Printable Logic Puzzle Grid Blank - Printable Crossword Puzzles - Free Printable

Let’s solve this step by step. We have 5 people: Cher, Johnny, Jane, Sue, Marcie.
They each did a different number of tasks — and the total is 30 (from clue #1).
No one did the same amount (clue #3), and everyone did more than 2 tasks (clue #4).
So possible task numbers are from 3 to ? — but since there are 5 people and total is 30, let’s think about what 5 different numbers >2 add up to 30.

Possible sets of 5 different integers >2 that sum to 30:

Try: 3, 4, 5, 6, 12 → 3+4+5+6+12 = 30 ✔
That matches the left column in the grid! So those are the task counts: 3, 4, 5, 6, 12.

Now assign them to people using clues.

Clue #5: Cher completed one more task than the resource who dressed in Reds.
Clue #7: Cher completed one less task than the resource who worked on Initiating process.

So:
Cher = Red-person + 1
Cher = Initiating-person - 1
→ So Red-person + 1 = Initiating-person - 1 → Initiating-person = Red-person + 2

Also, clue #10: Five tasks were completed by Jane → Jane = 5

Clue #9: Johnny worked on Planning process.

Clue #11 & #12: The person in Yellow suits completed all Executing tasks → so Yellow = Executing

Clue #15: Sue dressed in Orange.

Clue #14: Worker in Green completed one-third as many as Sue → Green = Sue / 3 → So Sue must be divisible by 3. Possible Sue values: 3, 6, 12 (since 5 is taken by Jane, and 4 not divisible by 3). But Sue can’t be 3 because then Green=1, which is <2 — invalid. So Sue = 6 or 12.

If Sue = 6 → Green = 2 → invalid (must be >2)
If Sue = 12 → Green = 4 → valid ✔
So Sue = 12, Green = 4

We already have Jane = 5.

Remaining task numbers: 3, 6 (since 4,5,12 taken)

People left: Cher, Johnny, Marcie

Clue #5: Cher = Red + 1
Clue #7: Cher = Initiating - 1

Also, clue #6: Than the resource who dressed in Reds → so someone wore Red.

Clue #16: One resource dressed in Blue.

Colors: Red, Blue, Green, Yellow, Orange
We know:
Sue = Orange (clue #15)
Green = 4 (we just found)
Yellow = Executing (clue #11-12)
So remaining colors: Red, Blue for others.

Back to Cher.

Cher = Red + 1
Cher must be either 3 or 6 (only ones left besides 4,5,12 — but 4 is Green, 5 is Jane, 12 is Sue)

If Cher = 3 → Red = 2 → invalid
If Cher = 6 → Red = 5 → but 5 is Jane → so Jane wore Red? Let’s check.

Jane = 5 → if she wore Red, then Cher = 5 + 1 = 6 → okay.

Then Cher = 6.

Then from clue #7: Cher = Initiating - 1 → 6 = Initiating - 1 → Initiating = 7 → but 7 isn’t in our list! Our task numbers are only 3,4,5,6,12. Problem.

Wait — maybe I made a mistake.

Task numbers assigned so far:

Jane = 5
Sue = 12
Green = 4 → so whoever has 4 tasks wore Green.

Left: 3, 6 for Cher, Johnny, Marcie — wait, three people, two numbers? No — we have five people: Cher, Johnny, Jane, Sue, Marcie.

Assigned:

Jane = 5
Sue = 12
Green-wearer = 4 → that’s one person.

So task numbers used: 4,5,12

Left: 3,6 → for two people? But we have three people left: Cher, Johnny, Marcie. That doesn’t work.

I think I messed up.

Total task numbers: 3,4,5,6,12 — five numbers for five people.

We have:

Jane = 5 (clue #10)

Sue = ? — we thought 12, but let’s recheck clue #14: “Completed one-third as many as Sue” → Green = Sue/3

Sue must be multiple of 3: possible 3,6,12

But Sue can’t be 3 → Green=1 invalid
Sue=6 → Green=2 invalid
Sue=12 → Green=4 valid → so Sue=12, Green=4

So now:

Jane = 5
Sue = 12
Green-wearer = 4 → that’s one person, say X

Left task numbers: 3,6

People left: Cher, Johnny, Marcie — three people, but only two numbers? Contradiction.

Unless... Green-wearer is one of Cher, Johnny, Marcie — yes, that’s fine.

So people: Cher, Johnny, Jane, Sue, Marcie

Tasks: assign 3,4,5,6,12

Jane = 5
Sue = 12
One person = 4 (wore Green)
Left: 3,6 for two people — but we have three people left? No: Jane and Sue are two, plus Green-wearer is third, so two left for 3 and 6.

People: let's list:

- Jane: 5
- Sue: 12
- Person A: 4 (Green)
- Person B: ?
- Person C: ?

But we have only five people. So after Jane, Sue, and Green-wearer, two left for 3 and 6.

The two left are from Cher, Johnny, Marcie minus the Green-wearer.

So among Cher, Johnny, Marcie, one has 4 (Green), and the other two have 3 and 6.

Now clue #5: Cher = Red + 1

Clue #7: Cher = Initiating - 1

So Cher cannot be 3, because then Red=2 invalid.

Cher cannot be 4, because 4 is Green, and Red is different color.

Cher could be 6 → then Red = 5 → but 5 is Jane → so Jane wore Red.

Then Cher = 6

Then from clue #7: Cher = Initiating - 1 → 6 = Initiating - 1 → Initiating = 7 → not in list! Impossible.

Cher = 12? But 12 is Sue.

Cher = 5? But 5 is Jane.

This is a problem.

Perhaps Sue is not 12.

Let me read clue #14 again: "Completed one-third as many as Sue" — it says "the worker who always dressed in Green completed one-third as many as Sue"

So Green = Sue / 3

Sue must be divisible by 3, and Green >2, so Sue >=9, but our max is 12, so Sue=12, Green=4 is only possibility.

But then Cher can't be assigned.

Unless Cher is the one with 4 tasks? But 4 is Green, and Cher might not be Green.

Let's list all clues again.

From the poem:

1. Total tasks: 30

2. All completed by team

3. None same amount

4. Each >2 tasks → so min 3

5. Cher = Red + 1

6. Than the resource who dressed in Reds — so Red is a person

7. Cher = Initiating - 1

8. Than the resource who worked on Initiating

9. Johnny worked on Planning

10. Jane = 5

11. Resource in Yellow suits

12. Completed all Executing tasks → so Yellow = Executing

13. Worker in Green

14. Completed one-third as many as Sue → Green = Sue/3

15. Sue dressed in Orange

16. One resource dressed in Blue

17. Resource who completed Monitoring tasks

18. Completed the most tasks of all → so 12 is the most, and that person did Monitoring? Clue #17 and #18: "The resource who completed the Monitoring tasks completed the most tasks of all." So Monitoring = 12

Oh! I missed that.

Clue #17 and #18: "The resource who completed the Monitoring tasks completed the most tasks of all."

And most tasks is 12, so Monitoring = 12

But clue #15: Sue dressed in Orange, and if Sue = 12, then Sue did Monitoring.

Is that possible? Yes.

So Sue = 12, and Sue did Monitoring, and wore Orange.

Green = Sue/3 = 4, so someone with 4 tasks wore Green.

Jane = 5

Left task numbers: 3,6

People left: Cher, Johnny, Marcie

One of them has 4 (Green), but 4 is already assigned to Green-wearer, who is one of these three.

Task numbers to assign: 3,4,6 for Cher, Johnny, Marcie — since Jane=5, Sue=12.

Yes! I forgot that 4 is also to be assigned to one of them.

So tasks: Cher, Johnny, Marcie have 3,4,6 in some order.

Jane=5, Sue=12.

Now, Green = 4, so the person with 4 tasks wore Green.

Sue wore Orange (clue #15)

Yellow = Executing (clue #11-12)

Blue is worn by one person (clue #16)

Red is worn by one person.

Now clue #5: Cher = Red + 1

Clue #7: Cher = Initiating - 1

Cher has either 3,4, or 6.

If Cher = 3, then Red = 2 — invalid

If Cher = 4, then Red = 3, and Initiating = 5

But Initiating = 5, and Jane = 5, so Jane did Initiating? Possible.

If Cher = 6, then Red = 5, Initiating = 7 — 7 not in list, invalid.

So only possibility: Cher = 4, Red = 3, Initiating = 5

So Cher has 4 tasks, wore Green? Because Green = 4, and Cher = 4, so Cher wore Green.

But clue #5: Cher = Red + 1, so Red = 3, so someone with 3 tasks wore Red.

Initiating = 5, and Jane = 5, so Jane did Initiating.

Now, Cher = 4, wore Green (since Green=4)

Jane = 5, did Initiating, and wore Red? Because Red=3? No.

Red = 3, so the person with 3 tasks wore Red.

Cher = 4, so not Red.

Jane = 5, not 3.

Sue = 12, not 3.

So the person with 3 tasks wore Red.

Who has 3 tasks? Among Johnny and Marcie, since Cher=4, Jane=5, Sue=12, so Johnny and Marcie have 3 and 6.

Say, one has 3, one has 6.

The one with 3 wore Red.

Now, clue #9: Johnny worked on Planning.

Clue #11-12: Yellow = Executing

Clue #16: One wore Blue.

Colors left: for the people.

People:

- Cher: 4 tasks, wore Green (since Green=4)

- Jane: 5 tasks, did Initiating, and since Red=3, she didn't wear Red; she must wear another color.

Colors: Red, Blue, Green, Yellow, Orange

Assigned:

- Cher: Green

- Sue: Orange (clue #15)

- Person with 3 tasks: Red

- Yellow: Executing

- Blue: one person

Now, Jane did Initiating, has 5 tasks.

What color did Jane wear? Not Green (Cher), not Orange (Sue), not Red (the 3-task person), so either Blue or Yellow.

But Yellow = Executing, and Jane did Initiating, so not Yellow. So Jane wore Blue.

Then the person with 3 tasks wore Red.

Now, who has 3 tasks? Johnny or Marcie.

Johnny worked on Planning (clue #9)

Marcie is the other.

Now, clue #19-20: Another enthusiastic resource completed each and every Closing task.

Clue #20: Completed each and every Closing task — so one person did all Closing tasks.

Similarly, clue #12: completed all Executing tasks — so Yellow did all Executing.

Probably each process is done by one person, since it says "completed all" for Executing and Closing.

Assume that each process is handled by one person.

Processes: Initiating, Planning, Executing, Monitoring, Closing

We have:

- Initiating: Jane (since she has 5, and Initiating=5 from earlier)

- Monitoring: Sue (12 tasks, and clue #17-18: Monitoring = most =12)

- Executing: Yellow-wearer

- Closing: the "another enthusiastic" one, clue #19-20

- Planning: Johnny (clue #9)

Now, who is Yellow? Executing.

Yellow-wearer has some task count.

Task counts left for processes: we have assignments.

People and their tasks and processes:

- Jane: 5 tasks, Initiating, wore Blue (as we deduced)

- Sue: 12 tasks, Monitoring, wore Orange

- Cher: 4 tasks, wore Green, what process? Not yet known.

- Johnny: ? tasks, Planning

- Marcie: ? tasks, ?

Tasks left for Johnny and Marcie: 3 and 6.

The person with 3 tasks wore Red.

So either Johnny or Marcie has 3 tasks and wore Red.

The other has 6 tasks.

Now, processes left: Executing, Closing

And Cher has no process yet.

Processes assigned:

- Initiating: Jane

- Planning: Johnny

- Monitoring: Sue

Left: Executing, Closing for Cher and Marcie? Or Johnny is Planning, so not available.

People: Cher, Johnny, Marcie need processes.

Johnny has Planning.

So Cher and Marcie have Executing and Closing.

But Executing is done by Yellow-wearer.

Closing is done by the "enthusiastic" one, clue #19-20.

Now, who wore Yellow?

Colors left: for Johnny and Marcie, and Cher is Green, Jane Blue, Sue Orange, so Johnny and Marcie have Red and Yellow? But Red is worn by the 3-task person.

So if Johnny has 3 tasks, he wore Red, and Marcie has 6, wore Yellow? Or vice versa.

But Yellow = Executing.

So if Marcie wore Yellow, she did Executing.

Then Cher must have done Closing? But clue #19-20 says "another enthusiastic resource" completed Closing, implying it's not the same as others.

List:

Suppose Johnny has 3 tasks, wore Red, did Planning.

Then Marcie has 6 tasks, wore Yellow, did Executing.

Then Cher has 4 tasks, wore Green, must have done Closing.

But clue #19-20: "Another enthusiastic, smiling resource completed each and every Closing task." — "another" might imply besides the one mentioned before, but in context, it might be fine.

Check if all clues are satisfied.

Clue #6: "Than the resource who dressed in Reds" — we have Johnny wore Red, has 3 tasks.

Cher = 4 = 3 + 1, good.

Clue #8: "Than the resource who worked on Initiating" — Jane did Initiating, has 5, Cher=4=5-1, good.

Clue #10: Jane=5, good.

Clue #11-12: Yellow suits completed Executing — if Marcie wore Yellow and did Executing, good.

Clue #13-14: Worker in Green completed one-third as many as Sue — Cher wore Green, has 4, Sue has 12, 4=12/3, good.

Clue #15: Sue in Orange, good.

Clue #16: One in Blue — Jane wore Blue, good.

Clue #17-18: Monitoring tasks completed by the one with most tasks — Sue has 12, did Monitoring, good.

Clue #19-20: Another resource completed Closing — Cher did Closing, and she is "another", probably ok.

Now, what about the colors and processes for the table.

We need to fill the grid.

First, resources: Cher, Johnny, Jane, Sue, Marcie

Tasks: Cher=4, Johnny=3, Jane=5, Sue=12, Marcie=6

Processes:
- Initiating: Jane
- Planning: Johnny
- Executing: Marcie (since Yellow)
- Monitoring: Sue
- Closing: Cher

Colors:
- Cher: Green
- Johnny: Red (since 3 tasks)
- Jane: Blue
- Sue: Orange
- Marcie: Yellow

Now, verify clue #20: "Completed each and every Closing task" — Cher did Closing, and she has 4 tasks, which should be all Closing tasks? But the process might have multiple tasks, but in this case, since each person is assigned to one process, and they did all tasks for that process, it makes sense.

Similarly, Marcie did all Executing tasks, etc.

Now, the number of tasks per process: since each person did all tasks for their process, the task count for the process is the same as the person's task count.

So:

- Initiating: Jane, 5 tasks

- Planning: Johnny, 3 tasks

- Executing: Marcie, 6 tasks

- Monitoring: Sue, 12 tasks

- Closing: Cher, 4 tasks

Total: 5+3+6+12+4=30, good.

Now, for the answer table: Name, Color, Process, # Tasks

Cher: Green, Closing, 4

Johnny: Red, Planning, 3

Jane: Blue, Initiating, 5

Sue: Orange, Monitoring, 12

Marcie: Yellow, Executing, 6

Now, to confirm, is there any clue against this?

Clue #19: "Another enthusiastic, smiling resource" — Cher is closing, and she might be enthusiastic, but it says "another", perhaps referring to besides Sue or someone, but probably acceptable.

All other clues seem satisfied.

In the initial grid, the # tasks are listed as 3,4,5,6,12, which match.

So final assignment:

- Cher: Color=Green, Process=Closing, #Tasks=4

- Johnny: Color=Red, Process=Planning, #Tasks=3

- Jane: Color=Blue, Process=Initiating, #Tasks=5

- Sue: Color=Orange, Process=Monitoring, #Tasks=12

- Marcie: Color=Yellow, Process=Executing, #Tasks=6

Now, for the Final Answer, we need to fill the table as per the question.

The user has a table to fill: Name, Color, Process, # Tasks

So:

Cher: Green, Closing, 4

Johnny: Red, Planning, 3

Jane: Blue, Initiating, 5

Sue: Orange, Monitoring, 12

Marcie: Yellow, Executing, 6

I think that's it.

Final Answer:

Cher: Green, Closing, 4
Johnny: Red, Planning, 3
Jane: Blue, Initiating, 5
Sue: Orange, Monitoring, 12
Marcie: Yellow, Executing, 6