Here are the solutions for each problem on the worksheet.
1.
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Area: $7 \text{ cm} \times 8 \text{ cm} = 56 \text{ sq cm}$
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Perimeter: $(7 + 8) \times 2 = 30 \text{ cm}$
2.
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Area: $9 \text{ in} \times 12 \text{ in} = 108 \text{ sq in}$
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Perimeter: $(9 + 12) \times 2 = 42 \text{ in}$
3.
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Area: $14 \text{ ft} \times 5 \text{ ft} = 70 \text{ sq ft}$
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Perimeter: $(14 + 5) \times 2 = 38 \text{ ft}$
4. (Square)
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Area: $9 \text{ yd} \times 9 \text{ yd} = 81 \text{ sq yd}$
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Perimeter: $9 \times 4 = 36 \text{ yd}$
5. (Square)
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Area: $5 \text{ in} \times 5 \text{ in} = 25 \text{ sq in}$
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Perimeter: $5 \times 4 = 20 \text{ in}$
6.
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Area: $10 \text{ cm} \times 3 \text{ cm} = 30 \text{ sq cm}$
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Perimeter: $(10 + 3) \times 2 = 26 \text{ cm}$
7. (Square)
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Area: $11 \text{ in} \times 11 \text{ in} = 121 \text{ sq in}$
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Perimeter: $11 \times 4 = 44 \text{ in}$
8.
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Area: $15 \text{ ft} \times 5 \text{ ft} = 75 \text{ sq ft}$
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Perimeter: $(15 + 5) \times 2 = 40 \text{ ft}$
9.
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Area: $11 \text{ cm} \times 10 \text{ cm} = 110 \text{ sq cm}$
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Perimeter: $(11 + 10) \times 2 = 42 \text{ cm}$
10. (Square)
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Area: $4 \text{ ft} \times 4 \text{ ft} = 16 \text{ sq ft}$
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Perimeter: $4 \times 4 = 16 \text{ ft}$
11.
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Area: $5 \text{ cm} \times 2 \text{ cm} = 10 \text{ sq cm}$
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Perimeter: $(5 + 2) \times 2 = 14 \text{ cm}$
12.
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Area: $13 \text{ in} \times 6 \text{ in} = 78 \text{ sq in}$
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Perimeter: $(13 + 6) \times 2 = 38 \text{ in}$
Final Answer:
1. Area: 56 sq cm, Perimeter: 30 cm
2. Area: 108 sq in, Perimeter: 42 in
3. Area: 70 sq ft, Perimeter: 38 ft
4. Area: 81 sq yd, Perimeter: 36 yd
5. Area: 25 sq in, Perimeter: 20 in
6. Area: 30 sq cm, Perimeter: 26 cm
7. Area: 121 sq in, Perimeter: 44 in
8. Area: 75 sq ft, Perimeter: 40 ft
9. Area: 110 sq cm, Perimeter: 42 cm
10. Area: 16 sq ft, Perimeter: 16 ft
11. Area: 10 sq cm, Perimeter: 14 cm
12. Area: 78 sq in, Perimeter: 38 in
Parent Tip: Review the logic above to help your child master the concept of free perimeter worksheet.
