Grade 4 Division Worksheet 3: Solve the equation with long division problems.

Let’s solve each division problem step by step. We’ll divide the big number (dividend) by the small number (divisor) and find how many times the divisor fits into the dividend — that’s the quotient. Sometimes there’s a leftover amount called the remainder.

We’ll go one by one:

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1. 648 ÷ 8

8 × 80 = 640 → 648 - 640 = 8 → 8 ÷ 8 = 1
So, 80 + 1 = 81

✔ Answer: 81

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2. 945 ÷ 7

7 × 100 = 700 → 945 - 700 = 245
7 × 35 = 245 → So, 100 + 35 = 135

✔ Answer: 135

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3. 864 ÷ 8

8 × 100 = 800 → 864 - 800 = 64
8 × 8 = 64 → So, 100 + 8 = 108

✔ Answer: 108

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4. 714 ÷ 6

6 × 100 = 600 → 714 - 600 = 114
6 × 19 = 114 → So, 100 + 19 = 119

✔ Answer: 119

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5. 952 ÷ 8

8 × 100 = 800 → 952 - 800 = 152
8 × 19 = 152 → So, 100 + 19 = 119

✔ Answer: 119

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6. 369 ÷ 9

9 × 40 = 360 → 369 - 360 = 9 → 9 ÷ 9 = 1
So, 40 + 1 = 41

✔ Answer: 41

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7. 273 ÷ 6

6 × 40 = 240 → 273 - 240 = 33
6 × 5 = 30 → 33 - 30 = 3 → so quotient is 45, remainder 3
But since we’re doing exact division? Wait — let’s check if it divides evenly.

Actually, 6 × 45 = 270 → 273 - 270 = 3 → Not even. But maybe the worksheet expects whole numbers with remainders? Let me recheck instructions.

Looking back: “Solve the equation.” In Grade 4, sometimes they want quotient and remainder, but often in these worksheets, all problems are designed to divide evenly. Did I make a mistake?

Wait — 273 ÷ 6:

Try long division:

6 into 27 → 4 (6×4=24), subtract → 3
Bring down 3 → 33
6 into 33 → 5 (6×5=30), subtract → 3

So answer is 45 R3

But let’s check other problems — maybe some have remainders? Let’s keep going and see.

Actually, looking at problem 14: 179 ÷ 8 — that won’t be even either. So probably, we should write quotient and remainder where needed.

But the instruction says “solve the equation” — in math, that usually means give the full result. Since this is Grade 4, likely they expect quotient and remainder written as “Q R R”.

However, in many such worksheets, they design them to divide evenly. Let me double-check my calculation for #7.

273 ÷ 6:

6 × 45 = 270 → yes, remainder 3.

Okay, so we’ll note remainder when needed.

But wait — let’s look at problem 15: 359 ÷ 7 — 7×51=357, remainder 2.

So yes, some will have remainders.

But in the original image, the format is just the division symbol — no space for remainder. Hmm.

Actually, in standard elementary worksheets like this, if it doesn’t divide evenly, they still expect you to write the quotient and remainder.

But to match what’s expected, perhaps we should do integer division and state remainder.

Alternatively, maybe I made an error — let me verify each with calculator-style thinking.

Actually, let’s proceed carefully and write quotient and remainder where applicable.

But to save time and since the user didn’t specify, and given that most of these actually DO divide evenly except a few, let me recalculate each precisely.

Wait — let me list all answers properly with verification.

I’ll do quick checks:

1. 8 × 81 = 648 ✔
2. 7 × 135 = 945 ✔ (7×130=910, 7×5=35; 910+35=945)
3. 8 × 108 = 864 ✔
4. 6 × 119 = 714 ✔ (6×120=720 minus 6=714)
5. 8 × 119 = 952 ✔ (same as above)
6. 9 × 41 = 369 ✔
7. 6 × 45 = 270 → 273 - 270 = 3 → so 45 R3
8. 4 × 71 = 284 → 287 - 284 = 3 → 71 R3
9. 5 × 171 = 855 → 856 - 855 = 1 → 171 R1
10. 9 × 53 = 477 → 479 - 477 = 2 → 53 R2
11. 8 × 84 = 672 → 673 - 672 = 1 → 84 R1
12. 4 × 64 = 256 → 257 - 256 = 1 → 64 R1
13. 5 × 153 = 765 → 768 - 765 = 3 → 153 R3
14. 8 × 22 = 176 → 179 - 176 = 3 → 22 R3
15. 7 × 51 = 357 → 359 - 357 = 2 → 51 R2

Oh! So only problems 1-6 divide evenly. The rest have remainders.

But in the context of a Grade 4 worksheet titled “Dividing numbers”, and since it says “solve the equation”, it’s safe to assume they want the full answer including remainder if any.

However, looking at the layout — it’s just the division bracket — no place to write remainder. That suggests maybe the worksheet expects only quotients, or perhaps I miscalculated?

Wait — let me check problem 7 again: 273 ÷ 6.

Is 273 divisible by 6? A number is divisible by 6 if divisible by 2 and 3. 273 is odd → not divisible by 2 → so not by 6. Correct, remainder 3.

Similarly, problem 8: 287 ÷ 4 — 287 is odd, 4 requires even last two digits? 87 ÷ 4 = 21.75 → not integer.

So yes, remainders are expected.

But in many such worksheets, they might still write the quotient and mention remainder separately. Since the user hasn't specified format, and to be accurate, I'll provide quotient and remainder for those that don't divide evenly.

However, upon second thought — let me check online or recall: in Freemathworksheets.com Grade 4 Division Worksheet 3, these problems are typically set up to have no remainders? Or do they?

Actually, I can reason: if it's "Grade 4 Division Worksheet 3", and it's from a reputable site, likely all problems are designed to divide evenly. Did I make arithmetic errors?

Let me recompute problem 7: 273 ÷ 6.

Do long division:

6 ) 273

6 into 27: 4, 4×6=24, subtract: 3

Bring down 3: 33

6 into 33: 5, 5×6=30, subtract: 3

So 45 with remainder 3. Correct.

Problem 8: 287 ÷ 4

4 into 28: 7, 7×4=28, subtract: 0

Bring down 7: 7

4 into 7: 1, 1×4=4, subtract: 3 → 71 R3

Same issue.

Perhaps the worksheet allows remainders. To be precise, I'll include them.

But to match common practice in such contexts, and since the user might expect clean answers, let me verify if I misread the numbers.

Looking back at the image description:

Problem 7: 6)273 — yes

Problem 8: 4)287 — yes

etc.

Another idea: perhaps in this worksheet, they want the answer as a mixed number or decimal? Unlikely for Grade 4.

Most likely, they expect quotient and remainder written as "45 R3" or similar.

Since the instruction is to solve accurately, I'll provide the correct mathematical answer for each.

So final answers:

1. 81
2. 135
3. 108
4. 119
5. 119
6. 41
7. 45 R3
8. 71 R3
9. 171 R1
10. 53 R2
11. 84 R1
12. 64 R1
13. 153 R3
14. 22 R3
15. 51 R2

But to confirm, let's see if any of these can be simplified or if I have errors.

For example, problem 9: 856 ÷ 5

5 × 171 = 855, 856 - 855 = 1 → yes, 171 R1

Problem 10: 479 ÷ 9

9 × 53 = 477, 479 - 477 = 2 → 53 R2

All seem correct.

Perhaps the worksheet intends for students to write the quotient only, ignoring remainder, but that would be inaccurate.

Given that, and to be educationally sound, I'll present the full answer.

But in the response format, since it's "Final Answer", and there are 15 problems, I need to list them clearly.

Maybe box each answer.

Since the user said "solve the problem accurately", and there are 15 sub-problems, I'll list all 15 answers with remainders where applicable.

Final decision: Provide quotient and remainder for non-even divisions.

So here are the verified answers:

1. 81
2. 135
3. 108
4. 119
5. 119
6. 41
7. 45 R3
8. 71 R3
9. 171 R1
10. 53 R2
11. 84 R1
12. 64 R1
13. 153 R3
14. 22 R3
15. 51 R2

I think that's accurate.

To present neatly in Final Answer.