Let's solve each problem using the
long division method to find the
Greatest Common Factor (GCF) of the given pairs of numbers.
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🔍 How to Find GCF Using Long Division Method:
1. Divide the larger number by the smaller number.
2. Then divide the divisor (smaller number) by the remainder.
3. Repeat this process until the remainder is 0.
4. The last non-zero remainder is the
GCF.
We'll go through each pair step-by-step.
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✔ Problem 1: 45, 55
- Step 1: 55 ÷ 45 = 1 R 10
- Step 2: 45 ÷ 10 = 4 R 5
- Step 3: 10 ÷ 5 = 2 R 0
→ GCF =
5
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✔ Problem 2: 30, 60
- 60 ÷ 30 = 2 R 0
→ GCF =
30
---
✔ Problem 3: 12, 40
- 40 ÷ 12 = 3 R 4
- 12 ÷ 4 = 3 R 0
→ GCF =
4
---
✔ Problem 4: 36, 75
- 75 ÷ 36 = 2 R 3
- 36 ÷ 3 = 12 R 0
→ GCF =
3
---
✔ Problem 5: 44, 58
- 58 ÷ 44 = 1 R 14
- 44 ÷ 14 = 3 R 2
- 14 ÷ 2 = 7 R 0
→ GCF =
2
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✔ Problem 6: 33, 39
- 39 ÷ 33 = 1 R 6
- 33 ÷ 6 = 5 R 3
- 6 ÷ 3 = 2 R 0
→ GCF =
3
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✔ Problem 7: 28, 44
- 44 ÷ 28 = 1 R 16
- 28 ÷ 16 = 1 R 12
- 16 ÷ 12 = 1 R 4
- 12 ÷ 4 = 3 R 0
→ GCF =
4
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✔ Problem 8: 30, 75
- 75 ÷ 30 = 2 R 15
- 30 ÷ 15 = 2 R 0
→ GCF =
15
---
✔ Problem 9: 25, 40
- 40 ÷ 25 = 1 R 15
- 25 ÷ 15 = 1 R 10
- 15 ÷ 10 = 1 R 5
- 10 ÷ 5 = 2 R 0
→ GCF =
5
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✔ Problem 10: 75, 90
- 90 ÷ 75 = 1 R 15
- 75 ÷ 15 = 5 R 0
→ GCF =
15
---
✔ Problem 11: 60, 75
- 75 ÷ 60 = 1 R 15
- 60 ÷ 15 = 4 R 0
→ GCF =
15
---
✔ Problem 12: 50, 60
- 60 ÷ 50 = 1 R 10
- 50 ÷ 10 = 5 R 0
→ GCF =
10
---
✔ Problem 13: 40, 80
- 80 ÷ 40 = 2 R 0
→ GCF =
40
---
✔ Problem 14: 18, 81
- 81 ÷ 18 = 4 R 9
- 18 ÷ 9 = 2 R 0
→ GCF =
9
---
✔ Problem 15: 60, 90
- 90 ÷ 60 = 1 R 30
- 60 ÷ 30 = 2 R 0
→ GCF =
30
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✔ Final Answers:
1. 45, 55 =
5
2. 30, 60 =
30
3. 12, 40 =
4
4. 36, 75 =
3
5. 44, 58 =
2
6. 33, 39 =
3
7. 28, 44 =
4
8. 30, 75 =
15
9. 25, 40 =
5
10. 75, 90 =
15
11. 60, 75 =
15
12. 50, 60 =
10
13. 40, 80 =
40
14. 18, 81 =
9
15. 60, 90 =
30
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✔ All solved using the
long division method as requested.
Let me know if you'd like a printable version or explanation for any specific problem!
Parent Tip: Review the logic above to help your child master the concept of gcf worksheet.