Fraction multiplication practice problems.

To solve the given problems, we need to multiply the fractions step by step. The general rule for multiplying fractions is:

\[
\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}
\]

After multiplying, we simplify the resulting fraction if possible.

Let's solve each problem one by one:

---

(m) $\frac{2}{7} \times \frac{3}{4}$

\[
\frac{2}{7} \times \frac{3}{4} = \frac{2 \times 3}{7 \times 4} = \frac{6}{28}
\]

Simplify $\frac{6}{28}$ by dividing the numerator and the denominator by their greatest common divisor (GCD), which is 2:

\[
\frac{6 \div 2}{28 \div 2} = \frac{3}{14}
\]

So, the answer is:

\[
\boxed{\frac{3}{14}}
\]

---

(n) $\frac{5}{7} \times \frac{1}{10}$

\[
\frac{5}{7} \times \frac{1}{10} = \frac{5 \times 1}{7 \times 10} = \frac{5}{70}
\]

Simplify $\frac{5}{70}$ by dividing the numerator and the denominator by their GCD, which is 5:

\[
\frac{5 \div 5}{70 \div 5} = \frac{1}{14}
\]

So, the answer is:

\[
\boxed{\frac{1}{14}}
\]

---

(o) $\frac{7}{12} \times \frac{2}{3}$

\[
\frac{7}{12} \times \frac{2}{3} = \frac{7 \times 2}{12 \times 3} = \frac{14}{36}
\]

Simplify $\frac{14}{36}$ by dividing the numerator and the denominator by their GCD, which is 2:

\[
\frac{14 \div 2}{36 \div 2} = \frac{7}{18}
\]

So, the answer is:

\[
\boxed{\frac{7}{18}}
\]

---

(p) $\frac{6}{7} \times \frac{2}{3}$

\[
\frac{6}{7} \times \frac{2}{3} = \frac{6 \times 2}{7 \times 3} = \frac{12}{21}
\]

Simplify $\frac{12}{21}$ by dividing the numerator and the denominator by their GCD, which is 3:

\[
\frac{12 \div 3}{21 \div 3} = \frac{4}{7}
\]

So, the answer is:

\[
\boxed{\frac{4}{7}}
\]

---

(q) $\frac{6}{7} \times \frac{2}{9}$

\[
\frac{6}{7} \times \frac{2}{9} = \frac{6 \times 2}{7 \times 9} = \frac{12}{63}
\]

Simplify $\frac{12}{63}$ by dividing the numerator and the denominator by their GCD, which is 3:

\[
\frac{12 \div 3}{63 \div 3} = \frac{4}{21}
\]

So, the answer is:

\[
\boxed{\frac{4}{21}}
\]

---

(r) $\frac{3}{10} \times \frac{5}{6}$

\[
\frac{3}{10} \times \frac{5}{6} = \frac{3 \times 5}{10 \times 6} = \frac{15}{60}
\]

Simplify $\frac{15}{60}$ by dividing the numerator and the denominator by their GCD, which is 15:

\[
\frac{15 \div 15}{60 \div 15} = \frac{1}{4}
\]

So, the answer is:

\[
\boxed{\frac{1}{4}}
\]

---

(s) $\frac{6}{15} \times \frac{3}{4}$

\[
\frac{6}{15} \times \frac{3}{4} = \frac{6 \times 3}{15 \times 4} = \frac{18}{60}
\]

Simplify $\frac{18}{60}$ by dividing the numerator and the denominator by their GCD, which is 6:

\[
\frac{18 \div 6}{60 \div 6} = \frac{3}{10}
\]

So, the answer is:

\[
\boxed{\frac{3}{10}}
\]

---

(t) $\frac{3}{5} \times \frac{11}{15}$

\[
\frac{3}{5} \times \frac{11}{15} = \frac{3 \times 11}{5 \times 15} = \frac{33}{75}
\]

Simplify $\frac{33}{75}$ by dividing the numerator and the denominator by their GCD, which is 3:

\[
\frac{33 \div 3}{75 \div 3} = \frac{11}{25}
\]

So, the answer is:

\[
\boxed{\frac{11}{25}}
\]

---

(u) $\frac{9}{20} \times \frac{10}{11}$

\[
\frac{9}{20} \times \frac{10}{11} = \frac{9 \times 10}{20 \times 11} = \frac{90}{220}
\]

Simplify $\frac{90}{220}$ by dividing the numerator and the denominator by their GCD, which is 10:

\[
\frac{90 \div 10}{220 \div 10} = \frac{9}{22}
\]

So, the answer is:

\[
\boxed{\frac{9}{22}}
\]

---

(v) $\frac{21}{30} \times \frac{2}{3}$

\[
\frac{21}{30} \times \frac{2}{3} = \frac{21 \times 2}{30 \times 3} = \frac{42}{90}
\]

Simplify $\frac{42}{90}$ by dividing the numerator and the denominator by their GCD, which is 6:

\[
\frac{42 \div 6}{90 \div 6} = \frac{7}{15}
\]

So, the answer is:

\[
\boxed{\frac{7}{15}}
\]

---

(w) $\frac{12}{25} \times \frac{5}{8}$

\[
\frac{12}{25} \times \frac{5}{8} = \frac{12 \times 5}{25 \times 8} = \frac{60}{200}
\]

Simplify $\frac{60}{200}$ by dividing the numerator and the denominator by their GCD, which is 20:

\[
\frac{60 \div 20}{200 \div 20} = \frac{3}{10}
\]

So, the answer is:

\[
\boxed{\frac{3}{10}}
\]

---

(x) $\frac{8}{9} \times \frac{3}{16}$

\[
\frac{8}{9} \times \frac{3}{16} = \frac{8 \times 3}{9 \times 16} = \frac{24}{144}
\]

Simplify $\frac{24}{144}$ by dividing the numerator and the denominator by their GCD, which is 24:

\[
\frac{24 \div 24}{144 \div 24} = \frac{1}{6}
\]

So, the answer is:

\[
\boxed{\frac{1}{6}}
\]

---

Final Answers:

\[
\boxed{\frac{3}{14}, \frac{1}{14}, \frac{7}{18}, \frac{4}{7}, \frac{4}{21}, \frac{1}{4}, \frac{3}{10}, \frac{11}{25}, \frac{9}{22}, \frac{7}{15}, \frac{3}{10}, \frac{1}{6}}
\]