Geometry worksheet focusing on proving triangle congruence using various theorems.

1. ∠CBA ≅ ∠DCB (Given)
AB ≅ BC (Given)
CB ≅ CB (Reflexive Property)
Therefore, △CBA ≅ △DCB by SAS.

2. ∠DGF ≅ ∠EGF (Given, since DGFE is a rectangle, diagonals bisect each other and create congruent angles at intersection)
GF ≅ GF (Reflexive Property)
DF ≅ EF (Diagonals of a rectangle are congruent and bisect each other, so halves are congruent)
Therefore, △DGF ≅ △EGF by SAS.

3. MW ≅ HP (Given)
MZ ≅ PO (Given)
∠MZW ≅ ∠HOP (Vertical angles are congruent)
Therefore, △MWZ ≅ △HPO by SAS.

4. ∠KJA ≅ ∠BKS (Given)
JK ≅ BK (Given)
∠JKA ≅ ∠BKS (Vertical angles are congruent)
Therefore, △JKA ≅ △BKS by ASA.

5. ∠NKL ≅ ∠MKL (Given, since KNL is a rhombus, diagonal KL bisects angle NKM)
KL ≅ KL (Reflexive Property)
∠NLK ≅ ∠MLK (Given, or from rhombus property that diagonal bisects the angle)
Therefore, △KNL ≅ △KML by ASA.

6. JK ≅ SL (Given)
∠JKL ≅ ∠SLK (Given)
KL ≅ LK (Reflexive Property)
Therefore, △JKL ≅ △SLK by SAS.

7. KL ≅ KU (Given)
LS ≅ US (Given)
KS ≅ KS (Reflexive Property)
Therefore, △KLS ≅ △KUS by SSS.

8. FG ≅ HK (Given)
FI ≅ OK (Given)
GI ≅ OH (Since FG ≅ HK and FI ≅ OK, subtracting gives GI ≅ OH)
Therefore, △FGI ≅ △HKO by SSS.

9. LY ≅ KM (Given)
YX ≅ TW (Given)
LX ≅ MT (Since LY ≅ KM and YX ≅ TW, adding gives LX ≅ MT)
Therefore, △LYX ≅ △KMT by SSS.

10. YH ≅ ZH (Given)
HK is altitude of △YHZ, so ∠YHK ≅ ∠ZHK ≅ 90°
HK ≅ HK (Reflexive Property)
Therefore, △YHK ≅ △ZHK by SAS.