GED Math Practice Test 1 | PDF | Area | Interest - Free Printable

Let's solve each problem step by step:

---

Problem 1: Solve: (10 - 5) + 4 × 11

#### Solution:
1. First, simplify the expression inside the parentheses:
\[
10 - 5 = 5
\]
So the expression becomes:
\[
5 + 4 \times 11
\]

2. Next, apply the order of operations (PEMDAS/BODMAS): Perform multiplication before addition.
\[
4 \times 11 = 44
\]
So the expression now is:
\[
5 + 44
\]

3. Finally, perform the addition:
\[
5 + 44 = 49
\]

#### Answer:
\[
\boxed{B}
\]

---

Problem 2: The following set of data is given: 12, 14, 20, 18, 16, 14, 24, 16. Adding which pair of numbers would make the mean higher?

#### Solution:
1. First, calculate the current mean of the given data:
\[
\text{Sum of the data} = 12 + 14 + 20 + 18 + 16 + 14 + 24 + 16 = 134
\]
\[
\text{Number of data points} = 8
\]
\[
\text{Current mean} = \frac{134}{8} = 16.75
\]

2. To increase the mean, we need to add a pair of numbers whose average is greater than the current mean (16.75).

3. Check each option:
- Option A: 12 and 14
\[
\text{Mean of 12 and 14} = \frac{12 + 14}{2} = 13 \quad (\text{less than 16.75})
\]
- Option B: 12 and 16
\[
\text{Mean of 12 and 16} = \frac{12 + 16}{2} = 14 \quad (\text{less than 16.75})
\]
- Option C: 18 and 22
\[
\text{Mean of 18 and 22} = \frac{18 + 22}{2} = 20 \quad (\text{greater than 16.75})
\]
- Option D: 22 and 24
\[
\text{Mean of 22 and 24} = \frac{22 + 24}{2} = 23 \quad (\text{greater than 16.75})
\]

4. Both options C and D will increase the mean, but the question asks for the pair that makes the mean higher. Option D has a higher mean (23) compared to option C (20).

#### Answer:
\[
\boxed{D}
\]

---

Problem 3: Abigail would like to purchase a new Kindle for $160. She has a coupon at Best Buy for 20% off. How much will the Kindle cost if she uses the coupon?

#### Solution:
1. Calculate the discount amount:
\[
\text{Discount} = 20\% \text{ of } 160 = 0.20 \times 160 = 32
\]

2. Subtract the discount from the original price:
\[
\text{Final price} = 160 - 32 = 128
\]

#### Answer:
\[
\boxed{D}
\]

---

Problem 4: On the last day camp, Krystal wants to treat her cabin to popsicles. She has 12 girls in her cabin. At the camp store Krystal can buy a pack of 4 popsicles for $3.50. What will it cost her to buy popsicles for her entire cabin?

#### Solution:
1. Determine how many packs of popsicles Krystal needs:
\[
\text{Total popsicles needed} = 12
\]
\[
\text{Popsicles per pack} = 4
\]
\[
\text{Number of packs} = \frac{12}{4} = 3
\]

2. Calculate the total cost:
\[
\text{Cost per pack} = 3.50
\]
\[
\text{Total cost} = 3 \times 3.50 = 10.50
\]

#### Answer:
\[
\boxed{A}
\]

---

Problem 5: Solve the inequality: \( y - 9 > 18 \)

#### Solution:
1. Add 9 to both sides of the inequality:
\[
y - 9 + 9 > 18 + 9
\]
\[
y > 27
\]

#### Answer:
\[
\boxed{B}
\]

---

Problem 6: Peter went to the hardware store with $10. He needs to purchase some light plate and outlet covers. Here are the prices at the store: Light plate covers: $0.75, Outlet plate covers: $1.25. He has enough money to purchase which set of items below?

#### Solution:
1. Calculate the cost for each option:
- Option A: 7 light plate covers and 4 outlet plate covers
\[
\text{Cost of 7 light plate covers} = 7 \times 0.75 = 5.25
\]
\[
\text{Cost of 4 outlet plate covers} = 4 \times 1.25 = 5.00
\]
\[
\text{Total cost} = 5.25 + 5.00 = 10.25 \quad (\text{exceeds $10})
\]

- Option B: 6 light plate covers and 6 outlet plate covers
\[
\text{Cost of 6 light plate covers} = 6 \times 0.75 = 4.50
\]
\[
\text{Cost of 6 outlet plate covers} = 6 \times 1.25 = 7.50
\]
\[
\text{Total cost} = 4.50 + 7.50 = 12.00 \quad (\text{exceeds $10})
\]

- Option C: 6 light plate covers and 4 outlet plate covers
\[
\text{Cost of 6 light plate covers} = 6 \times 0.75 = 4.50
\]
\[
\text{Cost of 4 outlet plate covers} = 4 \times 1.25 = 5.00
\]
\[
\text{Total cost} = 4.50 + 5.00 = 9.50 \quad (\text{within $10})
\]

- Option D: 5 light plate covers and 6 outlet plate covers
\[
\text{Cost of 5 light plate covers} = 5 \times 0.75 = 3.75
\]
\[
\text{Cost of 6 outlet plate covers} = 6 \times 1.25 = 7.50
\]
\[
\text{Total cost} = 3.75 + 7.50 = 11.25 \quad (\text{exceeds $10})
\]

#### Answer:
\[
\boxed{C}
\]

---

Problem 7: What is the slope of the line?

#### Solution:
1. The slope of a line is given by the formula:
\[
\text{slope} = \frac{\Delta y}{\Delta x} = \frac{\text{rise}}{\text{run}}
\]

2. From the graph:
- Choose two points on the line, such as \((-2, 0)\) and \((2, 8)\).
- Calculate the rise (\(\Delta y\)):
\[
\Delta y = 8 - 0 = 8
\]
- Calculate the run (\(\Delta x\)):
\[
\Delta x = 2 - (-2) = 2 + 2 = 4
\]
- Compute the slope:
\[
\text{slope} = \frac{\Delta y}{\Delta x} = \frac{8}{4} = 2
\]

#### Answer:
\[
\boxed{A}
\]

---

Final Answers:

1. \(\boxed{B}\)
2. \(\boxed{D}\)
3. \(\boxed{D}\)
4. \(\boxed{A}\)
5. \(\boxed{B}\)
6. \(\boxed{C}\)
7. \(\boxed{A}\)