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Quadratic area puzzle showing algebraic expressions for areas and dimensions of rectangles.

Quadratic area puzzle with three pink rectangles labeled with algebraic expressions and dimensions.

Quadratic area puzzle with three pink rectangles labeled with algebraic expressions and dimensions.

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Show Answer Key & Explanations Step-by-step solution for: 25 Fun Geometry Puzzles | Math = Love

Problem Analysis:


The image shows a composite shape divided into four regions, with the areas of three regions given as quadratic expressions. The goal is to determine the missing dimension (marked as "?") of the rightmost region and verify the consistency of the dimensions and areas.

#### Given:
1. The top-left region has an area of \( x^2 - 4 \).
2. The bottom-left region has an area of \( 4x^2 + 8x - 5 \).
3. The right region has an area of \( 6x^2 + 3x - 3 \).
4. The total width of the composite shape is \( x + 2 \).
5. The total height of the composite shape is \( 2x - 1 \).

We need to:
- Determine the missing dimension "?" of the right region.
- Verify that the dimensions and areas are consistent.

---

Step 1: Analyze the Left Side


The left side of the composite shape is divided into two regions:
- Top-left region: Area = \( x^2 - 4 \)
- Bottom-left region: Area = \( 4x^2 + 8x - 5 \)

The total width of the left side is given as \( 2x - 1 \). Let the heights of the top-left and bottom-left regions be \( h_1 \) and \( h_2 \), respectively. Then:
\[
h_1 + h_2 = 2x - 1
\]

#### Width of the Left Side:
The width of the left side is the same for both regions. Let this width be \( w_L \). Then:
\[
w_L \cdot h_1 = x^2 - 4 \quad \text{(Area of top-left region)}
\]
\[
w_L \cdot h_2 = 4x^2 + 8x - 5 \quad \text{(Area of bottom-left region)}
\]

From the total width of the composite shape, we know:
\[
w_L + w_R = x + 2
\]
where \( w_R \) is the width of the right region.

---

Step 2: Analyze the Right Side


The right side of the composite shape has one region with an area of \( 6x^2 + 3x - 3 \). Let the height of this region be \( h_R \). Then:
\[
w_R \cdot h_R = 6x^2 + 3x - 3
\]

The height of the right region must be the same as the total height of the composite shape, which is \( 2x - 1 \). Therefore:
\[
h_R = 2x - 1
\]

Substitute \( h_R \) into the area equation:
\[
w_R \cdot (2x - 1) = 6x^2 + 3x - 3
\]

Solve for \( w_R \):
\[
w_R = \frac{6x^2 + 3x - 3}{2x - 1}
\]

Perform polynomial division to simplify:
\[
6x^2 + 3x - 3 \div (2x - 1)
\]

1. Divide the leading term \( 6x^2 \) by \( 2x \) to get \( 3x \).
2. Multiply \( 3x \) by \( 2x - 1 \) to get \( 6x^2 - 3x \).
3. Subtract \( 6x^2 - 3x \) from \( 6x^2 + 3x - 3 \) to get \( 6x - 3 \).
4. Divide the leading term \( 6x \) by \( 2x \) to get \( 3 \).
5. Multiply \( 3 \) by \( 2x - 1 \) to get \( 6x - 3 \).
6. Subtract \( 6x - 3 \) from \( 6x - 3 \) to get \( 0 \).

Thus:
\[
w_R = 3x + 3
\]

---

Step 3: Verify the Total Width


The total width of the composite shape is given as \( x + 2 \). The width of the left side is \( 2x - 1 \), and the width of the right side is \( w_R = 3x + 3 \). Therefore:
\[
w_L + w_R = (2x - 1) + (3x + 3) = 5x + 2
\]

However, we know the total width is \( x + 2 \). This suggests a potential error in the problem setup or interpretation. Let us re-evaluate the dimensions and areas to ensure consistency.

---

Step 4: Re-evaluate the Dimensions


Given the areas and the total height \( 2x - 1 \), we can recheck the consistency:
- The height of the right region is \( 2x - 1 \).
- The width of the right region is \( 3x + 3 \).

The total width of the composite shape is:
\[
w_L + w_R = (2x - 1) + (3x + 3) = 5x + 2
\]

This does not match the given total width \( x + 2 \). Therefore, there might be an inconsistency in the problem statement. However, based on the given areas and the derived width of the right region, the missing dimension is:

\[
\boxed{3x + 3}
\]
Parent Tip: Review the logic above to help your child master the concept of geometry puzzles worksheet.
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