Solve the algebra maze by finding the correct path from Start to Finish using solutions to equations.

To find the correct path from Start to Finish, we need to solve each equation in the boxes and check if the value of $X$ matches the number written on the yellow arrow leading to the next box. If they match, that is the correct step.

Let's trace the path step-by-step:

Step 1: Start at the top-left box.
* Equation: $X + 7 = 15$
* Solve for $X$: Subtract 7 from 15.
$$15 - 7 = 8$$
* So, $X = 8$.
* Look at the arrows coming out of this box:
* Right arrow says $X = 17$ (Incorrect)
* Down arrow says $X = 11$ (Incorrect)
* Diagonal down-right arrow says $X = 8$ (Correct)
* Move diagonally down-right to the next box.

Step 2: Second box ($X + 6 = 13$)
* Equation: $X + 6 = 13$
* Solve for $X$: Subtract 6 from 13.
$$13 - 6 = 7$$
* So, $X = 7$.
* Look at the arrows coming out of this box:
* Up arrow says $X = 2$ (Incorrect)
* Right arrow says $X = 4$ (Incorrect)
* Down arrow says $X = 5$ (Incorrect)
* Diagonal down-left arrow says $X = 4$ (Incorrect)
* Diagonal down-right arrow says $X = 8$ (Incorrect)
* Wait, let me re-check the connections from the previous step.

Let's re-evaluate Step 1 carefully.
Box: $X + 7 = 15 \rightarrow X = 8$.
Arrows leaving this box:
- Right to "3 + X = 4": Label is $X=17$. No.
- Down to "5X = 20": Label is $X=11$. No.
- Diagonal to "X + 6 = 13": Label is $X=8$. Yes.

Okay, so we are at the box "X + 6 = 13".
We calculated $X = 7$.
Arrows leaving "X + 6 = 13":
- Up to "3 + X = 4": Label $X=2$. No.
- Right to "6 + X = 15": Label $X=4$. No.
- Down to "X - 10 = 5": Label $X=5$. No.
- Diagonal down-left to "X + 3 = 12": Label $X=4$. No.
- Diagonal down-right to "8X = 24": Label $X=8$. No.

Something is wrong. Let me re-read the diagram connections.

Let's look at the box "3 + X = 4" (Top row, 2nd box).
$3 + X = 4 \rightarrow X = 1$.
Arrows leaving it:
- Left from previous? No, arrows go OUT.
- Right to "4X = 12": Label $X=5$. No.
- Down to "X + 6 = 13": Label $X=2$. No.
- Diagonal down-right to "6 + X = 15": Label $X=3$. No.

Let's