The task involves calculating the value of various algebraic expressions given specific values for the variables. Below, I will explain the solution for each expression step by step.
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1) \( a - 2 \) when \( a = 10 \)
\[
a - 2 = 10 - 2 = 8
\]
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2) \( 3b \) when \( b = 4 \)
\[
3b = 3 \times 4 = 12
\]
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3) \( c + c \) when \( c = 5 \)
\[
c + c = 5 + 5 = 10
\]
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4) \( \frac{d}{2} \) when \( d = 8 \)
\[
\frac{d}{2} = \frac{8}{2} = 4
\]
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5) \( e - 8 \) when \( e = 5 \)
\[
e - 8 = 5 - 8 = -3
\]
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6) \( 5f \) when \( f = 7 \)
\[
5f = 5 \times 7 = 35
\]
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7) \( 9 - g \) when \( g = 8 \)
\[
9 - g = 9 - 8 = 1
\]
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8) \( 2h + 4 \) when \( h = 6 \)
\[
2h + 4 = 2 \times 6 + 4 = 12 + 4 = 16
\]
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9) \( 3i - 7 \) when \( i = 10 \)
\[
3i - 7 = 3 \times 10 - 7 = 30 - 7 = 23
\]
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10) \( 2j - 1 \) when \( j = 6 \)
\[
2j - 1 = 2 \times 6 - 1 = 12 - 1 = 11
\]
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11) \( 2(j - 1) \) when \( j = 6 \)
\[
2(j - 1) = 2(6 - 1) = 2 \times 5 = 10
\]
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12) \( 3k + 4 \) when \( k = 3 \)
\[
3k + 4 = 3 \times 3 + 4 = 9 + 4 = 13
\]
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13) \( 3(k + 4) \) when \( k = 3 \)
\[
3(k + 4) = 3(3 + 4) = 3 \times 7 = 21
\]
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14) \( l + 5 + l + 2 \) when \( l = 6 \)
\[
l + 5 + l + 2 = 6 + 5 + 6 + 2 = 19
\]
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15) \( \frac{10}{m} \) when \( m = 2 \)
\[
\frac{10}{m} = \frac{10}{2} = 5
\]
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16) \( 16 - 2n \) when \( n = 8 \)
\[
16 - 2n = 16 - 2 \times 8 = 16 - 16 = 0
\]
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17) \( \frac{o}{4} \) when \( o = 20 \)
\[
\frac{o}{4} = \frac{20}{4} = 5
\]
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18) \( 6p + 8 \) when \( p = 12 \)
\[
6p + 8 = 6 \times 12 + 8 = 72 + 8 = 80
\]
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19) \( 6(p + 8) \) when \( p = 12 \)
\[
6(p + 8) = 6(12 + 8) = 6 \times 20 = 120
\]
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20) \( \frac{1}{2}q - 7 \) when \( q = 16 \)
\[
\frac{1}{2}q - 7 = \frac{1}{2} \times 16 - 7 = 8 - 7 = 1
\]
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21) \( \frac{1}{2}(q - 7) \) when \( q = 16 \)
\[
\frac{1}{2}(q - 7) = \frac{1}{2}(16 - 7) = \frac{1}{2} \times 9 = 4.5
\]
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22) \( 50 - 3r \) when \( r = 10 \)
\[
50 - 3r = 50 - 3 \times 10 = 50 - 30 = 20
\]
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23) \( 2s + 3s \) when \( s = 4 \)
\[
2s + 3s = 5s = 5 \times 4 = 20
\]
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24) \( 4t + 3 + 2t \) when \( t = 3 \)
\[
4t + 3 + 2t = 6t + 3 = 6 \times 3 + 3 = 18 + 3 = 21
\]
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25) \( \frac{1}{4}u - 6 \) when \( u = 12 \)
\[
\frac{1}{4}u - 6 = \frac{1}{4} \times 12 - 6 = 3 - 6 = -3
\]
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Final Answers:
\[
\boxed{8, 12, 10, 4, -3, 35, 1, 16, 23, 11, 10, 13, 21, 19, 5, 0, 5, 80, 120, 1, 4.5, 20, 20, 21, -3}
\]
Parent Tip: Review the logic above to help your child master the concept of free high school algebra worksheet.
