To solve the problem of finding the area of each parallelogram, we use the formula for the area of a parallelogram:
\[
\text{Area} = \text{base} \times \text{height}
\]
We will calculate the area for each parallelogram step by step.
---
1. First Parallelogram
-
Base: 6 ft
-
Height: 7 ft
\[
\text{Area} = 6 \, \text{ft} \times 7 \, \text{ft} = 42 \, \text{ft}^2
\]
---
2. Second Parallelogram
-
Base: 11 mm
-
Height: 5 mm
\[
\text{Area} = 11 \, \text{mm} \times 5 \, \text{mm} = 55 \, \text{mm}^2
\]
---
3. Third Parallelogram
-
Base: 12 in
-
Height: 9 in
\[
\text{Area} = 12 \, \text{in} \times 9 \, \text{in} = 108 \, \text{in}^2
\]
---
4. Fourth Parallelogram
-
Base: 26 cm
-
Height: 8 cm
\[
\text{Area} = 26 \, \text{cm} \times 8 \, \text{cm} = 208 \, \text{cm}^2
\]
---
5. Fifth Parallelogram
-
Base: 3 m
-
Height: 1.9 m
\[
\text{Area} = 3 \, \text{m} \times 1.9 \, \text{m} = 5.7 \, \text{m}^2
\]
---
6. Sixth Parallelogram
-
Base: \(1 \frac{3}{4}\) mi (which is \(1.75\) mi)
-
Height: \(2 \frac{1}{2}\) mi (which is \(2.5\) mi)
\[
\text{Area} = 1.75 \, \text{mi} \times 2.5 \, \text{mi} = 4.375 \, \text{mi}^2
\]
---
7. Seventh Parallelogram
-
Base: \(2 \frac{1}{2}\) yd (which is \(2.5\) yd)
-
Height: \(1 \frac{2}{3}\) yd (which is \(1.6667\) yd)
\[
\text{Area} = 2.5 \, \text{yd} \times 1.6667 \, \text{yd} \approx 4.1667 \, \text{yd}^2
\]
---
8. Eighth Parallelogram
-
Base: 2.3 km
-
Height: 1.8 km
\[
\text{Area} = 2.3 \, \text{km} \times 1.8 \, \text{km} = 4.14 \, \text{km}^2
\]
---
Final Answers
\[
\boxed{
\begin{aligned}
&42 \, \text{ft}^2, \, 55 \, \text{mm}^2, \, 108 \, \text{in}^2, \, 208 \, \text{cm}^2, \\
&5.7 \, \text{m}^2, \, 4.375 \, \text{mi}^2, \, 4.1667 \, \text{yd}^2, \, 4.14 \, \text{km}^2
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of geometry parallelogram worksheet.
