Printable math worksheet for practicing fraction equivalence by filling in missing numbers.

The task involves filling in the missing numbers in equivalent fractions. The goal is to ensure that each fraction on the left side of the equation is equal to the fraction on the right side. This requires understanding how to create equivalent fractions by multiplying or dividing both the numerator and the denominator by the same number.

Let's solve each problem step by step:

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Problem 1:

$$
\frac{1}{4} = \frac{\square}{20}
$$

- To find the missing numerator, we need to determine what number, when multiplied by 4 (the denominator on the left), gives us 20 (the denominator on the right).
- \( 4 \times 5 = 20 \), so we multiply both the numerator and the denominator of \( \frac{1}{4} \) by 5.
- \( \frac{1 \times 5}{4 \times 5} = \frac{5}{20} \).

Thus, the missing number is:
$$
\boxed{5}
$$

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Problem 2:

$$
\frac{17}{24} = \frac{\square}{72}
$$

- To find the missing numerator, we need to determine what number, when multiplied by 24 (the denominator on the left), gives us 72 (the denominator on the right).
- \( 24 \times 3 = 72 \), so we multiply both the numerator and the denominator of \( \frac{17}{24} \) by 3.
- \( \frac{17 \times 3}{24 \times 3} = \frac{51}{72} \).

Thus, the missing number is:
$$
\boxed{51}
$$

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Problem 3:

$$
\frac{9}{18} = \frac{\square}{36}
$$

- To find the missing numerator, we need to determine what number, when multiplied by 18 (the denominator on the left), gives us 36 (the denominator on the right).
- \( 18 \times 2 = 36 \), so we multiply both the numerator and the denominator of \( \frac{9}{18} \) by 2.
- \( \frac{9 \times 2}{18 \times 2} = \frac{18}{36} \).

Thus, the missing number is:
$$
\boxed{18}
$$

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Problem 4:

$$
\frac{2}{5} = \frac{\square}{25}
$$

- To find the missing numerator, we need to determine what number, when multiplied by 5 (the denominator on the left), gives us 25 (the denominator on the right).
- \( 5 \times 5 = 25 \), so we multiply both the numerator and the denominator of \( \frac{2}{5} \) by 5.
- \( \frac{2 \times 5}{5 \times 5} = \frac{10}{25} \).

Thus, the missing number is:
$$
\boxed{10}
$$

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Problem 5:

$$
\frac{1}{16} = \frac{\square}{32}
$$

- To find the missing numerator, we need to determine what number, when multiplied by 16 (the denominator on the left), gives us 32 (the denominator on the right).
- \( 16 \times 2 = 32 \), so we multiply both the numerator and the denominator of \( \frac{1}{16} \) by 2.
- \( \frac{1 \times 2}{16 \times 2} = \frac{2}{32} \).

Thus, the missing number is:
$$
\boxed{2}
$$

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Problem 6:

$$
\frac{12}{22} = \frac{\square}{11}
$$

- To find the missing numerator, we need to determine what number, when divided by 2 (since \( 22 \div 2 = 11 \)), gives us the new denominator.
- We divide both the numerator and the denominator of \( \frac{12}{22} \) by 2.
- \( \frac{12 \div 2}{22 \div 2} = \frac{6}{11} \).

Thus, the missing number is:
$$
\boxed{6}
$$

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Problem 7:

$$
\frac{6}{21} = \frac{\square}{7}
$$

- To find the missing numerator, we need to determine what number, when divided by 3 (since \( 21 \div 3 = 7 \)), gives us the new denominator.
- We divide both the numerator and the denominator of \( \frac{6}{21} \) by 3.
- \( \frac{6 \div 3}{21 \div 3} = \frac{2}{7} \).

Thus, the missing number is:
$$
\boxed{2}
$$

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Final Answer:

$$
\boxed{5, 51, 18, 10, 2, 6, 2}
$$