CHEMISTRY COMPUTING FORMULA MASS WORKSHEET - Flipbook by | FlipHTML5 - Free Printable
Educational worksheet: CHEMISTRY COMPUTING FORMULA MASS WORKSHEET - Flipbook by | FlipHTML5. Download and print for classroom or home learning activities.
WEBP
1391×1800
78 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1599215
⭐
Show Answer Key & Explanations
Step-by-step solution for: CHEMISTRY COMPUTING FORMULA MASS WORKSHEET - Flipbook by | FlipHTML5
▼
Show Answer Key & Explanations
Step-by-step solution for: CHEMISTRY COMPUTING FORMULA MASS WORKSHEET - Flipbook by | FlipHTML5
Let’s solve each compound step by step. We’ll find the formula mass by adding up the atomic masses of all atoms in the formula, rounded to the tenth (one decimal place).
We’ll use these approximate atomic masses (rounded to tenths as instructed):
- Ag = 107.9
- N = 14.0
- O = 16.0
- Ni = 58.7
- S = 32.1
- Ca = 40.1
- P = 31.0
- Hg = 200.6
- Fe = 55.8
- K = 39.1
- Br = 79.9
- Be = 9.0
- Cr = 52.0
- Co = 58.9
- Cl = 35.5
- Cu = 63.5
- C = 12.0
- H = 1.0
- Zn = 65.4
- Al = 27.0
- Mg = 24.3
- Na = 23.0
---
Left Column:
1. AgNO₂
Ag: 1 × 107.9 = 107.9
N: 1 × 14.0 = 14.0
O: 2 × 16.0 = 32.0
Total = 107.9 + 14.0 + 32.0 = 153.9
2. NiSO₃
Ni: 1 × 58.7 = 58.7
S: 1 × 32.1 = 32.1
O: 3 × 16.0 = 48.0
Total = 58.7 + 32.1 + 48.0 = 138.8
3. Ca₃(PO₄)₂ → This means 3 Ca, 2 P, 8 O
Ca: 3 × 40.1 = 120.3
P: 2 × 31.0 = 62.0
O: 8 × 16.0 = 128.0
Total = 120.3 + 62.0 + 128.0 = 310.3
4. HgSO₄
Hg: 1 × 200.6 = 200.6
S: 1 × 32.1 = 32.1
O: 4 × 16.0 = 64.0
Total = 200.6 + 32.1 + 64.0 = 296.7
5. Fe(NO₃)₃ → 1 Fe, 3 N, 9 O
Fe: 1 × 55.8 = 55.8
N: 3 × 14.0 = 42.0
O: 9 × 16.0 = 144.0
Total = 55.8 + 42.0 + 144.0 = 241.8
6. KBr
K: 1 × 39.1 = 39.1
Br: 1 × 79.9 = 79.9
Total = 39.1 + 79.9 = 119.0
7. BeCr₂O₇
Be: 1 × 9.0 = 9.0
Cr: 2 × 52.0 = 104.0
O: 7 × 16.0 = 112.0
Total = 9.0 + 104.0 + 112.0 = 225.0
8. Co(ClO₃)₂ → 1 Co, 2 Cl, 6 O
Co: 1 × 58.9 = 58.9
Cl: 2 × 35.5 = 71.0
O: 6 × 16.0 = 96.0
Total = 58.9 + 71.0 + 96.0 = 225.9
9. Cu₂C₄H₄O₆
Cu: 2 × 63.5 = 127.0
C: 4 × 12.0 = 48.0
H: 4 × 1.0 = 4.0
O: 6 × 16.0 = 96.0
Total = 127.0 + 48.0 + 4.0 + 96.0 = 275.0
10. CuSO₄ · 7 H₂O → This is a hydrate. Add water molecules too.
First, CuSO₄:
Cu: 63.5
S: 32.1
O: 4 × 16.0 = 64.0 → subtotal = 63.5 + 32.1 + 64.0 = 159.6
Then 7 H₂O:
Each H₂O = 2×1.0 + 16.0 = 18.0
7 × 18.0 = 126.0
Total = 159.6 + 126.0 = 285.6
---
Right Column:
11. ZnCl₂
Zn: 1 × 65.4 = 65.4
Cl: 2 × 35.5 = 71.0
Total = 65.4 + 71.0 = 136.4
12. K₃PO₄
K: 3 × 39.1 = 117.3
P: 1 × 31.0 = 31.0
O: 4 × 16.0 = 64.0
Total = 117.3 + 31.0 + 64.0 = 212.3
13. Al₂(SO₄)₃ → 2 Al, 3 S, 12 O
Al: 2 × 27.0 = 54.0
S: 3 × 32.1 = 96.3
O: 12 × 16.0 = 192.0
Total = 54.0 + 96.3 + 192.0 = 342.3
14. MgCrO₄
Mg: 1 × 24.3 = 24.3
Cr: 1 × 52.0 = 52.0
O: 4 × 16.0 = 64.0
Total = 24.3 + 52.0 + 64.0 = 140.3
15. CaC₄H₄O₆
Ca: 1 × 40.1 = 40.1
C: 4 × 12.0 = 48.0
H: 4 × 1.0 = 4.0
O: 6 × 16.0 = 96.0
Total = 40.1 + 48.0 + 4.0 + 96.0 = 188.1
16. NaCl
Na: 1 × 23.0 = 23.0
Cl: 1 × 35.5 = 35.5
Total = 23.0 + 35.5 = 58.5
17. K₂Cr₂O₇
K: 2 × 39.1 = 78.2
Cr: 2 × 52.0 = 104.0
O: 7 × 16.0 = 112.0
Total = 78.2 + 104.0 + 112.0 = 294.2
18. H₂SO₄
H: 2 × 1.0 = 2.0
S: 1 × 32.1 = 32.1
O: 4 × 16.0 = 64.0
Total = 2.0 + 32.1 + 64.0 = 98.1
19. Cu(OH)₂ → 1 Cu, 2 O, 2 H (but OH group counted twice)
Actually: Cu, 2 O, 2 H — but let’s break it down:
Cu: 63.5
O: 2 × 16.0 = 32.0
H: 2 × 1.0 = 2.0
Total = 63.5 + 32.0 + 2.0 = 97.5
20. MgSO₄ · 5 H₂O
MgSO₄:
Mg: 24.3
S: 32.1
O: 4 × 16.0 = 64.0 → subtotal = 24.3 + 32.1 + 64.0 = 120.4
5 H₂O: 5 × 18.0 = 90.0
Total = 120.4 + 90.0 = 210.4
---
Final Answer:
COMPOUND FORMULA MASS
AgNO2 153.9
NiSO3 138.8
Ca3(PO4)2 310.3
HgSO4 296.7
Fe(NO3)3 241.8
KBr 119.0
BeCr2O7 225.0
Co(ClO3)2 225.9
Cu2C4H4O6 275.0
CuSO4 · 7 H2O 285.6
ZnCl2 136.4
K3PO4 212.3
Al2(SO4)3 342.3
MgCrO4 140.3
CaC4H4O6 188.1
NaCl 58.5
K2Cr2O7 294.2
H2SO4 98.1
Cu(OH)2 97.5
MgSO4 · 5 H2O 210.4
We’ll use these approximate atomic masses (rounded to tenths as instructed):
- Ag = 107.9
- N = 14.0
- O = 16.0
- Ni = 58.7
- S = 32.1
- Ca = 40.1
- P = 31.0
- Hg = 200.6
- Fe = 55.8
- K = 39.1
- Br = 79.9
- Be = 9.0
- Cr = 52.0
- Co = 58.9
- Cl = 35.5
- Cu = 63.5
- C = 12.0
- H = 1.0
- Zn = 65.4
- Al = 27.0
- Mg = 24.3
- Na = 23.0
---
Left Column:
1. AgNO₂
Ag: 1 × 107.9 = 107.9
N: 1 × 14.0 = 14.0
O: 2 × 16.0 = 32.0
Total = 107.9 + 14.0 + 32.0 = 153.9
2. NiSO₃
Ni: 1 × 58.7 = 58.7
S: 1 × 32.1 = 32.1
O: 3 × 16.0 = 48.0
Total = 58.7 + 32.1 + 48.0 = 138.8
3. Ca₃(PO₄)₂ → This means 3 Ca, 2 P, 8 O
Ca: 3 × 40.1 = 120.3
P: 2 × 31.0 = 62.0
O: 8 × 16.0 = 128.0
Total = 120.3 + 62.0 + 128.0 = 310.3
4. HgSO₄
Hg: 1 × 200.6 = 200.6
S: 1 × 32.1 = 32.1
O: 4 × 16.0 = 64.0
Total = 200.6 + 32.1 + 64.0 = 296.7
5. Fe(NO₃)₃ → 1 Fe, 3 N, 9 O
Fe: 1 × 55.8 = 55.8
N: 3 × 14.0 = 42.0
O: 9 × 16.0 = 144.0
Total = 55.8 + 42.0 + 144.0 = 241.8
6. KBr
K: 1 × 39.1 = 39.1
Br: 1 × 79.9 = 79.9
Total = 39.1 + 79.9 = 119.0
7. BeCr₂O₇
Be: 1 × 9.0 = 9.0
Cr: 2 × 52.0 = 104.0
O: 7 × 16.0 = 112.0
Total = 9.0 + 104.0 + 112.0 = 225.0
8. Co(ClO₃)₂ → 1 Co, 2 Cl, 6 O
Co: 1 × 58.9 = 58.9
Cl: 2 × 35.5 = 71.0
O: 6 × 16.0 = 96.0
Total = 58.9 + 71.0 + 96.0 = 225.9
9. Cu₂C₄H₄O₆
Cu: 2 × 63.5 = 127.0
C: 4 × 12.0 = 48.0
H: 4 × 1.0 = 4.0
O: 6 × 16.0 = 96.0
Total = 127.0 + 48.0 + 4.0 + 96.0 = 275.0
10. CuSO₄ · 7 H₂O → This is a hydrate. Add water molecules too.
First, CuSO₄:
Cu: 63.5
S: 32.1
O: 4 × 16.0 = 64.0 → subtotal = 63.5 + 32.1 + 64.0 = 159.6
Then 7 H₂O:
Each H₂O = 2×1.0 + 16.0 = 18.0
7 × 18.0 = 126.0
Total = 159.6 + 126.0 = 285.6
---
Right Column:
11. ZnCl₂
Zn: 1 × 65.4 = 65.4
Cl: 2 × 35.5 = 71.0
Total = 65.4 + 71.0 = 136.4
12. K₃PO₄
K: 3 × 39.1 = 117.3
P: 1 × 31.0 = 31.0
O: 4 × 16.0 = 64.0
Total = 117.3 + 31.0 + 64.0 = 212.3
13. Al₂(SO₄)₃ → 2 Al, 3 S, 12 O
Al: 2 × 27.0 = 54.0
S: 3 × 32.1 = 96.3
O: 12 × 16.0 = 192.0
Total = 54.0 + 96.3 + 192.0 = 342.3
14. MgCrO₄
Mg: 1 × 24.3 = 24.3
Cr: 1 × 52.0 = 52.0
O: 4 × 16.0 = 64.0
Total = 24.3 + 52.0 + 64.0 = 140.3
15. CaC₄H₄O₆
Ca: 1 × 40.1 = 40.1
C: 4 × 12.0 = 48.0
H: 4 × 1.0 = 4.0
O: 6 × 16.0 = 96.0
Total = 40.1 + 48.0 + 4.0 + 96.0 = 188.1
16. NaCl
Na: 1 × 23.0 = 23.0
Cl: 1 × 35.5 = 35.5
Total = 23.0 + 35.5 = 58.5
17. K₂Cr₂O₇
K: 2 × 39.1 = 78.2
Cr: 2 × 52.0 = 104.0
O: 7 × 16.0 = 112.0
Total = 78.2 + 104.0 + 112.0 = 294.2
18. H₂SO₄
H: 2 × 1.0 = 2.0
S: 1 × 32.1 = 32.1
O: 4 × 16.0 = 64.0
Total = 2.0 + 32.1 + 64.0 = 98.1
19. Cu(OH)₂ → 1 Cu, 2 O, 2 H (but OH group counted twice)
Actually: Cu, 2 O, 2 H — but let’s break it down:
Cu: 63.5
O: 2 × 16.0 = 32.0
H: 2 × 1.0 = 2.0
Total = 63.5 + 32.0 + 2.0 = 97.5
20. MgSO₄ · 5 H₂O
MgSO₄:
Mg: 24.3
S: 32.1
O: 4 × 16.0 = 64.0 → subtotal = 24.3 + 32.1 + 64.0 = 120.4
5 H₂O: 5 × 18.0 = 90.0
Total = 120.4 + 90.0 = 210.4
---
Final Answer:
COMPOUND FORMULA MASS
AgNO2 153.9
NiSO3 138.8
Ca3(PO4)2 310.3
HgSO4 296.7
Fe(NO3)3 241.8
KBr 119.0
BeCr2O7 225.0
Co(ClO3)2 225.9
Cu2C4H4O6 275.0
CuSO4 · 7 H2O 285.6
ZnCl2 136.4
K3PO4 212.3
Al2(SO4)3 342.3
MgCrO4 140.3
CaC4H4O6 188.1
NaCl 58.5
K2Cr2O7 294.2
H2SO4 98.1
Cu(OH)2 97.5
MgSO4 · 5 H2O 210.4
Parent Tip: Review the logic above to help your child master the concept of formula or molar mass worksheet.
