Worksheet for identifying functional groups in organic molecules.
A worksheet titled "Identify functional groups" with a table listing 14 molecules, each with a chemical structure, and columns for "Functional Group" and "Name."
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Step-by-step solution for: identifying organic functional groups
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Show Answer Key & Explanations
Step-by-step solution for: identifying organic functional groups
To solve the problem, we need to identify the functional groups present in each structural formula and classify them accordingly. Let's go through each structural formula step by step:
---
$$
\text{C} \equiv \text{C}
$$
- Functional Group: Alkynyl group (Triple bond)
- Type of Group: Alkynes
- Reason: The triple bond between two carbon atoms is characteristic of alkynes.
---
$$
\text{C} = \text{O}
$$
- Functional Group: Carbonyl group
- Type of Group: Aldehydes or Ketones
- Reason: The double bond between carbon and oxygen indicates a carbonyl group. Since there is no additional information about the rest of the molecule, it could be either an aldehyde or a ketone.
---
$$
\text{C} - \text{OH}
$$
- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.
---
$$
\text{C} = \text{N}
$$
- Functional Group: Imine group
- Type of Group: Imines
- Reason: The double bond between carbon and nitrogen is characteristic of imines.
---
$$
\text{C} \equiv \text{N}
$$
- Functional Group: Nitrile group
- Type of Group: Nitriles
- Reason: The triple bond between carbon and nitrogen is characteristic of nitriles.
---
$$
\text{C} - \text{Cl}
$$
- Functional Group: Halogen atom (Chlorine)
- Type of Group: Haloalkanes
- Reason: The single bond between carbon and chlorine indicates a haloalkane.
---
$$
\text{C} - \text{O} - \text{C}
$$
- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.
---
$$
\text{C} - \text{O} - \text{H}
$$
- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.
---
$$
\text{C} - \text{O} - \text{C}
$$
- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.
---
$$
\text{C} = \text{C} = \text{C}
$$
- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.
---
$$
\text{C} = \text{C} = \text{C}
$$
- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.
---
$$
\text{C} = \text{N} = \text{N}
$$
- Functional Group: Azide group
- Type of Group: Azides
- Reason: The presence of a nitrogen-nitrogen triple bond attached to a carbon atom is characteristic of azides.
---
$$
\text{C} = \text{S}
$$
- Functional Group: Thioaldehyde or Thioketone group
- Type of Group: Thiocarbonyls
- Reason: The double bond between carbon and sulfur is characteristic of thiocarbonyl compounds.
---
$$
\text{N} \equiv \text{N}
$$
- Functional Group: Nitrogen-Nitrogen triple bond
- Type of Group: Diazonium salts or Nitrogen-containing compounds
- Reason: The triple bond between two nitrogen atoms is characteristic of diazonium salts or other nitrogen-containing compounds.
---
| Structural Formula | Type of Group |
|--------------------|---------------|
| 1. $\text{C} \equiv \text{C}$ | Alkynes |
| 2. $\text{C} = \text{O}$ | Aldehydes/Ketones |
| 3. $\text{C} - \text{OH}$ | Alcohols |
| 4. $\text{C} = \text{N}$ | Imines |
| 5. $\text{C} \equiv \text{N}$ | Nitriles |
| 6. $\text{C} - \text{Cl}$ | Haloalkanes |
| 7. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 8. $\text{C} - \text{O} - \text{H}$ | Alcohols |
| 9. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 10. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 11. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 12. $\text{C} = \text{N} = \text{N}$ | Azides |
| 13. $\text{C} = \text{S}$ | Thiocarbonyls |
| 14. $\text{N} \equiv \text{N}$ | Diazonium salts/Nitrogen-containing compounds |
$$
\boxed{
\begin{array}{|c|c|}
\hline
\text{Structural Formula} & \text{Type of Group} \\
\hline
1. \text{C} \equiv \text{C} & \text{Alkynes} \\
2. \text{C} = \text{O} & \text{Aldehydes/Ketones} \\
3. \text{C} - \text{OH} & \text{Alcohols} \\
4. \text{C} = \text{N} & \text{Imines} \\
5. \text{C} \equiv \text{N} & \text{Nitriles} \\
6. \text{C} - \text{Cl} & \text{Haloalkanes} \\
7. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
8. \text{C} - \text{O} - \text{H} & \text{Alcohols} \\
9. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
10. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
11. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
12. \text{C} = \text{N} = \text{N} & \text{Azides} \\
13. \text{C} = \text{S} & \text{Thiocarbonyls} \\
14. \text{N} \equiv \text{N} & \text{Diazonium salts/Nitrogen-containing compounds} \\
\hline
\end{array}
}
$$
---
1. Structural Formula:
$$
\text{C} \equiv \text{C}
$$
- Functional Group: Alkynyl group (Triple bond)
- Type of Group: Alkynes
- Reason: The triple bond between two carbon atoms is characteristic of alkynes.
---
2. Structural Formula:
$$
\text{C} = \text{O}
$$
- Functional Group: Carbonyl group
- Type of Group: Aldehydes or Ketones
- Reason: The double bond between carbon and oxygen indicates a carbonyl group. Since there is no additional information about the rest of the molecule, it could be either an aldehyde or a ketone.
---
3. Structural Formula:
$$
\text{C} - \text{OH}
$$
- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.
---
4. Structural Formula:
$$
\text{C} = \text{N}
$$
- Functional Group: Imine group
- Type of Group: Imines
- Reason: The double bond between carbon and nitrogen is characteristic of imines.
---
5. Structural Formula:
$$
\text{C} \equiv \text{N}
$$
- Functional Group: Nitrile group
- Type of Group: Nitriles
- Reason: The triple bond between carbon and nitrogen is characteristic of nitriles.
---
6. Structural Formula:
$$
\text{C} - \text{Cl}
$$
- Functional Group: Halogen atom (Chlorine)
- Type of Group: Haloalkanes
- Reason: The single bond between carbon and chlorine indicates a haloalkane.
---
7. Structural Formula:
$$
\text{C} - \text{O} - \text{C}
$$
- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.
---
8. Structural Formula:
$$
\text{C} - \text{O} - \text{H}
$$
- Functional Group: Hydroxyl group
- Type of Group: Alcohols
- Reason: The single bond between carbon and hydroxyl (-OH) is characteristic of alcohols.
---
9. Structural Formula:
$$
\text{C} - \text{O} - \text{C}
$$
- Functional Group: Ether group
- Type of Group: Ethers
- Reason: The oxygen atom bonded to two carbon atoms is characteristic of ethers.
---
10. Structural Formula:
$$
\text{C} = \text{C} = \text{C}
$$
- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.
---
11. Structural Formula:
$$
\text{C} = \text{C} = \text{C}
$$
- Functional Group: Alkenyl group (Double bonds)
- Type of Group: Alkenes
- Reason: The presence of double bonds between carbon atoms is characteristic of alkenes.
---
12. Structural Formula:
$$
\text{C} = \text{N} = \text{N}
$$
- Functional Group: Azide group
- Type of Group: Azides
- Reason: The presence of a nitrogen-nitrogen triple bond attached to a carbon atom is characteristic of azides.
---
13. Structural Formula:
$$
\text{C} = \text{S}
$$
- Functional Group: Thioaldehyde or Thioketone group
- Type of Group: Thiocarbonyls
- Reason: The double bond between carbon and sulfur is characteristic of thiocarbonyl compounds.
---
14. Structural Formula:
$$
\text{N} \equiv \text{N}
$$
- Functional Group: Nitrogen-Nitrogen triple bond
- Type of Group: Diazonium salts or Nitrogen-containing compounds
- Reason: The triple bond between two nitrogen atoms is characteristic of diazonium salts or other nitrogen-containing compounds.
---
Final Answer:
| Structural Formula | Type of Group |
|--------------------|---------------|
| 1. $\text{C} \equiv \text{C}$ | Alkynes |
| 2. $\text{C} = \text{O}$ | Aldehydes/Ketones |
| 3. $\text{C} - \text{OH}$ | Alcohols |
| 4. $\text{C} = \text{N}$ | Imines |
| 5. $\text{C} \equiv \text{N}$ | Nitriles |
| 6. $\text{C} - \text{Cl}$ | Haloalkanes |
| 7. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 8. $\text{C} - \text{O} - \text{H}$ | Alcohols |
| 9. $\text{C} - \text{O} - \text{C}$ | Ethers |
| 10. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 11. $\text{C} = \text{C} = \text{C}$ | Alkenes |
| 12. $\text{C} = \text{N} = \text{N}$ | Azides |
| 13. $\text{C} = \text{S}$ | Thiocarbonyls |
| 14. $\text{N} \equiv \text{N}$ | Diazonium salts/Nitrogen-containing compounds |
$$
\boxed{
\begin{array}{|c|c|}
\hline
\text{Structural Formula} & \text{Type of Group} \\
\hline
1. \text{C} \equiv \text{C} & \text{Alkynes} \\
2. \text{C} = \text{O} & \text{Aldehydes/Ketones} \\
3. \text{C} - \text{OH} & \text{Alcohols} \\
4. \text{C} = \text{N} & \text{Imines} \\
5. \text{C} \equiv \text{N} & \text{Nitriles} \\
6. \text{C} - \text{Cl} & \text{Haloalkanes} \\
7. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
8. \text{C} - \text{O} - \text{H} & \text{Alcohols} \\
9. \text{C} - \text{O} - \text{C} & \text{Ethers} \\
10. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
11. \text{C} = \text{C} = \text{C} & \text{Alkenes} \\
12. \text{C} = \text{N} = \text{N} & \text{Azides} \\
13. \text{C} = \text{S} & \text{Thiocarbonyls} \\
14. \text{N} \equiv \text{N} & \text{Diazonium salts/Nitrogen-containing compounds} \\
\hline
\end{array}
}
$$
Parent Tip: Review the logic above to help your child master the concept of functional groups worksheet.