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Worksheet for identifying functional groups in organic molecules.

A worksheet titled "Identify functional groups" with a table listing 14 molecules, each with a chemical structure, and columns for "Functional Group" and "Name."

A worksheet titled "Identify functional groups" with a table listing 14 molecules, each with a chemical structure, and columns for "Functional Group" and "Name."

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Show Answer Key & Explanations Step-by-step solution for: identifying organic functional groups
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To solve the problem, we need to identify the functional groups present in each structural formula and classify them accordingly. Let's go through each structural formula step by step:

---

1. Structural Formula:


$$
\text{C} \equiv \text{C}
$$

- Functional Group: Alkynyl group (Triple bond)
- Type of Group: Alkynes
- Reason: The triple bond between two carbon atoms is characteristic of alkynes.

---

2. Structural Formula:


$$
\text{C} = \text{O}
$$

- Functional Group: Carbonyl group
- Type of Group: Aldehydes or Ketones
- Reason: The double bond between carbon and oxygen indicates a carbonyl group. Since there is no additional information about the rest of the molecule, it could be either an aldehyde or a ketone.

---

3. Structural Formula:


$$
\text{C} - \text{OH}
$$

- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.

---

4. Structural Formula:


$$
\text{C} = \text{N}
$$

- Functional Group: Imine group
- Type of Group: Imines
- Reason: The double bond between carbon and nitrogen is characteristic of imines.

---

5. Structural Formula:


$$
\text{C} \equiv \text{N}
$$

- Functional Group: Nitrile group
- Type of Group: Nitriles
- Reason: The triple bond between carbon and nitrogen is characteristic of nitriles.

---

6. Structural Formula:


$$
\text{C} - \text{Cl}
$$

- Functional Group: Halogen atom (Chlorine)
- Type of Group: Haloalkanes
- Reason: The single bond between carbon and chlorine indicates a haloalkane.

---

7. Structural Formula:


$$
\text{C} - \text{O} - \text{C}
$$

- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.

---

8. Structural Formula:


$$
\text{C} - \text{O} - \text{H}
$$

- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.

---

9. Structural Formula:


$$
\text{C} - \text{O} - \text{C}
$$

- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.

---

10. Structural Formula:


$$
\text{C} = \text{C} = \text{C}
$$

- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.

---

11. Structural Formula:


$$
\text{C} = \text{C} = \text{C}
$$

- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.

---

12. Structural Formula:


$$
\text{C} = \text{N} = \text{N}
$$

- Functional Group: Azide group
- Type of Group: Azides
- Reason: The presence of a nitrogen-nitrogen triple bond attached to a carbon atom is characteristic of azides.

---

13. Structural Formula:


$$
\text{C} = \text{S}
$$

- Functional Group: Thioaldehyde or Thioketone group
- Type of Group: Thiocarbonyls
- Reason: The double bond between carbon and sulfur is characteristic of thiocarbonyl compounds.

---

14. Structural Formula:


$$
\text{N} \equiv \text{N}
$$

- Functional Group: Nitrogen-Nitrogen triple bond
- Type of Group: Diazonium salts or Nitrogen-containing compounds
- Reason: The triple bond between two nitrogen atoms is characteristic of diazonium salts or other nitrogen-containing compounds.

---

Final Answer:



| Structural Formula | Type of Group |
|--------------------|---------------|
| 1. $\text{C} \equiv \text{C}$ | Alkynes |
| 2. $\text{C} = \text{O}$ | Aldehydes/Ketones |
| 3. $\text{C} - \text{OH}$ | Alcohols |
| 4. $\text{C} = \text{N}$ | Imines |
| 5. $\text{C} \equiv \text{N}$ | Nitriles |
| 6. $\text{C} - \text{Cl}$ | Haloalkanes |
| 7. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 8. $\text{C} - \text{O} - \text{H}$ | Alcohols |
| 9. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 10. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 11. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 12. $\text{C} = \text{N} = \text{N}$ | Azides |
| 13. $\text{C} = \text{S}$ | Thiocarbonyls |
| 14. $\text{N} \equiv \text{N}$ | Diazonium salts/Nitrogen-containing compounds |

$$
\boxed{
\begin{array}{|c|c|}
\hline
\text{Structural Formula} & \text{Type of Group} \\
\hline
1. \text{C} \equiv \text{C} & \text{Alkynes} \\
2. \text{C} = \text{O} & \text{Aldehydes/Ketones} \\
3. \text{C} - \text{OH} & \text{Alcohols} \\
4. \text{C} = \text{N} & \text{Imines} \\
5. \text{C} \equiv \text{N} & \text{Nitriles} \\
6. \text{C} - \text{Cl} & \text{Haloalkanes} \\
7. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
8. \text{C} - \text{O} - \text{H} & \text{Alcohols} \\
9. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
10. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
11. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
12. \text{C} = \text{N} = \text{N} & \text{Azides} \\
13. \text{C} = \text{S} & \text{Thiocarbonyls} \\
14. \text{N} \equiv \text{N} & \text{Diazonium salts/Nitrogen-containing compounds} \\
\hline
\end{array}
}
$$
Parent Tip: Review the logic above to help your child master the concept of functional groups worksheet.
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