Final Answer:
A)
i. $ f(x) = 2x + 4 $:
$ x = -1 $ → $ f(-1) = 2 $
$ x = 0 $ → $ f(0) = 4 $
$ x = \frac{3}{2} $ → $ f\left(\frac{3}{2}\right) = 7 $
ii. $ f(x) = \frac{2x + 5}{x + 1} $:
$ x = -1 $ → undefined
$ x = 0 $ → $ f(0) = 5 $
$ x = \frac{3}{2} $ → $ f\left(\frac{3}{2}\right) = \frac{8}{5} $
iii. $ f(x) = 4.5x^2 - 7.2x + 1 $:
$ x = -1 $ → $ f(-1) = 12.7 $
$ x = 0 $ → $ f(0) = 1 $
$ x = \frac{3}{2} $ → $ f\left(\frac{3}{2}\right) = -0.65 $
B)
Function rule: $ f(x) = \sqrt{x + 1} $
Given values:
$ x = 0 $ → $ f(0) = 1 $
$ x = 2 $ → $ f(2) = \sqrt{3} $
$ x = 4 $ → $ f(4) = \sqrt{5} $
$ x = 5 $ → $ f(5) = \sqrt{6} $
$ x = 63 $ → $ f(63) = 8 $
i. $ f(8) = \sqrt{9} = 3 $
ii. Solve $ \sqrt{x + 1} = 11 $ → $ x + 1 = 121 $ → $ x = 120 $
C)
$ f(x) = |2x^2 - 6| $, $ 8x + \frac{3}{2} $, $ (x - 5)(2x - 3) $
$ f(-2) = |2(4) - 6| = |8 - 6| = 2 $
$ f(1) = |2(1) - 6| = |-4| = 4 $
$ f(3) = |2(9) - 6| = |18 - 6| = 12 $
Parent Tip: Review the logic above to help your child master the concept of function table worksheets.
