
- 7 N to the left
- 4 N to the right (top)
- 4 N to the right (bottom)

So:
- Left: −7 N
- Right: +4 + 4 = +8 N
- Net = −7 + 8 = +1 N
- Net Force: 1 N to the right

---

✔ Final Answers:

| Problem | Net Force |
|--------|-----------|
| 1 | 4 N to the left |
| 2 | 5 N to the left |
| 3 | 0 N |
| 4 | 9 N to the right |
| 5 | 4 N to the left |
| 6 | 1 N to the left |
| 7 | 6 N to the left |
| 8 | 1 N to the right |
| 9 | 0 N |
| 10 | 1 N to the right |

---

🔍 Summary of How to Solve:

1. Assign signs: Right = +, Left = −
2. Add all forces algebraically.
3. If result is positive → net force to the right
4. If negative → net force to the left
5. If zero → no net force (balanced)

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