Printable worksheet titled "Equivalent Fractions Word Problems" featuring five real-world math scenarios for students to solve using fractions.

Problem 1:

Aunt Sue baked a batch of cookies and shared \(\frac{3}{10}\) of them with her neighbor. If she gave 15 cookies to her neighbor, how many cookies had Aunt Sue baked altogether?

#### Solution:
Let the total number of cookies Aunt Sue baked be \( x \).

According to the problem, Aunt Sue gave \(\frac{3}{10}\) of the cookies to her neighbor, which is equal to 15 cookies. Therefore, we can write the equation:
\[
\frac{3}{10} \cdot x = 15
\]

To solve for \( x \), multiply both sides of the equation by the reciprocal of \(\frac{3}{10}\), which is \(\frac{10}{3}\):
\[
x = 15 \cdot \frac{10}{3}
\]

Simplify the right-hand side:
\[
x = \frac{15 \cdot 10}{3} = \frac{150}{3} = 50
\]

Thus, Aunt Sue baked a total of \( 50 \) cookies.

#### Final Answer:
\[
\boxed{50}
\]

---

Problem 2:

At school, the teacher surveyed the color preferences of 21 students. Out of every 7 students surveyed, 4 said they liked blue the best. How many students said their favorite color was blue?

#### Solution:
We are given that out of every 7 students, 4 liked blue. This means the fraction of students who liked blue is:
\[
\frac{4}{7}
\]

The total number of students surveyed is 21. To find how many students liked blue, we calculate:
\[
\text{Number of students who liked blue} = \frac{4}{7} \cdot 21
\]

Simplify the expression:
\[
\frac{4}{7} \cdot 21 = \frac{4 \cdot 21}{7} = \frac{84}{7} = 12
\]

Thus, 12 students said their favorite color was blue.

#### Final Answer:
\[
\boxed{12}
\]

---

Problem 3:

A home improvement store in Ohio had some great deals on garden supplies. If 81 customers visited the store in the morning and \(\frac{5}{9}\) of them picked up garden tools, how many customers bought garden tools?

#### Solution:
The total number of customers who visited the store is 81. According to the problem, \(\frac{5}{9}\) of these customers bought garden tools. Therefore, we calculate:
\[
\text{Number of customers who bought garden tools} = \frac{5}{9} \cdot 81
\]

Simplify the expression:
\[
\frac{5}{9} \cdot 81 = \frac{5 \cdot 81}{9} = \frac{405}{9} = 45
\]

Thus, 45 customers bought garden tools.

#### Final Answer:
\[
\boxed{45}
\]

---

Problem 4:

Mark bought gift tokens for his daughter, Sally, to use at the state fair. Sally used \(\frac{13}{20}\) of the tokens on rides. If she used 65 tokens, how many tokens had Mark bought?

#### Solution:
Let the total number of tokens Mark bought be \( x \).

According to the problem, Sally used \(\frac{13}{20}\) of the tokens, which is equal to 65 tokens. Therefore, we can write the equation:
\[
\frac{13}{20} \cdot x = 65
\]

To solve for \( x \), multiply both sides of the equation by the reciprocal of \(\frac{13}{20}\), which is \(\frac{20}{13}\):
\[
x = 65 \cdot \frac{20}{13}
\]

Simplify the right-hand side:
\[
x = \frac{65 \cdot 20}{13} = \frac{1300}{13} = 100
\]

Thus, Mark bought a total of \( 100 \) tokens.

#### Final Answer:
\[
\boxed{100}
\]

---

Problem 5:

Mia blends biking and running into her training plan. She dedicates \(\frac{2}{7}\) of her everyday workout to biking. If she exercises for 49 minutes every day, how many minutes does she bike?

#### Solution:
The total time Mia exercises each day is 49 minutes. According to the problem, she dedicates \(\frac{2}{7}\) of this time to biking. Therefore, we calculate:
\[
\text{Time spent biking} = \frac{2}{7} \cdot 49
\]

Simplify the expression:
\[
\frac{2}{7} \cdot 49 = \frac{2 \cdot 49}{7} = \frac{98}{7} = 14
\]

Thus, Mia bikes for 14 minutes each day.

#### Final Answer:
\[
\boxed{14}
\]

---

Final Answers:

1. \(\boxed{50}\)
2. \(\boxed{12}\)
3. \(\boxed{45}\)
4. \(\boxed{100}\)
5. \(\boxed{14}\)